Originally Posted by niek_e

What is the error-message? What compiler are you using?
This compiles fine on VS2008 with warninglevel 4.
And why do you want to use const ints?

Originally Posted by ivailosp

try

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cpp Syntax (Toggle Plain Text)

#include <vector>
 
int main() {
	std::vector<const int> v();
	return 0;
}

#include <vector> int main() { std::vector<const int> v(); return 0; }

Originally Posted by vijayan121

concept: the value_type of a standard container (the type of the object stored in the container) is required to be Assignable http://www.sgi.com/tech/stl/Assignable.html
a const T ( or for that matter a T& ) is not Assignable and cannot be the value_type in a standard container.

Originally Posted by vijayan121

for a standard container, begin() and end() are overloaded on the const specifier.
on a modifiable container, begin() and end() return container::iterator.
on a const container, begin() and end() returns container::const_iterator.

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template< typename CNTR > // CNTR is a standard container
void foo( CNTR& cntr, const CNTR& const_cntr )
{
  typename CNTR::iterator iter = cntr.begin() ;
  typename CNTR::const_iterator const_iter = const_cntr.begin() ;
  typename CNTR::reverse_iterator rev_iter = cntr.rbegin() ;
  typename CNTR::const_reverse_iterator const_rev_iter = const_cntr.rbegin() ;
}

template< typename CNTR > // CNTR is a standard container void foo( CNTR& cntr, const CNTR& const_cntr ) { typename CNTR::iterator iter = cntr.begin() ; typename CNTR::const_iterator const_iter = const_cntr.begin() ; typename CNTR::reverse_iterator rev_iter = cntr.rbegin() ; typename CNTR::const_reverse_iterator const_rev_iter = const_cntr.rbegin() ; }

this code will not compile:

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C++ Syntax (Toggle Plain Text)

#include <vector>
 
void f( std::vector<int>::const_iterator& i )
{ std::cout << *i << std::endl; }
 
int main()
{
  std::vector<int> v;
  std::vector<int>::iterator b = v.begin() ;
  f(b);
}

#include <vector> void f( std::vector<int>::const_iterator& i ) { std::cout << *i << std::endl; } int main() { std::vector<int> v; std::vector<int>::iterator b = v.begin() ; f(b); }

but this will:

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template< typename ITERATOR > void f( ITERATOR i )
{  std::cout << *i << std::endl; }
 
#include <vector>
 
int main()
{
  std::vector<int> v;
  std::vector<int>::iterator b = v.begin() ;
  f(b);
}

template< typename ITERATOR > void f( ITERATOR i ) { std::cout << *i << std::endl; } #include <vector> int main() { std::vector<int> v; std::vector<int>::iterator b = v.begin() ; f(b); }

c++09: containers also have:

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// ...
  const_iterator cbegin() const;
  const_iterator cend () const;
  const_reverse_iterator crbegin() const;
  const_reverse_iterator crend () const;
// ...

// ... const_iterator cbegin() const; const_iterator cend () const; const_reverse_iterator crbegin() const; const_reverse_iterator crend () const; // ...

http://www.open-std.org/jtc1/sc22/wg...2004/n1674.pdf
so things become a bit more convenient.

note: prefer passing an iterator by value (rather than by modifiable reference);
it is more flexible for iterations to be non-intrusive.