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Array of Strings???

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Join Date: Jan 2008

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plgriffith plgriffith is offline

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Array of Strings???

Feb 21st, 2008

Ok, I know C/C++ really well, but just started Java today and am having an issue. I have an assignment where I have to ask the user how many names he wants to enter, and then have him enter all of the names. After all of the names have been entered, they have to be printed back out. I am not worried about the printing part, but I am worried about how to store all of these names. So far I have,

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
import java.io.*; 
public class Problem2
{
 
 
  private static BufferedReader stdin =  new BufferedReader( new InputStreamReader( System.in ) );
 
  public static void main(String[] arguments) throws IOException
  {
    System.out.println("Welcome. How many names do you wish to enter?");
    String input = stdin.readLine();
    int nameCount = Integer.parseInt(input);
 
    for(int i = 0; i < nameCount; i++)
      {
	System.out.print("Enter name: ");
 
	//NEED HELP HERE
 
 
      }
 
  }
}
import java.io.*; 
public class Problem2
{


  private static BufferedReader stdin =  new BufferedReader( new InputStreamReader( System.in ) );

  public static void main(String[] arguments) throws IOException
  {
    System.out.println("Welcome. How many names do you wish to enter?");
    String input = stdin.readLine();
    int nameCount = Integer.parseInt(input);

    for(int i = 0; i < nameCount; i++)
      {
	System.out.print("Enter name: ");

	//NEED HELP HERE


      }
  
  }
}

Thanks for any help you can provide!

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Join Date: May 2007

Posts: 4,445

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Ezzaral

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Re: Array of Strings???

Feb 21st, 2008

Yes, for your purposes a simple array of String would be all that was needed.

Help with Code Tags

(Toggle Plain Text)

import java.io.*; 
public class Problem2
{


  private static BufferedReader stdin =  new BufferedReader( new InputStreamReader( System.in ) );

  public static void main(String[] arguments) throws IOException
  {
    System.out.println("Welcome. How many names do you wish to enter?");
    String input = stdin.readLine();
    int nameCount = Integer.parseInt(input);
    String[] names = new String[nameCount];
    for(int i = 0; i < nameCount; i++)
      {
	System.out.print("Enter name: ");

	//NEED HELP HERE
        names[i] = stdin.readLine();
      }
  
  }
}

•

Join Date: Jan 2008

Posts: 97

Reputation: plgriffith is an unknown quantity at this point

Solved Threads: 6

plgriffith plgriffith is offline

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Junior Poster in Training

Re: Array of Strings???

Feb 21st, 2008

thanks ezzaral, that worked like a charm.

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Join Date: May 2007

Posts: 4,445

Reputation: Ezzaral has much to be proud of

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Ezzaral

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Re: Array of Strings???

Feb 21st, 2008

On a side note, never throw exceptions from main() - there is nothing above main in the call stack to handle them. Place try-catch blocks around the code inside main as needed and at the very least print a stack trace in the catch block.

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
    public static void main(String args[]) {
        try {
            BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
            System.out.println("Welcome. How many names do you wish to enter?");
            String input = stdin.readLine();
            int nameCount = Integer.parseInt(input);
            String[] names = new String[nameCount];
            for(int i = 0; i<nameCount; i++) {
                System.out.print("Enter name: ");
 
                //NEED HELP HERE
                names[i] = stdin.readLine();
            }
        } catch(IOException ioe) {
            ioe.printStackTrace();
        }
    }
    public static void main(String args[]) {
        try {
            BufferedReader stdin = new BufferedReader(new InputStreamReader(System.in));
            System.out.println("Welcome. How many names do you wish to enter?");
            String input = stdin.readLine();
            int nameCount = Integer.parseInt(input);
            String[] names = new String[nameCount];
            for(int i = 0; i<nameCount; i++) {
                System.out.print("Enter name: ");

                //NEED HELP HERE
                names[i] = stdin.readLine();
            }
        } catch(IOException ioe) {
            ioe.printStackTrace();
        }
    }