output in c programming

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output in c programming

 
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  #1
Nov 3rd, 2008
1) # define cube(x)(x*x*x)
main()
int x=2. y, z;
y= cube(++x);
z= ++y + 386 / cube(++x);
printf("%d %d %d", ++x, y, z);


convert into hexadecimal
2) a = 0*aa b = a<<1
a) b=a
b) b= 2a
Last edited by gayatri.saha; Nov 3rd, 2008 at 5:01 pm. Reason: did not get appropriate reply
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Re: output in c programming

 
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Nov 3rd, 2008
Your question seems clumsily constructed and you haven't used code tags. Be specific when asking questions.
Last edited by devnar; Nov 3rd, 2008 at 4:49 pm.
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Re: output in c programming

 
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  #3
Nov 4th, 2008
This is homework assignment and gayatri apparently wants us to do it for him/her.

The code you posted will have undefined behavior. cube(++x) could result in different answers on different compilers, so the ourput can not be determined exactly.
Don't PM me with questions -- you might get a nasty PM in response. If you have a question then post it in one of the forums.
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Re: output in c programming

 
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  #4
Nov 7th, 2008
Hi i am also new to C

I think ans may be

X=2, Y=8,z=61
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Re: output in c programming

 
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Nov 7th, 2008
We wont do your homework for you, and please use code tags in future please. Check the rules and welcome guide for details.
If i am helpful, please give me reputation points.
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Re: output in c programming

 
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Nov 8th, 2008
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Originally Posted by Ancient Dragon View Post
The code you posted will have undefined behavior. cube(++x) could result in different answers on different compilers, so the ourput can not be determined exactly.
Why? It increments i, calls cube with the new value, then returns the answer to y. What's undefined about it? i isn't modified twice.
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Re: output in c programming

 
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Nov 9th, 2008
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Originally Posted by WaltP View Post
Why? It increments i, calls cube with the new value, then returns the answer to y. What's undefined about it? i isn't modified twice.
That's because cube is not a function name: it's a macros. We (not me, I never use macros) have:
c Syntax (Toggle Plain Text) 
  1. # define cube(x)(x*x*x)
  2. int x = 2;
  3. y= cube(++x);
  4. is
  5. y = (++x*++x*++x);
But operator ++ side effect (incr x) committing point is the outer expression terminator - semicolon. So every factor may be equal to 3, 4, or 5!..
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Re: output in c programming

 
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  #8
Nov 10th, 2008
My bad. I thought he wrote a function. I didn't know the macro existed, never needing it.
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