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issue in a script invloving month arithmetic

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Join Date: Dec 2007

Posts: 4

Reputation: rajarp is an unknown quantity at this point

Solved Threads: 0

rajarp

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Newbie Poster

issue in a script invloving month arithmetic

Dec 30th, 2007

advance happy new year to all,
i am having a script.The purpose of the scripts is as follows.If the current month is march,june,september or december ,increment flag should be set to '1' otherwise increment flag should be set to '2'.the script is as follows

month= date +"%m"
if [ "$month" -eq 3 ] || [ "$month" -eq 6 ] || [ "$month" -eq 9 ] ||
[ "$month" -eq 12 ] ; then
inc_flg = 1
else
inc_flg = 2
fi

But am getting inc_flg =2 always.please help me to solve this issue.Is there anyother way to write a script???please help me.
regards,
rajarp

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Join Date: Oct 2007

Posts: 399

Reputation: eggi will become famous soon enough

Solved Threads: 47

eggi

Offline

Posting Whiz

Re: issue in a script invloving month arithmetic

Dec 31st, 2007

Hey There,

I'm not sure what you're looking to do over time (since you'll have to deal with leap years, etc), but the two things I found in the script were the way the "if" statement was setup and the assignment for the "month" variable.

I rewrote it very quickly like this and it gives you the result you wanted:

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month=`date +"%m"`
if [ "$month" -eq 3 -o "$month" -eq 6 -o "$month" -eq 9 -o "$month" -eq 12 ]
then
inc_flg=1
else
inc_flg=2
fi
echo "INC_FLG $inc_flg"
month=`date +"%m"`
if [ "$month" -eq 3 -o "$month" -eq 6 -o "$month" -eq 9 -o "$month" -eq 12 ]
then
inc_flg=1
else
inc_flg=2
fi
echo "INC_FLG $inc_flg"

Hope that helped you out

, Mike

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