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convert char to hexadecimal

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Join Date: Apr 2008

Posts: 29

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savinki

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convert char to hexadecimal

Apr 20th, 2008

i want to convert char array element into hexadecimal value. But the code i wrote is not giving the output as i expect.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
unsigned char in[256];
 
void Text(const char *Buffer)
{
static char tempValue[256];
 
    for(int i=0;i<=len;i++)
    {
 
        	sprintf(&tempValue[i],"%02x", (unsigned char)Buffer[i]);
		in[i]=(unsigned char)tempValue[i];
		cout<<"HexaValue"<<in[i];
 
    }
 
}
unsigned char in[256];

void Text(const char *Buffer)
{
static char tempValue[256];

    for(int i=0;i<=len;i++)
    {
		
        	sprintf(&tempValue[i],"%02x", (unsigned char)Buffer[i]);
		in[i]=(unsigned char)tempValue[i];
		cout<<"HexaValue"<<in[i];
        
    }
	
}

this is not working as i wanted.
i want..

unsigned char in[] = {0x0044,ox0055,.....};

can anyone help me to correct this...

Last edited by Ancient Dragon; Apr 20th, 2008 at 11:49 am. Reason: add code tags

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Re: convert char to hexadecimal

Apr 20th, 2008

you can try something like this: But your tempValue buffer may not be large enough, depending on the length of the string. Should be at least string length * 7, maybe larger.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
char temp[16];
tempValue[0] = 0;
// put below in a loop for each character
sprintf(temp,"0x%04X, ", Buffer[i]);
strcat(tempValue, temp);
char temp[16];
tempValue[0] = 0;
// put below in a loop for each character
sprintf(temp,"0x%04X, ", Buffer[i]);
strcat(tempValue, temp);