Problem in tryAgain function. Please Help!

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Problem in tryAgain function. Please Help!

 
0
  #1
Oct 18th, 2004
If you type in employee ID, and then a character (other than s, h or c) including the enter key. You get a message that says, "Do you want to try again or quit?" "Type q or Q to quit any other key to continue." If you hit any other key than q or Q, nothing happens.
I am trying to get the program to go to the else part of the function when another key than q or Q is hit, including the enter key. But I am out of ideas.
I hope someone out there can help. Any suggestions will be much appreciated. Thank you!

#include <iostream>
#include <iomanip>
using namespace std;
#include <cstdlib>
#include <string>

bool getEmployeeData (int*, char*, double*, double*, double*, double);
float calculateGrossPay (char, double, double, double);
void displayEmployeeInfo(int, char, double);
bool tryAgain(char*);
bool isValidStatus(char*);

int main()
{
int ID = 0;
double Salary = 0;
double hourwrk = 0;
double sales = 0;
double grossPay = 0;
char pyrllSt = ' ';
float totalPayroll = 0.0;
bool result = true;
while (result)
{
result = getEmployeeData (&ID, &pyrllSt, &Salary, &hourwrk, &sales, totalPayroll);
if (result)
{
grossPay = calculateGrossPay(pyrllSt, Salary, hourwrk, sales);
totalPayroll += grossPay;
displayEmployeeInfo (ID, pyrllSt, grossPay);
}
else
{
cout << "Total Payroll for this month: " << endl;
cout << fixed << showpoint << setprecision(2);
cout << "$" << totalPayroll << endl;
}
}
return (1);
}

bool getEmployeeData (int *ID, char *pyrllSt, double *Salary, double *hourwrk, double *sales, double totalPayroll)
{
cout << "Enter employee ID: " << endl;
cin >> *ID;

if (*ID > 0)
{
cout << "Enter payroll status: " << endl;
cin >> *pyrllSt;
if (isValidStatus(pyrllSt))
{
if (*pyrllSt == 's' || *pyrllSt == 'S')
{
cout << "Enter monthly salary" << endl;
cin >> *Salary;
}

if (*pyrllSt == 'h' || *pyrllSt == 'H')
{
cout << "Enter number of hours worked this month: " << endl;
cin >> *hourwrk;
}

if (*pyrllSt == 'c' || *pyrllSt == 'C')
{
cout << "Enter total sales for this month: " << endl;
cin >> *sales;
}
}//if isValid Status
return true;
}
else
{
return false;
}
}

bool isValidStatus (char *pyrllSt)
{
bool isGood = true;

while (isGood)
{

isGood = (*pyrllSt == 's' || *pyrllSt == 'S' || *pyrllSt =='h' || *pyrllSt == 'H' || *pyrllSt == 'c' || *pyrllSt =='C');

if (isGood)
{
return true;
}
else
{
isGood = tryAgain(pyrllSt);
}
}
return false;
}

bool tryAgain(char *pyrllSt)
{
char quit;

cout << "Type Q or q to quit, any other key to continue: " << endl;
cin >> quit;

if (quit == 'q' || quit == 'Q')
{
cout << "*** Program Terminated ***" << endl;
return false;
}
else
{
cout << "Re-enter: 's' or 'S' for salaried, 'h' or 'H' for hourly, " << endl;
cout << "'c' or 'C' for commissioned." << endl;
cin >> *pyrllSt;
return true;
}
}

float calculateGrossPay (char pyrllSt, double Salary, double hourwrk, double sales)
{
float grossPay;
if (pyrllSt == 's' || pyrllSt == 'S')
{
grossPay = Salary;
}

if (pyrllSt == 'h' || pyrllSt == 'H')
{
grossPay = hourwrk * 18.75;
}

if (pyrllSt == 'c' || pyrllSt == 'C')
{
grossPay = sales * 0.06 + 1000.00;
}
return grossPay;

}

void displayEmployeeInfo (int ID, char pyrllSt, double grossPay)
{
cout << "Employee ID: " << ID << endl;
cout << "Payroll Status: " << pyrllSt << endl;
cout << "Gross Pay: " << fixed << showpoint << setprecision(2);
cout << "$" << grossPay << endl;
}
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Re: Problem in tryAgain function. Please Help!

 
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  #2
Oct 18th, 2004
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
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