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Views: 13494 | Replies: 49
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Join Date: Oct 2004
Posts: 47
Reputation: 
Rep Power: 4
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Light Poster
hi guys......
i have a problem in writing a program of "how to delete the duplicate elements in an array"
for example....if i enter an array like:
10 20 30 40 30
then it should print:
10 20 30 40
so could plz help me out????? :cry:
i have attempted little though....but don't know how can i go ahead....
#include<stdio.h>
#include<conio.h>
int main(void)
{
int a[5],i,j;
clrscr();
printf("ENTER ARRAY ELEMENTS:");
for(i=0;i<5;i++)
scanf("%d",&a[i]);
fflush(stdin);
for(i=0;i<5;i++)
{
for(j=i;j<4;j++)
{
//i don't know now where do i go....from here on.....how to find the element which is repeating that is the duplicate and then how to delete that.....
so plz help me out......
i have a problem in writing a program of "how to delete the duplicate elements in an array"
for example....if i enter an array like:
10 20 30 40 30
then it should print:
10 20 30 40
so could plz help me out????? :cry:
i have attempted little though....but don't know how can i go ahead....
#include<stdio.h>
#include<conio.h>
int main(void)
{
int a[5],i,j;
clrscr();
printf("ENTER ARRAY ELEMENTS:");
for(i=0;i<5;i++)
scanf("%d",&a[i]);
fflush(stdin);
for(i=0;i<5;i++)
{
for(j=i;j<4;j++)
{
//i don't know now where do i go....from here on.....how to find the element which is repeating that is the duplicate and then how to delete that.....
so plz help me out......
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Join Date: Oct 2004
Posts: 47
Reputation:
Rep Power: 4
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Light Poster
could any 1 reply plz............
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Join Date: Sep 2004
Posts: 6,325
Reputation: 
Rep Power: 28
Solved Threads: 458
>could any 1 reply plz............
I was going to help you, until I saw that you bumped your thread before 30 minutes had passed. That's incredibly rude.
Try this: [Useful suggestion removed because you don't deserve it. Figure the solution out on your own]
I was going to help you, until I saw that you bumped your thread before 30 minutes had passed. That's incredibly rude.
Try this: [Useful suggestion removed because you don't deserve it. Figure the solution out on your own]
I'm a programmer. My attitude starts with arrogance, holds steady at condescension, and ends with hostility. Get used to it.
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Join Date: Oct 2004
Posts: 47
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Light Poster
im really sorry but im new to this site so don't know how exactly it works...but anyways.....i don't know how to go from here on.....i did'nt understand what exactly were u trying to say......
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Join Date: Oct 2004
Posts: 47
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Light Poster
i have been online here for 2 hrs..almost and didn't get any reply from any1/../so i was checking on some other threads of this site....as im new to this site...so plz don't take it otherwise...and help me out.......plz with this problem......
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Join Date: Dec 2003
Location: Nashville, TN
Posts: 2,333
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Originally Posted by galmca
i have been online here for 2 hrs..almost and didn't get any reply from any1/../so i was checking on some other threads of this site....as im new to this site...so plz don't take it otherwise...and help me out.......plz with this problem......
2 hours?!?!? You've not gotten an answer in 2 hours, and you're complaining?!?!?
Come on now. We're doing this for free-- you have no right to complain even if we don't answer in 2 days! Please be more mindful in the future. If nobody answers your question promptly, it's likely because we don't have the answer, or the right person has not yet visited the site.
Please be more considerate of other forum members, and don't bump your post in the same day you posted.
Alex Cavnar, aka alc6379
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Join Date: Sep 2004
Posts: 6,325
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Solved Threads: 458
>it's likely because we don't have the answer, or the right person has not yet visited the site.
Or the first person who wanted to help was too insulted and deleted the meat of her post.
Anyway, it's best to just ignore people like galmca. They go away after a short time and leave us in peace.
Or the first person who wanted to help was too insulted and deleted the meat of her post.
Anyway, it's best to just ignore people like galmca. They go away after a short time and leave us in peace. I'm a programmer. My attitude starts with arrogance, holds steady at condescension, and ends with hostility. Get used to it.
