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Parse error: syntax error, unexpected $end

  #1  
Feb 16th, 2008
Hi all

I m using following code..
<?php
session_start();

if(!isset($_SESSION['captcha'])){session_register('captcha');}
$PHP_SELF = $_SERVER['PHP_SELF'];
$stringa = '';
$cifre = 5;
for($i=1;$i<=$cifre;$i++){
	$letteraOnumero = rand(1,2);
	if($letteraOnumero == 1){
		// lettera
		$lettere = 'ABEFHKMNRVWX';
		$x = rand(1,11);
		$lettera = substr($lettere,$x,1);
		$stringa .= $lettera;
	} else {
		$numero = rand(3,7);
		$stringa .= $numero;
	}
}
$_SESSION['captcha'] = $stringa;
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<link rel="stylesheet" type="text/css" href="css/styles.css" />
</head>
<body>
<table width="100" height="54" border="0" cellpadding="0" cellspacing="0" bgcolor="#FFFFFF" id="Table_01">
  <tr>
    <td height="39"  align="left" valign="top" class="imagesstyle"><h1 class="style2"><img src="3EImages/dot3E.jpg" alt="" width="29" height="29" align="left" class="imagesstyle" />General Enquiry<br />
   </h1>
   <td height="39"  valign="top" style="padding-top: 5px"><a href="http://www.3esolutionsindia.com/" target="_blank">Home</a></td>
   </td>
  </tr>
  <tr>
    <td  align="left" valign="top" class="tableDetail"><p><img src="3EImages/ContactUs/Enquiry.jpg" width="170" height="124" align="right" class="imgbrdr" /><strong>Thanks for showing interest in  3E Solutions.</strong> <br />
            <br />
Kindly fill all the required  fields. We will get in touch with you within 24 hours.</p>
      <p>&nbsp;</p>
	<form id="captchaform" action="enquiry.php" method="post" style="width:300px;">
        <p align="right"> <label>
        *Name:
        <input type="text" name="name" id="name" size="30"/>
        </label></p>
        <p align="right">*Email Address:
          <label>
          <input type="text" name="email" id="email" size="30" />
          </label>
        </p>
        <p align="right">Phone No:
          <label>
          <input type="text" name="phone" id="phone" size="30" />
          </label>
        </p>
        <p align="right" style="">Interseted in:
          <label>
          <textarea name="interested" cols="30" rows="6" wrap="physical" id="interested">
          </textarea>
          </label>
		</p>
		<p align="right">
				<div id="captcha">
				<p align="right"><img src="captcha.php" />&nbsp;&nbsp;</p>
				<p align="right"><label for="code">*Enter Code: </label>
				<input type="text" name="code" id="code" size="30" /></p>
				</div>
				</p>
				<p align="right"><input type="submit" name="button" id="button" value="Submit" style="font-size:small;color: black;" />&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
		</form>
      </td>
  </tr>
  </table>
</body>
</html>
and getting arror as--
Parse error: syntax error, unexpected $end in /home/esolutio/public_html/enquirycaptcha.php on line 1


i m not getting where is the problem..
plz reply.
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Re: Parse error: syntax error, unexpected $end

  #2  
Feb 16th, 2008
I ran your script and I didn't get any error. Maybe you are getting the error because there is no space after
if(!isset($_SESSION['captcha'])){session_register('captcha');}
Replace this line by this.
  1. if(!isset($_SESSION['captcha'])){ session_register('captcha'); }

Cheers,
Naveen
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Re: Parse error: syntax error, unexpected $end

  #3  
Feb 16th, 2008
unexpected generaly means youve missed a '}' somwhere and php parser has reached the end of the script expecting it get used to error checking
1) get a decent text editor i use textpad which is so so.
2) using your new editor remove parts of code and trial the script until it runs smoothly that way you will narrow down the location of the error.
3) if you find you have messed your script up just (ctrl z)undo it and it will regress to its former state

im fairly new at php but there hasnt been an error that hasnt got passed my 'trial and error' above. hope i helped
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Re: Parse error: syntax error, unexpected $end

