Forum: PHP  Oct 21st, 2004 |
| Replies: 7 Views: 4,241 Thank you very much Shorty. I have another question - this code works if a new event is added, where its type is selected from the list. How can I modify the code to enable me to edit an existing... |
| Forum: PHP Oct 20th, 2004 |
| Replies: 7 Views: 4,241 Yes it returns a result. Correct me if I am wrong, but if it doesn't it won't pass the if statement test and won't display a blank list. Been working on this all morning without much success.
ta
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| Forum: PHP Oct 20th, 2004 |
| Replies: 7 Views: 4,241 OK Roberdin. No it still does not make any difference.
tip |
| Forum: PHP Oct 20th, 2004 |
| Replies: 6 Views: 3,931 |
| Forum: PHP Oct 20th, 2004 |
| Replies: 7 Views: 4,241 Can someone show me where I go wrong. I am trying to populate a drop down list with field "type_desc" from the eventType table. Upon selection, the value that will be passed will be "type_code". All... |
| Forum: PHP Oct 18th, 2004 |
| Replies: 6 Views: 3,931 Thank you very much Roberdin and poA for your help. Now I can proceed
tip |
| Forum: PHP Oct 18th, 2004 |
| Replies: 6 Views: 3,931 Help with querystring error.
I am try to pass a query string to the same page but having problem
This is my code:
<HTML><BODY>
<div align=center>
<A href="?page=1">Page 1</A> -
<A... |
| Forum: PHP Oct 2nd, 2004 |
| Replies: 4 Views: 11,324 Include the update sql statement in the while loop. At the moment it only updates the last $kind in the table. |
| Forum: PHP Sep 28th, 2004 |
| Replies: 5 Views: 7,651 help! help! help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! anyone
tip |
| Forum: PHP Sep 28th, 2004 |
| Replies: 5 Views: 7,651 These parts of my code produce a droplist which is populated by event_code field from the events table. But how do I populate the rest of the data on the form which an event_code is selected from... |
| Forum: PHP Sep 28th, 2004 |
| Replies: 5 Views: 7,651 Thanks Gary. Any solutions for my queries. Query 1 is vital at this state.
ta
tip |
| Forum: PHP Sep 28th, 2004 |
| Replies: 5 Views: 7,651 I have solve the following error by declaring $option_block = ''; at the top.
Note that the above codes produce this error meassage but still seems to work:
Notice: Undefined variable:... |
| Forum: PHP Sep 28th, 2004 |
| Replies: 5 Views: 7,651 I am a second year IT student who is working on a project using PHP(frontend) and MySQL(backend). I am brand new to these softwares which are not being touch in class. I have 2 questions:
1. How... |
