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Open Same forminstance Multiple times

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Open Same forminstance Multiple times

 
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  #1
Mar 24th, 2008
I wonder how it is possible to open 2 instances at the same time of a Form.
Normally when you ex press a button to open another form, one instance of that form is opened.

If I put these 2 lines inside a buttoncontrol, first one instance is opened and when I close this opened form, then the next line executes and the same form opens again.

How could it be possible to open both at the same time, so I have 2 instances open ?

C++ Syntax (Toggle Plain Text) 
  1. this->form2instance.ShowDialog();
  2. this->form2instance.ShowDialog();
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Re: Open Same forminstance Multiple times

 
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  #2
Mar 25th, 2008
Form::ShowDialog() shows the form as a modal dialog box. (the code following it is not executed until after the dialog box is closed.)
to show two instances of the same form:
a. create two instances of the Form (you seem to already have one instance, so create one more)
b. call Form::Show() on each of them.
Last edited by vijayan121; Mar 25th, 2008 at 12:32 am.
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Re: Open Same forminstance Multiple times

 
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  #3
Mar 25th, 2008
Yes, that seems logic.. thanks. I have created 2 instances now like this where I try to open 2 at the same time with the button2_Click_3 below but the same thing is happening here again.
First form21instance is opened and then when I close this instance, form22instance is opened.
Any idéas what this could depend on ?


C++ Syntax (Toggle Plain Text) 
  1. public ref class Form3 : public System::Windows::Forms::Form
  2. {
  3. 	private: Form2 form21instance;
  4. 	private: Form2 form22instance;
  5. }
C++ Syntax (Toggle Plain Text) 
  1. private: System::Void button2_Click_3(System::Object^  sender, System::EventArgs^  e) 
  2.  {
  3. 	 this->form21instance.ShowDialog();
  4. 	 this->form22instance.ShowDialog();
  5.  }

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Originally Posted by vijayan121 View Post
Form::ShowDialog() shows the form as a modal dialog box. (the code following it is not executed until after the dialog box is closed.)
to show two instances of the same form:
a. create two instances of the Form (you seem to already have one instance, so create one more)
b. call Form::Show() on each of them.
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Re: Open Same forminstance Multiple times

 
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  #4
Mar 25th, 2008
I have also tried to open another form at the same time.
So in this case I will actually open 2 different "Forms" in my application.
(Form2 and Form4).
When pressing the button, first Form2 is opened and when closed, then Form4 will open.
I cant figure out what this is depending on, though I want both forms to open at the same time.


C++ Syntax (Toggle Plain Text) 
  1. public ref class Form3 : public System::Windows::Forms::Form
  2. {
  3. 	private: Form4 form4instance;
  4. 	private: Form2 form22instance;
  5. }
C++ Syntax (Toggle Plain Text) 
  1. private: System::Void button2_Click_3(System::Object^  sender, System::EventArgs^  e) 
  2. {
  3. 	 this->form22instance.ShowDialog();
  4. 	 this->form4instance.ShowDialog();
  5. }
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Re: Open Same forminstance Multiple times

 
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  #5
Mar 25th, 2008
Like vijayan121 already pointed out, you need to use the Show() method instead of the ShowDialog(). So try ...
C++ Syntax (Toggle Plain Text) 
  1. private: System::Void button2_Click_3(System::Object^  sender, System::EventArgs^  e) 
  2. {
  3. 	 this->form22instance.Show();
  4. 	 this->form4instance.Show();
  5. }
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Re: Open Same forminstance Multiple times

 
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  #6
Mar 25th, 2008
Yes, I totally missed that. Ofcourse, .Show() works fine.
Thank you...


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Originally Posted by mitrmkar View Post
Like vijayan121 already pointed out, you need to use the Show() method instead of the ShowDialog(). So try ...
C++ Syntax (Toggle Plain Text) 
  1. private: System::Void button2_Click_3(System::Object^  sender, System::EventArgs^  e) 
  2. {
  3. 	 this->form22instance.Show();
  4. 	 this->form4instance.Show();
  5. }
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