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Views: 6793 | Replies: 11
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Join Date: Sep 2004
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Newbie Poster
Hi,
I just started a program containing every single prog we have done for school so far and added some private stuff.
Searching through my older files I found a prog which lists all Integers between 1 and 255 and their respective ASCII char, so I decided to include it into my 'collection'.
The problem is that 'twas a Win32 executable and we're working under DOS. Well actually this wouldn't be much of a problem, but the script seems no to work under DOS.
Well, first of here's the script:
As I stated, no problems under Win32, but under DOS it stops at 26 and after pressing a key again the screen gets cleared again and stays black.
So my question is..is there any way to get something like this running under DOS?
I tried a simple "cin>>intvar; charvar=intvar; cout<<charvar;" aswell, but any value above 25 simply results in nothing being put out.
Well, thanks in advance.~
I just started a program containing every single prog we have done for school so far and added some private stuff.
Searching through my older files I found a prog which lists all Integers between 1 and 255 and their respective ASCII char, so I decided to include it into my 'collection'.
The problem is that 'twas a Win32 executable and we're working under DOS. Well actually this wouldn't be much of a problem, but the script seems no to work under DOS.
Well, first of here's the script:
# include <iostream.h>
# include <conio.h>
main()
{
int i, j, ip, ipp;
float k, l;
char zeichen;
for (i=1;i<=254;i++)
{
zeichen=i;
cout<<"\n"<<i<<" - "<<zeichen;
j=1;
for (j=1;j<=25;j++)
{
k=1.0*i/20;
l=1.0*j;
if (k==l)
{
ip=i+1;
ipp=i+20;
if (i<=240) cout<<"\n\n(Press any key --> "<<ip<<" to "<<ipp<<" )";
getch();
clrscr();
};
}
}
getch();
}As I stated, no problems under Win32, but under DOS it stops at 26 and after pressing a key again the screen gets cleared again and stays black.
So my question is..is there any way to get something like this running under DOS?
I tried a simple "cin>>intvar; charvar=intvar; cout<<charvar;" aswell, but any value above 25 simply results in nothing being put out.
Well, thanks in advance.~
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Join Date: Apr 2004
Posts: 3,418
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Skip 26. Or better yet, skip printing everything non-printable.
#include <stdio.h>
#include <ctype.h>
int main(void)
{
int i;
for ( i = 0; i < 256; ++i )
{
putchar(isprint(i) ? i : '.');
putchar(i % 16 == 15 ? '\n' : ' ');
}
return 0;
}
/* my output
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
! " # $ % & ' ( ) * + , - . /
0 1 2 3 4 5 6 7 8 9 : ; < = > ?
@ A B C D E F G H I J K L M N O
P Q R S T U V W X Y Z [ \ ] ^ _
` a b c d e f g h i j k l m n o
p q r s t u v w x y z { | } ~ .
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
. . . . . . . . . . . . . . . .
*/
Last edited by Dave Sinkula : Sep 24th, 2004 at 5:45 pm. Reason: Added code.
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Newbie Poster
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Originally Posted by Dave Sinkula
Skip 26. Or better yet, skip printing everything non-printable.
Wow, thanks for the fast reply.
Well, but how to skip them most easily?
The first and more or less only thing that comes into my mind is like:
if ( i != 26 && i != anotherone && i != yetanotherone &&...
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[Oops. I see your reply beat my edit.]
I'd use isprint.
I'd use isprint.
#include <stdio.h>
#include <ctype.h>
int main(void)
{
int i;
for ( i = 0; i < 128; ++i )
{
putchar(isprint(i) ? i : '.');
putchar(i % 32 == 31 ? '\n' : ' ');
}
return 0;
}
/* my output
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
! " # $ % & ' ( ) * + , - . / 0 1 2 3 4 5 6 7 8 9 : ; < = > ?
@ A B C D E F G H I J K L M N O P Q R S T U V W X Y Z [ \ ] ^ _
` a b c d e f g h i j k l m n o p q r s t u v w x y z { | } ~ .
*/ •
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Newbie Poster
I see, thanks again.
