>I am confused about where it will be getting files from?
The program will be executed like this:

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$ mycat file1 file2 file3

$ mycat file1 file2 file3

For the purposes of your assignment, you can assume the following for argc and argv of main:

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argc = 4;
argv[0] = "mycat";
argv[1] = "file1";
argv[2] = "file2";
argv[3] = "file3";

argc = 4; argv[0] = "mycat"; argv[1] = "file1"; argv[2] = "file2"; argv[3] = "file3";

To test this out, use the following program:

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#include <stdio.h>
 
int main ( int argc, char *argv[] )
{
  int i;
 
  printf ( "argc = %d\n", argc );
  for ( i = 0; i < argc; i++ )
    printf ( "argv[%d] = %s\n", i, argv[i] );
 
  return 0;
}

#include <stdio.h> int main ( int argc, char *argv[] ) { int i; printf ( "argc = %d\n", argc ); for ( i = 0; i < argc; i++ ) printf ( "argv[%d] = %s\n", i, argv[i] ); return 0; }

That's how you access command line arguments. Converting the above loop to open the files in sequence and either print the contents of the file to stdout or move on to the next file if it fails to open is fairly trivial if you know how to open a file and read from it.