Prog to list ASCII codes (beginners' stuff)

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Prog to list ASCII codes (beginners' stuff)

 
1
  #1
Sep 24th, 2004
Hi,

I just started a program containing every single prog we have done for school so far and added some private stuff.
Searching through my older files I found a prog which lists all Integers between 1 and 255 and their respective ASCII char, so I decided to include it into my 'collection'.

The problem is that 'twas a Win32 executable and we're working under DOS. Well actually this wouldn't be much of a problem, but the script seems no to work under DOS.

Well, first of here's the script:
  1. # include <iostream.h>
  2. # include <conio.h>
  3.  
  4. main()
  5. {
  6. int i, j, ip, ipp;
  7. float k, l;
  8. char zeichen;
  9. for (i=1;i<=254;i++)
  10. {
  11. zeichen=i;
  12. cout<<"\n"<<i<<" - "<<zeichen;
  13. j=1;
  14. for (j=1;j<=25;j++)
  15. {
  16. k=1.0*i/20;
  17. l=1.0*j;
  18. if (k==l)
  19. {
  20. ip=i+1;
  21. ipp=i+20;
  22. if (i<=240) cout<<"\n\n(Press any key --> "<<ip<<" to "<<ipp<<" )";
  23. getch();
  24. clrscr();
  25. };
  26. }
  27. }
  28. getch();
  29. }

As I stated, no problems under Win32, but under DOS it stops at 26 and after pressing a key again the screen gets cleared again and stays black.

So my question is..is there any way to get something like this running under DOS?

I tried a simple "cin>>intvar; charvar=intvar; cout<<charvar;" aswell, but any value above 25 simply results in nothing being put out.

Well, thanks in advance.~
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Re: Prog to list ASCII codes (beginners' stuff)

 
0
  #2
Sep 24th, 2004
Skip 26. Or better yet, skip printing everything non-printable.
  1. #include <stdio.h>
  2. #include <ctype.h>
  3.  
  4. int main(void)
  5. {
  6. int i;
  7. for ( i = 0; i < 256; ++i )
  8. {
  9. putchar(isprint(i) ? i : '.');
  10. putchar(i % 16 == 15 ? '\n' : ' ');
  11. }
  12. return 0;
  13. }
  14.  
  15. /* my output
  16.  . . . . . . . . . . . . . . . .
  17.  . . . . . . . . . . . . . . . .
  18.   ! " # $ % & ' ( ) * + , - . /
  19.  0 1 2 3 4 5 6 7 8 9 : ; < = > ?
  20.  @ A B C D E F G H I J K L M N O
  21.  P Q R S T U V W X Y Z [ \ ] ^ _
  22.  ` a b c d e f g h i j k l m n o
  23.  p q r s t u v w x y z { | } ~ .
  24.  . . . . . . . . . . . . . . . .
  25.  . . . . . . . . . . . . . . . .
  26.  . . . . . . . . . . . . . . . .
  27.  . . . . . . . . . . . . . . . .
  28.  . . . . . . . . . . . . . . . .
  29.  . . . . . . . . . . . . . . . .
  30.  . . . . . . . . . . . . . . . .
  31.  . . . . . . . . . . . . . . . .
  32.  */
Last edited by Dave Sinkula; Sep 24th, 2004 at 6:45 pm. Reason: Added code.
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Re: Prog to list ASCII codes (beginners' stuff)

 
0
  #3
Sep 24th, 2004
Originally Posted by Dave Sinkula
Skip 26. Or better yet, skip printing everything non-printable.
Wow, thanks for the fast reply.

Well, but how to skip them most easily?

The first and more or less only thing that comes into my mind is like:

if ( i != 26 && i != anotherone && i != yetanotherone &&...
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Re: Prog to list ASCII codes (beginners' stuff)

 
0
  #4
Sep 24th, 2004
[Oops. I see your reply beat my edit.]

I'd use isprint.

  1. #include <stdio.h>
  2. #include <ctype.h>
  3.  
  4. int main(void)
  5. {
  6. int i;
  7. for ( i = 0; i < 128; ++i )
  8. {
  9. putchar(isprint(i) ? i : '.');
  10. putchar(i % 32 == 31 ? '\n' : ' ');
  11. }
  12. return 0;
  13. }
  14.  
  15. /* my output
  16.  . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
  17.   ! " # $ % & ' ( ) * + , - . / 0 1 2 3 4 5 6 7 8 9 : ; < = > ?
  18.  @ A B C D E F G H I J K L M N O P Q R S T U V W X Y Z [ \ ] ^ _
  19.  ` a b c d e f g h i j k l m n o p q r s t u v w x y z { | } ~ .
  20.  */
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
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Re: Prog to list ASCII codes (beginners' stuff)

 
0
  #5
Sep 24th, 2004
I see, thanks again.

