XML, XSLT and XPATH

XML, XSLT and XPATH RSS

new to xslt

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Join Date: Nov 2006

Posts: 47

Reputation: nnobakht is an unknown quantity at this point

Solved Threads: 1

nnobakht

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Light Poster

new to xslt

Oct 21st, 2008

Hi guys,
Im brand new to doing tansformations and cannot seem to wrap my head around it.
I have a Xml File which looks something like

 Help with Code Tags 
 XML, XSLT and XPATH Syntax (Toggle Plain Text) 
<parentNode>
  <childnode1 att1="1" att2="2"/>
  <childnode2></childnode2>
  <childnode1 att1="1" att2="2"/>
  <childnode21></childnode21>
  <childnode1 att1="1" att2="2"/>
  <childnode22></childnode22>
  <childnode1 att1="1" att2="2"/>
  <childnode23></childnode23>
  <childnode1 att1="1" att2="2"/>
  <childnode24></childnode24>
  <optionalNode></optionalNode>
</parentNode>
<parentNode>
  <childnode1 att1="1" att2="2"/>
  <childnode2></childnode2>
  <childnode1 att1="1" att2="2"/>
  <childnode21></childnode21>
  <childnode1 att1="1" att2="2"/>
  <childnode22></childnode22>
  <childnode1 att1="1" att2="2"/>
  <childnode23></childnode23>
  <childnode1 att1="1" att2="2"/>
  <childnode24></childnode24>
  <optionalNode></optionalNode>
</parentNode>

The childnode labled ChildNode1 is repeated several times (the values are identical) and what i am trying to do is transform this xml into a new xml which only has one childnode1
and teh rest are "deleted" or ignored during the transformation.Everything else must stay the same and the position of the childnode needs to be the first position it is found in.
I know the name of the childNode1 before hand.

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 XML, XSLT and XPATH Syntax (Toggle Plain Text) 
<parentNode>
  <childnode1 att1="1" att2="2"/>
  <childnode2></childnode2>
  <childnode21></childnode21>
  <childnode22></childnode22>
  <childnode23></childnode23>
  <childnode24></childnode24>
  <optionalNode></optionalNode>
</parentNode>
<parentNode>
  <childnode1 att1="1" att2="2"/>
  <childnode2></childnode2>
  <childnode21></childnode21>
  <childnode22></childnode22>
  <childnode23></childnode23>
  <childnode24></childnode24>
  <optionalNode></optionalNode>
</parentNode>

Is this even possible?
How should i go about it.
Thank you

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Join Date: Jun 2008

Posts: 13

Reputation: gravyboat is an unknown quantity at this point

Solved Threads: 2

gravyboat

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Newbie Poster

Re: new to xslt

Oct 27th, 2008

Here is an XSLT that will do what you want.

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 XML, XSLT and XPATH Syntax (Toggle Plain Text) 
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="xml" indent="yes"/>
 
    <xsl:template match="/">
    	<parentNode>
	    	<xsl:copy-of select=".//childnode1[1]"/>
 
	    	<xsl:for-each select="./parentNode/child::*[not(name()='childnode1')]">
	    		<xsl:copy-of select="."/>
	    	</xsl:for-each>
	    </parentNode>
	</xsl:template>
 
</xsl:stylesheet>
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
	<xsl:output method="xml" indent="yes"/>

    <xsl:template match="/">
    	<parentNode>
	    	<xsl:copy-of select=".//childnode1[1]"/>
	    	
	    	<xsl:for-each select="./parentNode/child::*[not(name()='childnode1')]">
	    		<xsl:copy-of select="."/>
	    	</xsl:for-each>
	    </parentNode>
	</xsl:template>

</xsl:stylesheet>

At the root we create the <parentNode> that will contain all children. Since we only want one childnode1, we copy the first by using the "[1]" position argument. We then loop through all of the children of parentNode, copying only those that are not named childnode1.