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Search: Posts Made By: wonder_gal
Forum: ASP.NET May 9th, 2007
Replies: 8
Views: 10,829
Posted By wonder_gal
Ya of course I knew about populating one combo. My question here is how to populate the SECOND drop down list upon changes of selected value in the FIRST drop down list.
Forum: ASP.NET May 8th, 2007
Replies: 8
Views: 10,829
Posted By wonder_gal
Hi,

I have 2 drop down lists, in which the selection value of the 1st drop down list will determine the content of the second drop down list.
Is that I need to use javascript function to achieve...
Forum: VB.NET Apr 16th, 2007
Replies: 1
Views: 7,437
Posted By wonder_gal
Hi, can anyone help?
Your examples is very much appreciated.
Thanks.
Forum: VB.NET Apr 12th, 2007
Replies: 1
Views: 7,437
Posted By wonder_gal
Hi,


I need to write a windows application to automatically login to a website(with username and password being provided) to retrieve some data from the website. Can someone show me an example on...
Forum: VB.NET Apr 12th, 2007
Replies: 1
Views: 4,407
Posted By wonder_gal
Hi, I receive this error "No default member found for type 'Guid'." when I run my application.



db = New SqlConnection(GetConnectionString())
db.Open()

Dim strSQL As String
strSQL =...
Forum: VB.NET Apr 11th, 2007
Replies: 9
Solved: Unzip Function
Views: 8,592
Posted By wonder_gal
Icic, I got it. I just marked this post as SOLVED already.
Thanks to everyone here for sharing. :)
Forum: VB.NET Apr 11th, 2007
Replies: 9
Solved: Unzip Function
Views: 8,592
Posted By wonder_gal
The problem came from the string array actually. :)
Forum: VB.NET Apr 11th, 2007
Replies: 9
Solved: Unzip Function
Views: 8,592
Posted By wonder_gal
Hi all,

My problem been solved. Thanks for reading anyway. ;)
Forum: VB.NET Apr 11th, 2007
Replies: 9
Solved: Unzip Function
Views: 8,592
Posted By wonder_gal
Hi,

I've tried your suggestion, it cannot work, because it says the expression


x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")


does not return a value. :(
Forum: VB.NET Apr 11th, 2007
Replies: 9
Solved: Unzip Function
Views: 8,592
Posted By wonder_gal
Hi,

I am writing a function to unzip a zipped file. But I'm getting this error, "Cast from string "C:\temp\FileName.zip" to type 'Integer' is not valid." Below is my coding, I got this error in...
Showing results 1 to 10 of 10

 


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