Java

Java RSS

JAVA: code for menu selection using Scanner class

•

Join Date: Nov 2004

Posts: 7

Reputation: Maria5683 is an unknown quantity at this point

Solved Threads: 0

Maria5683

Offline

Newbie Poster

JAVA: code for menu selection using Scanner class

Nov 9th, 2004

How do you write the code using Scanner class to set up a menu (i.e 1 for something, 2 for something, and so on.) Then have the user to choose.

Thanks

•

Join Date: Sep 2004

Posts: 7,603

Reputation: Narue has a reputation beyond repute

Solved Threads: 713

Narue

Offline

Code Goddess

Re: JAVA: code for menu selection using Scanner class

Nov 9th, 2004

Something along these lines:

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
import java.util.*;
 
class Main {
  public void display_menu() {
    System.out.println ( "1) Option 1\n2) Option 2\n3) Option 3" );
    System.out.print ( "Selection: " );
  }
 
  public Main() {
    Scanner in = new Scanner ( System.in );
 
    display_menu();
    switch ( in.nextInt() ) {
      case 1:
        System.out.println ( "You picked option 1" );
        break;
      case 2:
        System.out.println ( "You picked option 2" );
        break;
      case 3:
        System.out.println ( "You picked option 3" );
        break;
      default:
        System.err.println ( "Unrecognized option" );
        break;
    }
  }
 
  public static void main ( String[] args ) {
    new Main();
  }
}
import java.util.*;

class Main {
  public void display_menu() {
    System.out.println ( "1) Option 1\n2) Option 2\n3) Option 3" );
    System.out.print ( "Selection: " );
  }
  
  public Main() {
    Scanner in = new Scanner ( System.in );
    
    display_menu();
    switch ( in.nextInt() ) {
      case 1:
        System.out.println ( "You picked option 1" );
        break;
      case 2:
        System.out.println ( "You picked option 2" );
        break;
      case 3:
        System.out.println ( "You picked option 3" );
        break;
      default:
        System.err.println ( "Unrecognized option" );
        break;
    }
  }
  
  public static void main ( String[] args ) {
    new Main();
  }
}

I'm here to prove you wrong.

•

Join Date: Nov 2004

Posts: 7

Reputation: Maria5683 is an unknown quantity at this point

Solved Threads: 0

Maria5683

Offline

Newbie Poster

Re: JAVA: code for menu selection using Scanner class

Nov 10th, 2004

Thank you. This help out a lot!

•

Join Date: Oct 2009

Posts: 2

Reputation: vgi is an unknown quantity at this point

Solved Threads: 0

vgi

Offline

Newbie Poster

Oct 19th, 2009

How do you write the code that allows you to go back to the menu after choosing an option?

•

Join Date: Jul 2009

Posts: 48

Reputation: sneaker is an unknown quantity at this point

Solved Threads: 7

sneaker

Offline

Light Poster

Oct 19th, 2009

•

Originally Posted by vgi

How do you write the code that allows you to go back to the menu after choosing an option?

Hi

You can make it simple an add a new method like in this example below that is based on the class above. I have chanced the name of the class because I personally do not think that classes should be named as Main.

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
import java.util.*;
 
public class InputMenu 
{
    public void display_menu() 
    {
	System.out.println("1) Option 1\n2) Option 2\n3) Option 3");
	System.out.print("Selection: ");
    }
 
    public void question()
    {
	System.out.println("Would you like to proceed or quit?");
	System.out.println("To proceed enter 9.");
	System.out.println("If you wish to quit enter 0.");
 
	Scanner q = new Scanner(System.in);
 
	switch (q.nextInt()) 
	{
	    case 0:
	    System.out.println ("Thank you and godbye.");
	    break;
 
	    case 9:
	    System.out.println ("Please proceed.");
	    new InputMenu();
	    break;
 
	    default:
	    System.err.println ( "Unrecognized option" );
	    break;
	}
    }
 
    public InputMenu() 
    {
	Scanner in = new Scanner(System.in);
        display_menu();
 
	switch (in.nextInt()) 
	{
	    case 1:
	    System.out.println ( "You picked option 1" );
	    question();
	    break;
 
	    case 2:
	    System.out.println ( "You picked option 2" );
	    question();
	    break;
 
	    case 3:
	    System.out.println ( "You picked option 3" );
	    question();
	    break;
 
	    default:
	    System.err.println ( "Unrecognized option" );
	    break;
	}
    }
 
    public static void main (String[]args) 
    {
	new InputMenu();
    }
}
import java.util.*;

public class InputMenu 
{
    public void display_menu() 
    {
	System.out.println("1) Option 1\n2) Option 2\n3) Option 3");
	System.out.print("Selection: ");
    }
    
    public void question()
    {
	System.out.println("Would you like to proceed or quit?");
	System.out.println("To proceed enter 9.");
	System.out.println("If you wish to quit enter 0.");

	Scanner q = new Scanner(System.in);
       
	switch (q.nextInt()) 
	{
	    case 0:
	    System.out.println ("Thank you and godbye.");
	    break;
  
	    case 9:
	    System.out.println ("Please proceed.");
	    new InputMenu();
	    break;

	    default:
	    System.err.println ( "Unrecognized option" );
	    break;
	}
    }
 
    public InputMenu() 
    {
	Scanner in = new Scanner(System.in);
        display_menu();
  
	switch (in.nextInt()) 
	{
	    case 1:
	    System.out.println ( "You picked option 1" );
	    question();
	    break;
  
	    case 2:
	    System.out.println ( "You picked option 2" );
	    question();
	    break;
  
	    case 3:
	    System.out.println ( "You picked option 3" );
	    question();
	    break;

	    default:
	    System.err.println ( "Unrecognized option" );
	    break;
	}
    }
 
    public static void main (String[]args) 
    {
	new InputMenu();
    }
}

As you see a new method question() is added and this method is called from all cases in the switch() (inside InputMenu() ) except the default case.

Hope this gave you an idea of how it works