I wish to check if a variable (I am pulling the variable as mysql_fetch_array) contains the number 2008 in it. If so it is displayed.

Now I have the display working fine but it displays everything and I want to optimize it to just show the variables containing 2008.

Any ideas?

Thanks, Regards X.

Umm..
If the record in the table has more than 2008, for example, some text with it, you can try it this way.

I just solved it using stristr and then found your solution (never got notified of your message)whats the difference between the functions?

Thanks once again nav.

stristr does the same as strstr. But stristr is case-insensitive. ie., stristr("This is a test","IS"); will return true since "IS" is found in "This". Whereas, strstr("This is a test","IS"); will return false (since "IS" doesn't match with "is").

Cheers,
Nav

Ahh ok thanks nav, genious as usual

On to the next problem XD

If you get a chance to look at my double click problem (requires 2 clicks to be updated) I think that covers everything I require for this project XD

I read your post above with great interest. I have a phpBB forum and am the most beginning of beginners. I have what seems to me an easy question for someone beyond my "knowledge". I am trying to construct a simple if then else statement that I can wrtie that will test for the "is the user logged in " variable (which I don't know) - test for true or false and allow me to display a guest message.

This is so simple Im a little embarassed (lol) but I would appreciate some help.

Thanks,

This is the "bones" of what I'm trying to.
--------------------------------------------------------------
$logged = variable_name_that contains_login_value


<?php
if $logged = variable_name_that contains_login_value
display welcome/signup banner;
} else {
Do nothing;
}
?>
--------------------------------------------------------------

You should post your problem in a new thread but anyways.

Few minor things wrong with your code:


Hope that helps

Regards, X

Thanks for the reply it is much appreciated. My only remaining questions are:

1. Is the correct name of the variable $logged
2. What values do it contain or return

Thanks again

Umm.. There are some things you need to know before 'creating' a variable. A variable can't start with an integer. For example, $123variable is not a valid variable name. More about it here..
http://nl2.php.net/language.variables
And $logged will have the value that you assigned to it. For example,

Nav has answered your question.

If you still dont understand, cut out a section of your code and we will try to help you.