CIN>>EQUATION (how to then mult by it later)
Please support our C++ advertiser: Programming Forums
![]() |
•
•
Posts: 12
Reputation:
Solved Threads: 0
I'm currently writing a program that takes in a function such as ( 7x+19 ) and I need to evaluate the function that user inputs at range of numbers. I've got the loop figured out to loop through my desired numbers, but I don't know what to call the function when the user cin>>function. Should it be a char, string, int, double? Because later I'll need to call function and mult. it by lets say 3, or 5, or 12, etc? So what should I do to accomplish what I need to get done, I'm kind of stuck on this one. I'm kind of a beginner.
Do you want to multiply numbers or do you want to replace the x in your inputfunction with a value?
"If you judge people, you have no time to love them." Mother Teresa
Make love, no war. Cave ab homine unius libri.
First rule of debugging: "If you get a different error message, you're making progress."
Danny
Make love, no war. Cave ab homine unius libri.
First rule of debugging: "If you get a different error message, you're making progress."
Danny
•
•
Posts: 2,902
Reputation:
Solved Threads: 367
•
•
•
•
yea, I need to exchange x for the the number. such as 3, 4, 5 etc. Ill run a while loop to get my x,y coord.
You probably need to post some code and provide an example of a run of the program, even though you haven't written the program yet. You need to decide what kind of functions are legal (polynomials, exponents, logarithms, etc.). Have the user enter the function, read it in as a string, then parse the string in such a way that you can tell what kind of function it is (e.g. polynomial, whether it's a legal function that you can handle, then parse the string further to extract the relevant numbers (i.e. coefficients and exponents in a polynomial). But I think you'll have to read the function in as a string from the user.
The big thing is to decide what input your program needs to be able to handle, what assumptions it can make as far as good input, then go from there, in my opinion.
Last edited by VernonDozier : Nov 5th, 2008 at 2:00 pm.
•
•
Posts: 391
Reputation:
Solved Threads: 38
Sounds like your trying to parse a function. You'll have to enter the function as a string (either char * or string class), then use a loop to figuire out its contents. Depending on how robust/useful you want it to be, this could be a bit challenging for a beginner. Here's a start:
This will parse the formula and extract all the numbers into an array. This isn't really useful for solving anything, but it's a start. I would sugguest creating a class for holding/handling formulas and their operations. As you can see, it's a bit more complex an issue than it seems
cplusplus Syntax (Toggle Plain Text)
#include <string> #include <iostream> using namespace std; int main() { string sFormula = ""; strin sBuffer = ""; bool numStream(false); int iVal[255] = {0}; int iCount(0); cout << "Enter formula: "; cin >> sFormula for (int i(0); i < strlen(sFormula); ++i) { if (isdigit(sFormula[i])) { numStream = true; sBuffer += sFormula[i]; } if (numStream && !isdigit(sFormula[i]) { numStream = false; iVal[iCount++] = atoi(sBuffer); } } return 0; }
This will parse the formula and extract all the numbers into an array. This isn't really useful for solving anything, but it's a start. I would sugguest creating a class for holding/handling formulas and their operations. As you can see, it's a bit more complex an issue than it seems
Last edited by skatamatic : Nov 5th, 2008 at 2:15 pm.
As VernonDozier said you have to read your input as a string. But then you have to parse your inputstring and that's a whole world on it's own! But if you're adventurous enough to try it, don't hesitate! Start with http://en.wikipedia.org/wiki/Parsing
"If you judge people, you have no time to love them." Mother Teresa
Make love, no war. Cave ab homine unius libri.
First rule of debugging: "If you get a different error message, you're making progress."
Danny
Make love, no war. Cave ab homine unius libri.
First rule of debugging: "If you get a different error message, you're making progress."
Danny
•
•
Posts: 391
Reputation:
Solved Threads: 38
Here's an actual working math parser. It only works with addition and subtraction though. You've got me interested now, so I'm gonna write a (much more useful) class for this problem.
It works like this:
Input a stream of numbers and operands (- or +), all seperated by a space. Ie 2 + 6 + 8 - 11
And it will output the result. It won't throw any exceptions, so if you see eratic results you probably entered the equation wrong.
cplusplus Syntax (Toggle Plain Text)
#include <string.h> #include <iostream> using namespace std; int main() { string sFormula = ""; string sBuffer; char szFormula[255]; bool numStream(false); int iVal[2] = {0}; int iReturnVal(0); int iCount(0); char cLastOperator(0); cout << "Enter formula: "; cin.getline(szFormula, 54); for (unsigned int i(0); i < strlen(szFormula); ++i) { if (isdigit(szFormula[i])) { numStream = true; sBuffer += szFormula[i]; } if (numStream && (!isdigit(szFormula[i]) || i == strlen(szFormula) - 1)) { numStream = false; iVal[iCount++] = atoi(sBuffer.c_str()); if (cLastOperator == '+') { iReturnVal += iVal[0] + iVal[1]; iVal[0] = 0; iVal[1] = 0; iCount = 0; cLastOperator = 0; } else if (cLastOperator == '-') { iReturnVal -= iVal[0] + iVal[1]; iVal[0] = 0; iVal[1] = 0; iCount = 0; cLastOperator = 0; } sBuffer = ""; } if (!numStream && (szFormula[i] == '+' || szFormula[i] == '-' || szFormula[i] == '*')) { cLastOperator = szFormula[i]; } } cout << szFormula << " = " << iReturnVal << endl; cin.get(); return 0; }
It works like this:
Input a stream of numbers and operands (- or +), all seperated by a space. Ie 2 + 6 + 8 - 11
And it will output the result. It won't throw any exceptions, so if you see eratic results you probably entered the equation wrong.
Last edited by skatamatic : Nov 5th, 2008 at 3:05 pm.
![]() |
Other Threads in the C++ Forum
- Previous Thread: A little problem
- Next Thread: Repaint window help?
•
•
•
•
Views: 393 | Replies: 8 | Currently Viewing: 1 (0 members and 1 guests)






Linear Mode