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need help with ASCII
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I am just starting to learn C++ with the Waite group primer. I wrote a program loosely based on the books instructions to display any entered ASCII character and its numeric value and the same for the next character in the table.
Heres the bug: The second character works fine, but the first always and without fail comes out as -52 which is impossible. Here is the code:
Thanks in advance.
Heres the bug: The second character works fine, but the first always and without fail comes out as -52 which is impossible. Here is the code:
C++ Syntax (Toggle Plain Text)
Thanks in advance.
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Join Date: Apr 2008
Posts: 296
Reputation: 
Solved Threads: 42
Posting Whiz in Training
Hi
Your code:
char ch;
int i = ch;
You didn't assign a value to ch. So i is undefined. Also this would not work if you do cin >> ch.
You may try this instead:
char xxx = 'x';
cout << "char: " << xxx << " as int: " << (int) xxx << endl;
cout << "next char: " << ++xxx << " as next int: " << (int) xxx << endl;
If you know pointers, there would also be a solution.
crs,
tesu
Your code:
char ch;
int i = ch;
You didn't assign a value to ch. So i is undefined. Also this would not work if you do cin >> ch.
You may try this instead:
char xxx = 'x';
cout << "char: " << xxx << " as int: " << (int) xxx << endl;
cout << "next char: " << ++xxx << " as next int: " << (int) xxx << endl;
If you know pointers, there would also be a solution.
crs,
tesu
The first time you print 'i', it has the initial unknown value it got from 'ch'.
If you add the green and red lines below, you'll probably get the idea ...
If you add the green and red lines below, you'll probably get the idea ...
// morechar.cpp -- char and int types contrasted
#include <iostream>
int main()
{
using namespace std;
char ch; //declare a variable ch
// ch is not initialized to any known value ...
cout << "uninitialized ch is: " << ch << endl;
int i = ch; // stores same code in an int
cout << "i, being assigned the uninitialized value of ch, is: " << i << endl;
cout << "Enter any ASCII character:\n";
cin >> ch;
// align i with ch ...
i = ch;
cout << " The ASCII code for " << ch << " is " << i << endl;
cout << "Adding one to the character code takes you to the next character.\n";
ch = ch + 1; //change the character code in ch
i = ch;
cout << "The ASCII code for " << ch << " is " << i << endl;
//using the cout.put member function to display a char
cout << "Displaying char ch using cout.put(ch): ";
cout.put(ch);
//using cout.put() to display a char constant
cout.put('!');
cout << endl << "done." << endl;
return 0;
} •
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Join Date: Apr 2008
Posts: 296
Reputation:
Solved Threads: 42
Posting Whiz in Training
instead of: int i = ch; // stores same code in an int (wrongly)
you might try: int*i =(int*)ch;
then
cin>>ch; // enter A for example
cout << ch; // gives A
cout << i; // gives 0x41
cout << (int)i; // gives 65
krs,
tesu
you might try: int*i =(int*)ch;
then
cin>>ch; // enter A for example
cout << ch; // gives A
cout << i; // gives 0x41
cout << (int)i; // gives 65
krs,
tesu
Thanks people. I had something along the lines of mitrmkar's thing before I checked, but I still don't get the -52 stuff
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Originally Posted by NervousWreck 
Thanks people. I had something along the lines of mitrmkar's thing before I checked, but I still don't get the -52 stuff
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