or try $dir = "x:\\share1\\share2";

if (-d $dir);
{
print $dir," exists\n";
}
else
{
print $dir," not found\n";
}

heres some more hints:

(1) do not attempt to look for "return" statements. at all.

(2) only use the open/close brace counting method.

(3) you need to change your regex method. merely...

(1) do not just blindly replace = with == , there was only one place where this was an issue

if($openCount==$closeCount)

(2) SOME functions can have NO "return" statements (void) ... but ANY...

in case it's not clear...

your parsing method will count the opening brace in line 6, but not the closing brace in line 10

1) i noticed in your earlier code you were using = when you should have been using ==

2) you also had a do statement without a corresponding while condition. avoid do/while's for this and other...

for one thing, you cant put the begin/end of line operators (^ and $) inside parentheses. they must be immediately adjacent to the match operator like this

/^ ...regex... $/

for another...

it isn't "necessarily" always at the first spot.

but the regex should be correct.

post more code. use [code=c] tags, please

as for checking whether or not it is a function... each subroutine in C starts with one or more return type:

int, long, short, double, float, void, char, unsigned ...

then it has a single word...

easiest way is to

(1) do a dir (ls) listing of directory contents, parse each one for a .c extention. start with the first .c file...

(2) open the .c file for READ, to a file handle.

(3)...