  #4  
Feb 16th, 2008
ORIGINAL
<?php
session_start();

if(!isset($_SESSION['captcha'])){session_register('captcha');}
$PHP_SELF = $_SERVER['PHP_SELF'];
$stringa = '';
$cifre = 5;
for($i=1;$i<=$cifre;$i++){
$letteraOnumero = rand(1,2);
if($letteraOnumero == 1){
// lettera
$lettere = 'ABEFHKMNRVWX';
$x = rand(1,11);
$lettera = substr($lettere,$x,1);
$stringa .= $lettera;
} else {
$numero = rand(3,7);
$stringa .= $numero;
}
}


FIXED

<?php
session_start();

if(!isset($_SESSION['captcha'])){session_register('captcha');}
$PHP_SELF = $_SERVER['PHP_SELF'];
$stringa = '';
$cifre = 5;
for($i=1;$i<=$cifre;$i++){
$letteraOnumero = rand(1,2);
if($letteraOnumero == 1){
// lettera
$lettere = 'ABEFHKMNRVWX';
$x = rand(1,11);
$lettera = substr($lettere,$x,1);
$stringa .= $lettera;
} }else {
$numero = rand(3,7);
$stringa .= $numero;
}
}
Last edited by cmarkme : Feb 16th, 2008 at 3:36 am. Reason: IGNORE I MADE A MISTAKE
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Re: Parse error: syntax error, unexpected $end

  #5  
Feb 16th, 2008
Originally Posted by cmarkme View Post
ORIGINAL
<?php
session_start();

if(!isset($_SESSION['captcha'])){session_register('captcha');}
$PHP_SELF = $_SERVER['PHP_SELF'];
$stringa = '';
$cifre = 5;
for($i=1;$i<=$cifre;$i++){
$letteraOnumero = rand(1,2);
if($letteraOnumero == 1){
// lettera
$lettere = 'ABEFHKMNRVWX';
$x = rand(1,11);
$lettera = substr($lettere,$x,1);
$stringa .= $lettera;
} else {
$numero = rand(3,7);
$stringa .= $numero;
}
}


FIXED

<?php
session_start();

if(!isset($_SESSION['captcha'])){session_register('captcha');}
$PHP_SELF = $_SERVER['PHP_SELF'];
$stringa = '';
$cifre = 5;
for($i=1;$i<=$cifre;$i++){
$letteraOnumero = rand(1,2);
if($letteraOnumero == 1){
// lettera
$lettere = 'ABEFHKMNRVWX';
$x = rand(1,11);
$lettera = substr($lettere,$x,1);
$stringa .= $lettera;
} }else {
$numero = rand(3,7);
$stringa .= $numero;
}
}


That wouldn't fix anything. There is a } at the end which is for 'for loop'. You just closed the 'for loop' after 'if loop'. That would generate an error
Parse error: syntax error, unexpected T_ELSE
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Re: Parse error: syntax error, unexpected $end

  #6  
Feb 16th, 2008
Actually i m getting this error when i upload my page on the web..
insted when i run this on my pc, it won't generate any error..

So what can i do..

plz help..
thnks all...
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Re: Parse error: syntax error, unexpected $end

  #7  
Feb 16th, 2008
That's strange! do you have error_reporting turned on on your local system ?
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Re: Parse error: syntax error, unexpected $end

  #8  
Feb 16th, 2008
I dont know about that..

How to check that??
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Re: Parse error: syntax error, unexpected $end

  #9  
Feb 16th, 2008
Open php.ini and search for display_errors. If its off, turn it On. Then look for error_reporting. Uncomment this line. error_reporting = E_ALL & ~E_NOTICE & ~E_STRICT.
Or, add ini_set("display_errors","On"); error_reporting(E_ALL); in your script.
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Re: Parse error: syntax error, unexpected $end

  #10  
Feb 17th, 2008
I m still getting the problem..

i've checked php.ini
All the settings are correct..

But it is happing so.. Is there need extra setting while uploading the php..

plz help..
thanks..
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