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Views: 487 | Replies: 3
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Join Date: Mar 2008
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Newbie Poster
Hi,
I m developing a web application for video streming, but my client requires that as the user loging or singin in the site the web cam must be start automatically, and if the hardware is not found than a prompt must be displayed that "Your system doesn't support webcam facility'
I m trying to solve this problem since last 2 weeks, but i m not able to solve it. So any of u is able to solve it, plz try 4 me, i m requesting u people.
Thnxs,
I m developing a web application for video streming, but my client requires that as the user loging or singin in the site the web cam must be start automatically, and if the hardware is not found than a prompt must be displayed that "Your system doesn't support webcam facility'
I m trying to solve this problem since last 2 weeks, but i m not able to solve it. So any of u is able to solve it, plz try 4 me, i m requesting u people.
Thnxs,
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Join Date: Mar 2008
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Junior Poster
I don't believe you will find a way to access remote hardware using PHP.
If you do, please let me know.... maybe I can win a MacBook Air also!
Matti Ressler
Suomeia
If you do, please let me know.... maybe I can win a MacBook Air also!
Matti Ressler
Suomeia
Last edited by Suomedia : Mar 29th, 2008 at 12:23 pm.
If you want your dreams to come true, the first thing you must do is to wake up....
Suomedia - Dynamic Content Management
Suomedia - Dynamic Content Management
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Join Date: Aug 2005
Location: Cologne, Germany
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Junior Poster in Training
Guess you can do it in java or flash. Or you write you own lib and access it via exec. Could be worth trying it.
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Join Date: Nov 2007
Location: Bangalore, India
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I dont think that can be done using php. As sDjh has already mentioned, try that in java/flash or in .NET !
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
*PM asking for help will be ignored*
*PM asking for help will be ignored*
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