But seeing this...
The output under Win32 is like:
And so on, so...
Aint I able to display the 255 ones of those under Dos?
But seeing this...
The output under Win32 is like:
1 - ☺ 2 - ☻ 3 - ♥ 4 - ♦ 5 - ♣ 6 - ♠ 7 - 8 - 9 - 10 - 11 - ♂ 12 - ♀ 13 - 14 - ♫ 15 - ☼ 16 - ► 17 - ◄ 18 - ↕ 19 - ‼ 20 - ¶ 21 - §
Aint I able to display the 255 ones of those under Dos?
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Join Date: Sep 2004
Location: Overflow State
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C Programmer
Check out http://www.asciitable.com/
The full list of ASCII characters are there. The function isprint() knows which of the characters are printable. isprint() returns a nonzero value if the input is a printable character, including the space character (0x20 – 0x7E). The other characters are either extended, or do other features which aren't print friendly.
More information on isprint()
isprint() is included in the ctype library, ctype.h:
int isprint(int c);
» This function returns nonzero if c is a space or a character for which either isalnum() or ispunct() returns nonzero.
int isalnum(int c);
» This function returns nonzero if c is any of or other locale-specific alphabetic character.
int ispunct(int c);
» This function returns nonzero if c is any of the following or other implementation-defined punctuation character:
Hope this helps,
- Stack Overflow
The full list of ASCII characters are there. The function isprint() knows which of the characters are printable. isprint() returns a nonzero value if the input is a printable character, including the space character (0x20 – 0x7E). The other characters are either extended, or do other features which aren't print friendly.
More information on isprint()
isprint() is included in the ctype library, ctype.h:
int isprint(int c);
» This function returns nonzero if c is a space or a character for which either isalnum() or ispunct() returns nonzero.
int isalnum(int c);
» This function returns nonzero if c is any of or other locale-specific alphabetic character.
According to AsciiTable.com Characters ASCII a thru z 97 thru 122 A thru Z 65 thru 90 0 thru 9 48 thru 57
» This function returns nonzero if c is any of the following or other implementation-defined punctuation character:
According to AsciiTable.com
Characters ASCII
! " # $ % & ' ( ) * + , - . / 33 thru 47
: ; < = > ? @ 58 thru 64
[ \ ] ^ _ ' 91 thru 96
{ | } ~ 123 thru 126Hope this helps,
- Stack Overflow
Last edited by Stack Overflow : Sep 24th, 2004 at 7:15 pm. Reason: More detailed information
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Newbie Poster
Thanks, might be quite of use, though probably not directly in what I'm thinking of.
See the attachments, I just want the fourth attachment (Dos, page2) to be like the second one (W32, page2).
See the attachments, I just want the fourth attachment (Dos, page2) to be like the second one (W32, page2).
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Originally Posted by Stack Overflow
Check out http://www.asciitable.com/
The full list of ASCII characters are there. The function isprint() knows which of the characters are printable. isprint() returns a nonzero value if the input is a printable character, including the space character (0x20 – 0x7E). The other characters are either extended, or do other features which aren't print friendly.
More information on isprint()
isprint() is included in the ctype library, ctype.h:
int isprint(int c);
» This function returns nonzero if c is a space or a character for which either isalnum() or ispunct() returns nonzero.
int isalnum(int c);
» This function returns nonzero if c is any of or other locale-specific alphabetic character.
int ispunct(int c);According to AsciiTable.com Characters ASCII a thru z 97 thru 122 A thru Z 65 thru 90 0 thru 9 48 thru 57
» This function returns nonzero if c is any of the following or other implementation-defined punctuation character:
According to AsciiTable.com Characters ASCII ! " # $ % & ' ( ) * + , - . / 33 thru 47 : ; < = > ? @ 58 thru 64 [ \ ] ^ _ ' 91 thru 96 { | } ~ 123 thru 126
Hope this helps,
- Stack Overflow
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Originally Posted by Anu
See the attachments, I just want the fourth attachment (Dos, page2) to be like the second one (W32, page2).
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