But seeing this...

The output under Win32 is like:
  1. 1 - ☺
  2. 2 - ☻
  3. 3 - ♥
  4. 4 - ♦
  5. 5 - ♣
  6. 6 - ♠
  7. 7 -
  8. 8 -
  9. 9 -
  10. 10 -
  11. 11 - ♂
  12. 12 - ♀
  13. 13 -
  14. 14 - ♫
  15. 15 - ☼
  16. 16 - ►
  17. 17 - ◄
  18. 18 - ↕
  19. 19 - ‼
  20. 20 - ¶
  21. 21 - §
And so on, so...

Aint I able to display the 255 ones of those under Dos?
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Re: Prog to list ASCII codes (beginners' stuff)

 
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  #6
Sep 24th, 2004
Check out http://www.asciitable.com/

The full list of ASCII characters are there. The function isprint() knows which of the characters are printable. isprint() returns a nonzero value if the input is a printable character, including the space character (0x20 – 0x7E). The other characters are either extended, or do other features which aren't print friendly.

More information on isprint()
isprint() is included in the ctype library, ctype.h:

int isprint(int c);
» This function returns nonzero if c is a space or a character for which either isalnum() or ispunct() returns nonzero.

int isalnum(int c);
» This function returns nonzero if c is any of or other locale-specific alphabetic character.
According to AsciiTable.com
Characters	ASCII
a thru z	97 thru 122
A thru Z	65 thru 90
0 thru 9	48 thru 57
int ispunct(int c);
» This function returns nonzero if c is any of the following or other implementation-defined punctuation character:
According to AsciiTable.com
Characters			ASCII
! " # $ % & ' ( ) * + , - . /	33 thru 47
: ; < = > ? @			58 thru 64
[ \ ] ^ _ '			91 thru 96
{ | } ~				123 thru 126

Hope this helps,
- Stack Overflow
Last edited by Stack Overflow; Sep 24th, 2004 at 8:15 pm. Reason: More detailed information
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Re: Prog to list ASCII codes (beginners' stuff)

 
0
  #7
Sep 24th, 2004
Thanks, might be quite of use, though probably not directly in what I'm thinking of.

See the attachments, I just want the fourth attachment (Dos, page2) to be like the second one (W32, page2).
Attached Images
File Type: jpg w32a.JPG (8.5 KB, 4 views)
File Type: jpg w32b.JPG (10.2 KB, 5 views)
File Type: jpg dosa.JPG (10.7 KB, 5 views)
File Type: jpg dosb.JPG (4.3 KB, 5 views)
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Re: Prog to list ASCII codes (beginners' stuff)

 
0
  #8
Sep 24th, 2004
Originally Posted by Stack Overflow
Check out http://www.asciitable.com/

The full list of ASCII characters are there. The function isprint() knows which of the characters are printable. isprint() returns a nonzero value if the input is a printable character, including the space character (0x20 – 0x7E). The other characters are either extended, or do other features which aren't print friendly.

More information on isprint()
isprint() is included in the ctype library, ctype.h:

int isprint(int c);
» This function returns nonzero if c is a space or a character for which either isalnum() or ispunct() returns nonzero.

int isalnum(int c);
» This function returns nonzero if c is any of or other locale-specific alphabetic character.
According to AsciiTable.com
 Characters	ASCII
 a thru z	97 thru 122
 A thru Z	65 thru 90
 0 thru 9	48 thru 57
int ispunct(int c);
» This function returns nonzero if c is any of the following or other implementation-defined punctuation character:
According to AsciiTable.com
 Characters			ASCII
 ! " # $ % & ' ( ) * + , - . /	33 thru 47
 : ; < = > ? @			58 thru 64
 [ \ ] ^ _ '			91 thru 96
 { | } ~				123 thru 126

Hope this helps,
- Stack Overflow
The greater utility of functions like ispunct and isalnum are that they also work with other character sets, some of which, for example, do not necessarily have a contiguous alphabet or such. They are designed to work regardless of the particular implementation.
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Re: Prog to list ASCII codes (beginners' stuff)

 
0
  #9
Sep 24th, 2004
Originally Posted by Anu
See the attachments, I just want the fourth attachment (Dos, page2) to be like the second one (W32, page2).
DOS has a particular issue with the value 26. Apparently it is an end-of-file marker. So on a DOS system, it will not work the way you'd like. Thus my recommendation to skip it.
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Re: Prog to list ASCII codes (beginners' stuff)

 
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  #10
Sep 25th, 2004
That was all I actually wanted to know. Thanks once again. ^^
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