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Join Date: Sep 2008

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unk45

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address book

Oct 3rd, 2008

im supposed to create an address book and so far have gone as far as getting the input..my problem now is the highlighted section..i have to return bak the info put in initially by the user (first, last name and address), based upon a question to the user to input either the last name or the first and last name of the persons he wants to pull up. would appreciate some help
thnx

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#include <iostream>

const int maxpeople = 50;

struct person
{
	char firstname[20];

	char lastname[20];

	char address[20];
};

void addpeople(person holdspeople[], int size);

void getperson(person holdspeople[maxpeople], int size, int stringsize);

using namespace std;

person people[10];

int main()
{
	addpeople(people, 10);

	getperson(people, 10, 20);

	return 0;
}

void addpeople(person holdspeople[maxpeople], int size)
{
	for(int i = 0;i < size; i++)
	{

		cout<<"Enter your first name, last name and address respectively"<<endl;
	
		cin>>holdspeople[i].firstname>>holdspeople[i].lastname>>holdspeople[i].address;
	
	}
}


void getperson(person holdspeople[maxpeople], int size, int stringsize)
{	
		char firstname[20];

		char lastname[20];

	for (int i = 0; i < stringsize; i++)
    {
		firstname[i] = holdspeople[i].firstname;
		
		lastname[i] = holdspeople[i].lastname;
    }
}

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Ancient Dragon Ancient Dragon is offline

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Re: address book

Oct 3rd, 2008

Since you have the coice of entering either last name, or first and last name, you will probably have to ask for which they want to enter then create an if condition
Example:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
...
int type;
char firstname[20] = {0};
char lastname[20] = {0};
 
cout << "Enter 1) Last Name\n2) First Name and Last Name\n";
cin >> type;
if( type == 1)
{
    // last name only
    cout << "Enter Last Name\n";
    cin >> lastname;
    // now search the array for last name only
}
else if( type == 2)
{
    cout << "Enter First Name\n";
    cin >> firstname;
    cout << "Enter Last Name\n";
    cin >> lastname;
   // now search the array for both first name and last name
}
else
{
    // display error message
}
...
int type;
char firstname[20] = {0};
char lastname[20] = {0};

cout << "Enter 1) Last Name\n2) First Name and Last Name\n";
cin >> type;
if( type == 1)
{
    // last name only
    cout << "Enter Last Name\n";
    cin >> lastname;
    // now search the array for last name only
}
else if( type == 2)
{
    cout << "Enter First Name\n";
    cin >> firstname;
    cout << "Enter Last Name\n";
    cin >> lastname;
   // now search the array for both first name and last name
}
else
{
    // display error message
}

Don't PM me with questions -- you might get a nasty PM in response. If you have a question then post it in one of the forums.

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unk45

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Re: address book

Oct 3rd, 2008

ok so i worked on it but its not exactly coming out like i hoped.

my loop is off and i cant see why, and im getting weird signs. the thing is im supposed to keep asking the user if he wants to find the initial input info, based on an input off person's last name or first name and last name until he decides to exit.
plz help...
thnx

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
 
const int maxpeople = 50;
 
struct person
{
	char firstname[20];
 
	char lastname[20];
 
	char address[20];
};
 
void addpeople(person people[], int size);
 
void getperson(person people[maxpeople], int size);
 
using namespace std;
 
person people[10];
 
int main()
{
	addpeople(people, 10);
 
	while(true)
	{
 
	getperson(people, 10);
 
	}
 
	return 0;
}
 
void addpeople(person people[maxpeople], int size)
{
	for(int i = 0;i < size; i++)
	{
 
		cout<<"Enter your first name, last name and address respectively"<<endl;
 
		cin>>people[i].firstname>>people[i].lastname>>people[i].address;
 
	}
}
 
 
void getperson(person people[maxpeople], int size)
{	
	char type;
 
	char firstname[20] = {0};
 
	char lastname[20] = {0};
 
	while(true)
	{
	cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
	cin >> type;
 
	if( type == '1')
	{
 
		cout << "Enter Last Name\n";
		cin >> lastname;
 
			for(int i = 0; ;i++)
			{
 
			if(people[i].lastname == lastname)
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}
 
