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Views: 2681 | Replies: 85 | Solved
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Join Date: Oct 2007
Location: Bristol, UK
Posts: 1,122
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Rep Power: 3
Solved Threads: 47
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Join Date: Oct 2007
Location: Bristol, UK
Posts: 1,122
Reputation:
Rep Power: 3
Solved Threads: 47
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Join Date: Oct 2007
Location: Bristol, UK
Posts: 1,122
Reputation:
Rep Power: 3
Solved Threads: 47
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Join Date: Sep 2007
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Yes you won't be able to do that.
No, what I mean is that after you are done saving and formatting the XML document, compeletely done with it, add that code there, or in your case:
Server.Transfer("C:/temp/" + FileUpload1.FileName)
That should basically be your last line of code after converting everything.
No, what I mean is that after you are done saving and formatting the XML document, compeletely done with it, add that code there, or in your case:
Server.Transfer("C:/temp/" + FileUpload1.FileName)
That should basically be your last line of code after converting everything.
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Join Date: Oct 2007
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hmmm. Having done that, getting runtime exception of "expected virtual path"
I put that line right before the return strHtml statement at bottom of code.lol this is my first asp.net app - talk about jumping in at deep end !
I put that line right before the return strHtml statement at bottom of code.lol this is my first asp.net app - talk about jumping in at deep end !
Last edited by majestic0110 : Feb 6th, 2008 at 10:41 am. Reason: missed a bit out
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You are receiving that error on the code "C:/..."? That's odd, but okay. So put the server.mappath("") relative to your document. If your document is in C:/documents/asppage.aspx then put something like this:
server.transfer(server.mappath("../temp/" & FileUpload1.FileName))
Oh, and keep in mind that if "filename" is only the name, you will have to add ".xml" at the end. Spit out (server.mappath("../temp/" & FileUpload1.FileName)) to see if it is displaying correctly. (put it in a response.write)
server.transfer(server.mappath("../temp/" & FileUpload1.FileName))
Oh, and keep in mind that if "filename" is only the name, you will have to add ".xml" at the end. Spit out (server.mappath("../temp/" & FileUpload1.FileName)) to see if it is displaying correctly. (put it in a response.write)
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Join Date: Oct 2007
Location: Bristol, UK
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Rep Power: 3
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Join Date: Oct 2007
Location: Bristol, UK
Posts: 1,122
Reputation:
Rep Power: 3
Solved Threads: 47
OK here is what I currently have
using System;
using System.Data;
using System.Configuration;
using System.Collections;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System.Xml;
using System.Xml.Xsl;
using System.Xml.XPath;
using System.IO;
namespace runXslt { }
public partial class Default2 : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
}
protected void Button1_Click(object sender, EventArgs e)
{
// Specify the path on the server to
// save the uploaded file to.
String savePath = "C:/temp/";
// Get the name of the file to upload.
String fileName = FileUpload1.FileName;
// Get the extension of the uploaded file.
string extension = System.IO.Path.GetExtension(fileName);
// Before attempting to perform operations
// on the file, verify that the FileUpload
// control contains a file.
if (FileUpload1.HasFile)
{
if ((extension == ".xml"))
{
// Append the name of the file to upload to the path.
savePath += fileName;
// Call the SaveAs method to save the
// uploaded file to the specified path.
// If a file with the same name
// already exists in the specified path,
// the uploaded file overwrites it.
FileUpload1.SaveAs(savePath);
// Notify the user of the name of the newly saved file
Label1.Text = "SUCCESS! - Your file was uploaded and converted as " + fileName;
//call XSLT transform
ApplyXSLTransformation();
}
else
{
// Notify the user why their file was not uploaded.
Label1.Text = "ERROR - Your file was not uploaded or converted because " +
fileName + "it does not have a .xml extension.";
}
}
else
{
// Notify the user that a file was not uploaded.
Label1.Text = "ERROR - You did not specify a file to upload.";
}
}
protected void LinkButton1_Click(object sender, EventArgs e)
{
}
private string ApplyXSLTransformation()
{
string strHtml;
string strXstFile = Server.MapPath("test.xslt");
XslCompiledTransform x = new XslCompiledTransform();
// Load the XML - use (Server.MapPath("/temp/" + FileUpload1.FileName));
//if using server i.e. not local machine
XPathDocument doc = new XPathDocument(("C:/temp/" + FileUpload1.FileName));
// Load the style sheet.
XslCompiledTransform xslt = new XslCompiledTransform();
xslt.Load(strXstFile);
MemoryStream ms = new MemoryStream();
XmlTextWriter writer = new XmlTextWriter(ms, null);
StreamReader rd = new StreamReader(ms);
xslt.Transform(doc, writer);
ms.Position = 0;
strHtml = rd.ReadToEnd();
rd.Close();
ms.Close();
Server.Transfer(Server.MapPath("C:/temp/dl" + FileUpload1.FileName));
return strHtml;
}
} Last edited by majestic0110 : Feb 6th, 2008 at 11:18 am. Reason: highlight area of interest
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Join Date: Sep 2007
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try specifying the name of the file. server.transfer may not allow transfering to a XML file, you know? It may only except .net extensions.'
You can try response.redirect instead, or build a "thank you" page with the download link where they can download the file. Then they can click and download it when they are ready.
You can try response.redirect instead, or build a "thank you" page with the download link where they can download the file. Then they can click and download it when they are ready.
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