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Using command line parameters

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Join Date: Sep 2004

Posts: 3

Reputation: db0 is an unknown quantity at this point

Solved Threads: 0

db0

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Newbie Poster

Using command line parameters

Sep 16th, 2004

Hi all. Somthing strange is going on... I want to use "-debug" command line parameter to make my app show some debug info. Here is my code (not entire but needed part)...

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#include <iostream.h>
 
bool debug_mode=0;
 
int main(int argc, char **argv)
{
 
if(argv>1) cout << argv[0] << endl << argv[1] << endl;
 
if( (argc>1) && (argv[1]=="-debug") ) debug_mode=1;
 
// Some code that checks my database integrity, and does not use
// debug_mode variable in any way
 
if(debug_mode)
{
  cout << "Some debug information" << endl;
}
 
// here is additional code
 
return 0;
 
}
#include <iostream.h>

bool debug_mode=0;

int main(int argc, char **argv)
{

if(argv>1) cout << argv[0] << endl << argv[1] << endl;

if( (argc>1) && (argv[1]=="-debug") ) debug_mode=1;

// Some code that checks my database integrity, and does not use
// debug_mode variable in any way

if(debug_mode)
{
  cout << "Some debug information" << endl;
}

// here is additional code

return 0;

}

The problem is that when I start my app with "-debug" (exactly "./dbreader -debug") parameter I can see that my argv[0] is "./dbreader" and argv[1] is exactly "-debug" but my IF STATMENT didn't set debug_mode to "1", and so no additional info is shown...

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