I actually worked out the exercise with a double array , as you said ( a[5][80 ). But I was just churious about mohammad's version . :rolleyes:

I want it with #include <iostream> and all the rest ( cout & cin) . This one doesn't work:


#include <iostream>
#include <conio.h>
using namespace std;
main()
{ char *a[5]; int i;...

Indeed , I haven't tested them until now. It seems like both versions give the same result ...

My guess is: i should start from 0? :p

Hehe. :) It should be like this:


for(i=1;i<=n;i++)

NOT

for(i=1;i<=n;++i)

I apologize. That one I didn't test. Here is the correct version , tested :cheesy: :

#include <iostream>
#include <conio.h>
using namespace std;
int main()
{ int a[50],b[50],i,j,n;...

Try
#include <iostream.h>
void main()
{ ...... /* your program here */
cin.get();
}

It should work .

It works fine as for(i=1;i<=n;i++) . Trust me. :lol:

It works , altought the exercise says that I should use two arrays , one for the names and one for the grades. Oh well , it's important that it works ... :)

Thank you very much!

Do you mean something like
a[1][1] = "Victor";
a[2][2] = "Jose"; ???

I mean:
char a[30][30],i,n;
cout<<"n= "; cin>>n;
for(i=1;i<=n;i++) { cout<<"Give "<<i<<"-st name: "; cin>>a[i]; }
...

It'll be something like this:

#include <iostream.h>
#include <conio.h>
void main()
{ clrscr(); int a[50],b[50],i,n,g;
cout<<"Give the number of elements of both vectors: "; cin>>n;...

As this is my first post on this forum I want to say "Hello!" to everybody and I hope that we'll help each other as much as we can and we'll be very good friends. :)

So, this is my problem ( a...