			}
	}
 
	else if( type == '2')
	{
		cout << "Enter First Name\n";
		cin >> firstname;
		cout << "Enter Last Name\n";
		cin >> lastname;
 
		for(int i = 0; ;i++)
		{
 
			if(people[i].lastname == lastname && people[i].firstname == firstname )
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}
 
 
		}
 
	}
 
	else if(type == '1' && type == '2')
	{
		while (type == 1 && type == 2)
		{
		cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
		cin >> type;
		}
	}
 
	else if{type = 'exit')
		break;
 
	}
 
}
#include <iostream>

const int maxpeople = 50;

struct person
{
	char firstname[20];

	char lastname[20];

	char address[20];
};

void addpeople(person people[], int size);

void getperson(person people[maxpeople], int size);

using namespace std;

person people[10];

int main()
{
	addpeople(people, 10);

	while(true)
	{
	
	getperson(people, 10);

	}

	return 0;
}

void addpeople(person people[maxpeople], int size)
{
	for(int i = 0;i < size; i++)
	{

		cout<<"Enter your first name, last name and address respectively"<<endl;

		cin>>people[i].firstname>>people[i].lastname>>people[i].address;

	}
}


void getperson(person people[maxpeople], int size)
{	
	char type;
	
	char firstname[20] = {0};
	
	char lastname[20] = {0};

	while(true)
	{
	cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
	cin >> type;
	
	if( type == '1')
	{
		
		cout << "Enter Last Name\n";
		cin >> lastname;
		
			for(int i = 0; ;i++)
			{

			if(people[i].lastname == lastname)
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}
	
			}
	}
	
	else if( type == '2')
	{
		cout << "Enter First Name\n";
		cin >> firstname;
		cout << "Enter Last Name\n";
		cin >> lastname;
		
		for(int i = 0; ;i++)
		{
		
			if(people[i].lastname == lastname && people[i].firstname == firstname )
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}

	
		}

	}
	
	else if(type == '1' && type == '2')
	{
		while (type == 1 && type == 2)
		{
		cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
		cin >> type;
		}
	}

	else if{type = 'exit')
		break;

	}

}

Last edited by unk45; Oct 3rd, 2008 at 2:28 pm.

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Join Date: Sep 2008

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Sci@phy

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Posting Whiz in Training

Re: address book

Oct 3rd, 2008

else if{type = 'exit')

First, there's some syntax error, but that's different story.
type is char variable. How can it store 'exit'? Besides, what is 'exit'? (answer: nothing)

Try to change it like, if user types 'x', or 'e'... or simply else (not 1 or 2)

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Join Date: Sep 2008

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unk45

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Re: address book

Oct 3rd, 2008

yeah..sorry about that..just realized it myself..so whats that command to make it jump to the press any key to continue part??

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
 
const int maxpeople = 50;
 
struct person
{
	char firstname[20];
 
	char lastname[20];
 
	char address[20];
};
 
void addpeople(person people[], int size);
 
void getperson(person people[maxpeople], int size);
 
using namespace std;
 
person people[10];
 
int main()
{
	addpeople(people, 10);
 
	while(true)
	{
 
	getperson(people, 10);
 
	}
 
	return 0;
}
 
void addpeople(person people[maxpeople], int size)
{
	for(int i = 0;i < size; i++)
	{
 
		cout<<"Enter your first name, last name and address respectively"<<endl;
 
		cin>>people[i].firstname>>people[i].lastname>>people[i].address;
 
	}
}
 
 
void getperson(person people[maxpeople], int size)
{	
	char type;
 
	char firstname[20] = {0};
 
	char lastname[20] = {0};
 
 
 
	cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
	cin >> type;
 
	if( type == '1')
	{
 
		cout << "Enter Last Name\n";
		cin >> lastname;
 
			for(int i = 0; ;i++)
			{
 
			if(people[i].lastname == lastname)
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}
 
			}
	}
 
	else if( type == '2')
	{
		cout << "Enter First Name\n";
		cin >> firstname;
		cout << "Enter Last Name\n";
		cin >> lastname;
 
		for(int i = 0; ;i++)
		{
 
			if(people[i].lastname == lastname && people[i].firstname == firstname )
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}
 
 
		}
 
	}
 
	else if(type == '1' && type == '2')
	{
		while (type == 1 && type == 2)
		{
		cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
		cin >> type;
		}
	}
 
	else if(type == 'exit')
 
