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error: initial value of reference to non-const must be an lvalue
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Join Date: Feb 2008
Posts: 628
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Practically a Master Poster
I have a function Scan.MakeLinearGrid() which returns a vector<vector<Vector3> >
I have another function that is made to accept this type of thing:
Scan.setAngleList(vector<vector<Vector3> >);
But if I call it like this:
it says
but if i do
it works fine.
Can someone explain the difference?
Thanks,
Dave
I have another function that is made to accept this type of thing:
Scan.setAngleList(vector<vector<Vector3> >);
But if I call it like this:
C++ Syntax (Toggle Plain Text)
C++ Syntax (Toggle Plain Text)
but if i do
C++ Syntax (Toggle Plain Text)
it works fine.
Can someone explain the difference?
Thanks,
Dave
Your Vector3 is missing the appropriate copy constructor.
A good rule of thumb is if you use any one of copy constructor, assignment operator, or virtual destructor, then you need all three. (Not always, but usually.)
Hope this helps.
A good rule of thumb is if you use any one of copy constructor, assignment operator, or virtual destructor, then you need all three. (Not always, but usually.)
Hope this helps.
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Join Date: Feb 2008
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Practically a Master Poster
I have neither an assignment operator or virtual destructor, so then why do i need a copy constructor?
Can you give a simple example of each of those?
Can you give a simple example of each of those?
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Join Date: May 2008
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Posting Whiz
What does setAngleList do? When you say
Scan.setAngleList(Scan.MakeLinearGrid()); it passes a temporary object to the method. If setAngleList doesn't modify the object, you should make it a const reference anyway because that's both safer and more flexible in what you can pass. If setAngleList does modify the object, you shouldn't be passing a temporary at all, this call has a logical error that's luckily being caught by the compiler, and the working example you gave is the way to fix the error. If at first you don't succeed, keep on sucking until you do succeed.
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