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Views: 133 | Replies: 5
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Join Date: May 2008
Posts: 16
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Newbie Poster
function is x/y+z means (x/y)+z
if you dont write to Z anything
program says "ERROR: Operator-operand imbalance."
program is that as it is above
and my code is
ERRORS--> error C2144: syntax error : missing ')' before type 'int'
error C2660: 'arith_ex' : function does not take 0 parameters
error C2059: syntax error : ')'
if you dont write to Z anything
program says "ERROR: Operator-operand imbalance."
program is that as it is above
and my code is
#include <iostream>
using namespace std;
class Calculator
{
int x,y,z;
public:
void arith_ex(int,int,int);
};
void Calculator::arith_ex(int x,int y,int z)
{
cout<<"X="<<endl;
cin>>x;
cout<<"Y="<<endl;
cin>>y;
cout<<"Z="<<endl;
cin>>z;
if(z==' ')
{cout<<"ERROR: Operator-operand imbalance."<<endl;
}
cout<<"Sonuc="<<x/y+z<<endl;
}
int main()
{
Calculator hesap;
hesap.arith_ex(int x,int y ,int z); //expected primary expression before 'int'//
return 0;
}ERRORS--> error C2144: syntax error : missing ')' before type 'int'
error C2660: 'arith_ex' : function does not take 0 parameters
error C2059: syntax error : ')'
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Join Date: Dec 2005
Posts: 3,058
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You don't specify the types when you call the function.
But you also have no x,y,z to pass to the function either.
hesap.arith_ex(x,y , z);
But you also have no x,y,z to pass to the function either.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
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Join Date: May 2006
Location: India
Posts: 247
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Solved Threads: 24
Posting Whiz in Training
You have declared variables x,y,z as members of the class and also as parameter values of the function
and call the function as
alternatively you can define the function without any arguments like
in this line
arith_ex
do something like this C++ Syntax (Toggle Plain Text)
C++ Syntax (Toggle Plain Text)
alternatively you can define the function without any arguments like
C++ Syntax (Toggle Plain Text)
in this line
hesap.arith_ex(int x,int y ,int z); x,y,z are undefined. Declare them earlier in the code and assign them some values. There are 10 types of people in the world, those who understand binary and those who don't.
All generalizations are wrong. Even this one.
All generalizations are wrong. Even this one.
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Join Date: May 2008
Posts: 16
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Newbie Poster
but i want to take numbers from user
how can i ?
how can i ?
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Join Date: Nov 2007
Posts: 770
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Master Poster
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Originally Posted by mertucci 
but i want to take numbers from user
how can i ?
You already correctly take all the input from the user by using cin, e.g. the following works
cin>>x;
But you cannot call a function like this:
hesap.arith_ex(int x,int y ,int z);
The above line actually generates all of the three errors you get.
You are not allowed to specify the types of the arguments you pass to a function when you make the function call. Instead you need to do it like:
// declare the variables you need to pass to the function int x = 0; int y = 0; int z = 0; // here you might also get the values from the user, using cin hesap.arith_ex(x, y, z); // now make the function call with the arguments
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