 
 
 
}
#include <iostream>

const int maxpeople = 50;

struct person
{
	char firstname[20];

	char lastname[20];

	char address[20];
};

void addpeople(person people[], int size);

void getperson(person people[maxpeople], int size);

using namespace std;

person people[10];

int main()
{
	addpeople(people, 10);

	while(true)
	{
	
	getperson(people, 10);

	}

	return 0;
}

void addpeople(person people[maxpeople], int size)
{
	for(int i = 0;i < size; i++)
	{

		cout<<"Enter your first name, last name and address respectively"<<endl;

		cin>>people[i].firstname>>people[i].lastname>>people[i].address;

	}
}


void getperson(person people[maxpeople], int size)
{	
	char type;
	
	char firstname[20] = {0};
	
	char lastname[20] = {0};


	
	cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
	cin >> type;
	
	if( type == '1')
	{
		
		cout << "Enter Last Name\n";
		cin >> lastname;
		
			for(int i = 0; ;i++)
			{

			if(people[i].lastname == lastname)
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}
	
			}
	}
	
	else if( type == '2')
	{
		cout << "Enter First Name\n";
		cin >> firstname;
		cout << "Enter Last Name\n";
		cin >> lastname;
		
		for(int i = 0; ;i++)
		{
		
			if(people[i].lastname == lastname && people[i].firstname == firstname )
		{
			cout<<"The person's first name is"<<people[i].firstname<<"\n The persons last name is "<<people[i].lastname<<"\n The person's address is "<<people[i].address;
		}

	
		}

	}
	
	else if(type == '1' && type == '2')
	{
		while (type == 1 && type == 2)
		{
		cout << "Enter 1) to find the person by their Last Name\n OR\n 2) to find the person by their First Name and Last Name\n";
		cin >> type;
		}
	}

	else if(type == 'exit')
	

	

}

Last edited by unk45; Oct 3rd, 2008 at 2:38 pm.

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Join Date: Dec 2007

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Agni

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Re: address book

Oct 3rd, 2008

why dont these 'for(int i = 0; ;i++)' loops have any comparison condition? when will it stop? I think before you complete this assignment you need to understand loops and arrays once more.. dont even try to solve it before you re-read those topics, ur basics are not correct and your just trying to somehow get the output without understanding what your doing here .. and you might just make yourself learn something wrong ... hit the books and then attempt it again... all the best

thanks
-chandra

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unk45

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Re: address book

Oct 3rd, 2008

ok..i think i figured that out

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
for(int i = 0;i < size ;i++)
for(int i = 0;i < size ;i++)

but now jst asks the last name or first name question when i type in a number?

Last edited by unk45; Oct 3rd, 2008 at 2:52 pm.

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Lerner

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Re: address book

Oct 3rd, 2008

You are using C style strings for the names, which is fine, but you can't compare C style strings using the == operator. You can compare stl string objects using the == operator. To compare C style strings for equality you need to use strcmp() and evaluate the return value. If the two strings are the same the return value should be zero.
----------------------------------------------
I'd tell the user how to exit the loop explicitly.

cout << "enter the appropriate number to select the described option" << endl;
cout << "1) search by last name only" << endl;
cout << "2) search by first and last name" << endl;
cout << "3) stop searching" << endl;
char type;
cin >> type;

I would declare type as an int rather than a char, too, but that's personal choice.
-----------------------------------------
else if(type == '1' && type == '2')

How can type be both '1' and '2'? Given the context I'd use != instead of ==.

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stilllearning stilllearning is offline

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Re: address book

Oct 3rd, 2008

There is another problem with your code

if(people[i].lastname == lastname)
You cannot compare two char arrays with the == operator. You either need to define them as "string" or you need to use strcmp() to compare them.

Last edited by stilllearning; Oct 3rd, 2008 at 4:38 pm.

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Ancient Dragon Ancient Dragon is offline

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Re: address book

#10

Oct 3rd, 2008

>>if(people[i].lastname == lastname)
You can't compare two character arrays with the == operator like you do two std::strings. To compare character arrays call strcmp() functions. if( strcmp(people[i].lastname == lastname) == 0)

Don't PM me with questions -- you might get a nasty PM in response. If you have a question then post it in one of the forums.