How to start for this?

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Join Date: Apr 2008

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latour1972 latour1972 is offline

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How to start for this?

May 9th, 2008

Write two program segments (functions) that accomplish each of the following:
a) A function that Calculates the integer part of the quotient when integer a is divided by integer b.
b) A function that Calculates the integer remainder when integer a is divided by integer b.

Use the functions developed in (a) and (b) to write a function that inputs an integer between 1 and 32767 and prints it as a series of digits, each pair of which is separated by two spaces. For example, the integer 4562 should print as follows: 4 5 6 2

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Join Date: Dec 2005

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Salem

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void main'ers are DOOMed

Re: How to start for this?

May 9th, 2008

Do you know what quotient and remainder mean?

If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.

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Join Date: Dec 2007

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Re: How to start for this?

May 9th, 2008

they've actually given you the psuedocode for it, if it helps to get you started, just pick two numbers and do the math operation on paper and that will help you write your functions...make sure you use the correct operators indicated by the results the psuedocode asks for. Your instructor should have shown you how to do spaces in a cout statement for your spacing problem.

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latour1972 latour1972 is offline

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Re: How to start for this?

May 12th, 2008

I know quotient and remainder mean but I still cant figure that out.....

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Join Date: Apr 2008

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tesuji

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Re: How to start for this?

May 12th, 2008

Hi latour1972,

maybe these will help you:

 Help with Code Tags 
 cpp Syntax (Toggle Plain Text) 
// Two function to computing quotient and remainder
int quotient (int z ) { return z / 10; }
int reminder ( int z ) { return z % 10; }
 
// Simple solution to split int number into its digits
void demon ()
{  int n, d0, d1, d2, d3, d4;
   cout << "Enter an integer between 1 and 32767: ";
   cin >> n;
   cout << n << endl;
   d4 = reminder(n); n = quotient(n);
   d3 = reminder(n); n = quotient(n);
   d2 = reminder(n); n = quotient(n);
   d1 = reminder(n); d0= quotient(n);
   cout << d0 << "  " << d1 << "  " << d2 << "  " << d3 << "  " << d4 << endl;
}
 
 
//  Below solution works recursively. Do you understand this?
//  if you call split (4562), result is 4 5 6 2
void split(int n){
   int d = n % 10; n = n / 10;
   if ( n > 0) split (n);
   cout << d << "  ";
}
// Two function to computing quotient and remainder
int quotient (int z ) { return z / 10; }
int reminder ( int z ) { return z % 10; }

// Simple solution to split int number into its digits
void demon ()
{  int n, d0, d1, d2, d3, d4;
   cout << "Enter an integer between 1 and 32767: ";
   cin >> n;
   cout << n << endl;
   d4 = reminder(n); n = quotient(n);
   d3 = reminder(n); n = quotient(n);
   d2 = reminder(n); n = quotient(n);
   d1 = reminder(n); d0= quotient(n);
   cout << d0 << "  " << d1 << "  " << d2 << "  " << d3 << "  " << d4 << endl;
}


//  Below solution works recursively. Do you understand this?
//  if you call split (4562), result is 4 5 6 2
void split(int n){
   int d = n % 10; n = n / 10;
   if ( n > 0) split (n);
   cout << d << "  ";
}

krs,
tesu

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Join Date: Apr 2008

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Re: How to start for this?

May 13th, 2008

tks.....
I am working on this.....and it helps me to understand....

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Originally Posted by tesuji

Hi latour1972,

maybe these will help you:
Help with Code Tags

cpp Syntax (Toggle Plain Text)
// Two function to computing quotient and remainder
int quotient (int z ) { return z / 10; }
int reminder ( int z ) { return z % 10; }
 
// Simple solution to split int number into its digits
void demon ()
{  int n, d0, d1, d2, d3, d4;
   cout << "Enter an integer between 1 and 32767: ";
   cin >> n;
   cout << n << endl;
   d4 = reminder(n); n = quotient(n);
   d3 = reminder(n); n = quotient(n);
   d2 = reminder(n); n = quotient(n);
   d1 = reminder(n); d0= quotient(n);
   cout << d0 << "  " << d1 << "  " << d2 << "  " << d3 << "  " << d4 << endl;
}
 
 
//  Below solution works recursively. Do you understand this?
//  if you call split (4562), result is 4 5 6 2
void split(int n){
   int d = n % 10; n = n / 10;
   if ( n > 0) split (n);
   cout << d << "  ";
}
// Two function to computing quotient and remainder int quotient (int z ) { return z / 10; } int reminder ( int z ) { return z % 10; } // Simple solution to split int number into its digits void demon () { int n, d0, d1, d2, d3, d4; cout << "Enter an integer between 1 and 32767: "; cin >> n; cout << n << endl; d4 = reminder(n); n = quotient(n); d3 = reminder(n); n = quotient(n); d2 = reminder(n); n = quotient(n); d1 = reminder(n); d0= quotient(n); cout << d0 << " " << d1 << " " << d2 << " " << d3 << " " << d4 << endl; } // Below solution works recursively. Do you understand this? // if you call split (4562), result is 4 5 6 2 void split(int n){ int d = n % 10; n = n / 10; if ( n > 0) split (n); cout << d << " "; }
krs,
tesu