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Join Date: Jun 2004
Location: Marin, CA, USA
Posts: 434
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Unprevaricator
So you want to see if any of a[]'s values duplicate any OTHER of a[]'s values?
You've got a start there with the two loops, so how about something like:
for each element (that's a[i] in the first loop, say)
look through every OTHER element in the array to see if it matches; in your code fragment that would be the 'for j' loop. Something like (and I am paraphrasing, not writing compilable code here):
for i 0..5
for j 0..5
if i is not j, then if a[i] equals a[j] you have a match between the elements at i and j!
The next part is to figure out how to remove that duplicate. One simple approach is to copy the non-dups down over the dup (so if 3 is the dup, set [3] = [4] and [4] = [5]). Another approach is to have a separate array of non-duplicate values, like this:
(from the above loops, just below the close of the for j loop)
if not a duplicate, then copy a[i] over to nonDuplicates[countOfNonDuplicates] and increment the countOfNonDuplicates.
You've got a start there with the two loops, so how about something like:
for each element (that's a[i] in the first loop, say)
look through every OTHER element in the array to see if it matches; in your code fragment that would be the 'for j' loop. Something like (and I am paraphrasing, not writing compilable code here):
for i 0..5
for j 0..5
if i is not j, then if a[i] equals a[j] you have a match between the elements at i and j!
The next part is to figure out how to remove that duplicate. One simple approach is to copy the non-dups down over the dup (so if 3 is the dup, set [3] = [4] and [4] = [5]). Another approach is to have a separate array of non-duplicate values, like this:
(from the above loops, just below the close of the for j loop)
if not a duplicate, then copy a[i] over to nonDuplicates[countOfNonDuplicates] and increment the countOfNonDuplicates.
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Join Date: Oct 2004
Posts: 47
Reputation:
Rep Power: 4
Solved Threads: 0
Light Poster
hi guys......
i have a problem in writing a program of "how to delete the duplicate elements in an array"
for example....if i enter an array like:
10 20 30 40 30
then it should print:
10 20 30 40
so could plz help me out?????
i have attempted little though....but don't know how can i go ahead....
#include<stdio.h>
#include<conio.h>
int main(void)
{
int a[5],i,j;
clrscr();
printf("ENTER ARRAY ELEMENTS:");
for(i=0;i<5;i++)
scanf("%d",&a[i]);
fflush(stdin);
for(i=0;i<5;i++)
{
for(j=i;j<4;j++)
{
//i don't know now where do i go....from here on.....how to find the element which is repeating that is the duplicate and then how to delete that.....
so plz help me out......
i have a problem in writing a program of "how to delete the duplicate elements in an array"
for example....if i enter an array like:
10 20 30 40 30
then it should print:
10 20 30 40
so could plz help me out?????
i have attempted little though....but don't know how can i go ahead....
#include<stdio.h>
#include<conio.h>
int main(void)
{
int a[5],i,j;
clrscr();
printf("ENTER ARRAY ELEMENTS:");
for(i=0;i<5;i++)
scanf("%d",&a[i]);
fflush(stdin);
for(i=0;i<5;i++)
{
for(j=i;j<4;j++)
{
//i don't know now where do i go....from here on.....how to find the element which is repeating that is the duplicate and then how to delete that.....
so plz help me out......
•
•
Join Date: Oct 2004
Posts: 47
Reputation:
Rep Power: 4
Solved Threads: 0
Light Poster
for finding out the duplicates here...first...i have done like :
for(i=0;i<5;i++)
{
for(j=0;j<5;j++)
{
if(a[i]==a[j])
printf("duplicate element exists:");
else
printf("duplicate elements does not exist:");
}
}
but when i run this it doesnot run properly and gives some weird output....so what do i do now?
for(i=0;i<5;i++)
{
for(j=0;j<5;j++)
{
if(a[i]==a[j])
printf("duplicate element exists:");
else
printf("duplicate elements does not exist:");
}
}
but when i run this it doesnot run properly and gives some weird output....so what do i do now?
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