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Views: 755 | Replies: 10 | Solved
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Join Date: Nov 2007
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Junior Poster
hi,
does anyone know how to check if certain character is contained in the argument?
for example: > foo /home/myname
how should I check if the argument contains a "/" character?
thanks
does anyone know how to check if certain character is contained in the argument?
for example: > foo /home/myname
how should I check if the argument contains a "/" character?
thanks
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Join Date: Jan 2007
Location: Ireland
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just use "basename"
Real stupidity always beats Artificial Intelligence. (Terry Pratchett)
BA BizMg, MCSE, DCSE, Linux+, Network+
BA BizMg, MCSE, DCSE, Linux+, Network+
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Join Date: Oct 2007
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Posting Whiz in Training
Hey There,
You can use expr's colon (
notation for string comparison, but it might be easier to read and write to do something with grep, like:
echo $1|grep "/" >/dev/null 2>&1
(use -q for Gnu grep and you can avoid the output redirection).
then check errno ($?). If it equals 0, your string has a "/" in it.
Hope that helps,
Mike
You can use expr's colon (
notation for string comparison, but it might be easier to read and write to do something with grep, like:echo $1|grep "/" >/dev/null 2>&1
(use -q for Gnu grep and you can avoid the output redirection).
then check errno ($?). If it equals 0, your string has a "/" in it.
Hope that helps,
Mike
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Join Date: Nov 2007
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Junior Poster
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Originally Posted by eggi 
Hey There,
You can use expr's colon (
echo $1|grep "/" >/dev/null 2>&1
(use -q for Gnu grep and you can avoid the output redirection).
then check errno ($?). If it equals 0, your string has a "/" in it.
Hope that helps,
Mike
thanks, and it definitely helps. I actually figured that out after a while. I have another question if anyone helps out, it would be so great.
say file=/home/admin/foo
and i want to delete the foo and leave file=/home/admin how do i do that?
i tried:
echo $file | tr '/' ' ' | sed 's/ *$//' | tr ' ' '/' #it deleted everything.. : (
can anyone tell how do i delete something in between? all the reference I read only tell the usage of ^ and $ Thanks
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Join Date: Jan 2007
Location: Ireland
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first idea is to use "cut" with '/' as delimeter
Real stupidity always beats Artificial Intelligence. (Terry Pratchett)
BA BizMg, MCSE, DCSE, Linux+, Network+
BA BizMg, MCSE, DCSE, Linux+, Network+
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Join Date: Nov 2007
Posts: 107
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Junior Poster
cut works if I know the exact input path="/home/admin/foo"
but if path is an argument.... then it won't know cut -f what field.
what i need is ...
path="$1"
and if $1 is a directory... say like path="/home/admin/foo"
then i need to remove the file foo from the dir and leave path="/home/admin"
......
but if path is an argument.... then it won't know cut -f what field.
what i need is ...
path="$1"
and if $1 is a directory... say like path="/home/admin/foo"
then i need to remove the file foo from the dir and leave path="/home/admin"
......
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Join Date: Oct 2007
Posts: 267
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Posting Whiz in Training
Hey THere,
Your initial shot was pretty close. Just change:
to
and that should do it
Best wishes,
Mike
Your initial shot was pretty close. Just change:
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file=/home/admin/foo
echo $file | tr '/' ' ' | sed 's/ *$//' | tr ' ' '/'
to
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file=/home/admin/foo
echo $file |sed 's/^.*\/\(.*\)$/\1/'
and that should do it
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-bash-3.2$ echo $file |sed 's/^.*\/\(.*\)$/\1/'
foo
Best wishes,
Mike
Linux and Unix Tips, Tricks and Individual Advice - The Linux and Unix Menagerie!
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Having trouble passing cert exams? Check out How To Pass Any Computer Certification Test!
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Join Date: Nov 2007
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Junior Poster
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Originally Posted by eggi
Hey THere,
Your initial shot was pretty close. Just change:
to
and that should do it
Best wishes,
Mike
Mike,
wow... you are genius! That is really helpful and I had never thought about using the saving to register.
However, i need the dir part of the $path but the last file.
$path=/home/admin/foo
result: $path=/home/admin
thanks for the big hint though, i tried to save the same first part into register 1 and the second part into register 2....... but it returns the whole path...(dont' know ) if possible please fix it.. if i get my result..i'll post it here too
my attempt:
echo $path | sed 's/\(^.*\/\):\(.*\)$/\1/'
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Join Date: Nov 2007
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Junior Poster
hey all,
just to echo myself.... instead of banging my head for solution of the sed and tr wutever.. it could be done by just :
path=/home/admin/foo
dirname /home/admin/foo
thanks for everyone tried to help.....
just to echo myself.... instead of banging my head for solution of the sed and tr wutever.. it could be done by just :
path=/home/admin/foo
dirname /home/admin/foo
thanks for everyone tried to help.....
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Join Date: Oct 2007
Posts: 267
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Posting Whiz in Training
Hey,
I know this is closed, but wanted to follow up since I missed you last time
Sorry
To get the basename, with sed, just so you have it for your stockpile, just change your expression:
to
Of course, you're right, basename and dirname are much simpler to use
Cheers,
Mike
I know this is closed, but wanted to follow up since I missed you last time
SorryTo get the basename, with sed, just so you have it for your stockpile, just change your expression:
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echo $path | sed 's/\(^.*\/\):\(.*\)$/\1/'
to
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echo $path | sed 's/^\(.*\)\/.*$/\1/'
/home/admin
Of course, you're right, basename and dirname are much simpler to use
Cheers,
Mike
Last edited by eggi : Jul 1st, 2008 at 12:09 am.
Linux and Unix Tips, Tricks and Individual Advice - The Linux and Unix Menagerie!
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Having trouble passing cert exams? Check out How To Pass Any Computer Certification Test!
------------------------------------------------------------------------
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