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Views: 1982 | Replies: 12
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Join Date: Dec 2004
Posts: 15
Reputation: 
Rep Power: 4
Solved Threads: 0
Newbie Poster
Hi,
Here's my code:
#include <iostream.h>
int main ()
{
int i;
cout << "Please enter a number" << endl;
cin >> i;
if (i < 0)
{ cout << "The number you entered is negative.\n";}
if (i = 0)
{ cout << "The number you entered is zero.\n";}
if (i > 0)
{ cout << "The number you entered is positive.\n";}
else
{ cout << "Thank you for using this program.\n";}
return 0;
}
I just want to have the program print if the number is 0, negative or positive. The code works with no errors but all it does is ask for a number, and when you hit enter it says Thanks...What am I doing wrong? I've been on this for 2 hours! HELP.
Here's my code:
#include <iostream.h>
int main ()
{
int i;
cout << "Please enter a number" << endl;
cin >> i;
if (i < 0)
{ cout << "The number you entered is negative.\n";}
if (i = 0)
{ cout << "The number you entered is zero.\n";}
if (i > 0)
{ cout << "The number you entered is positive.\n";}
else
{ cout << "Thank you for using this program.\n";}
return 0;
}
I just want to have the program print if the number is 0, negative or positive. The code works with no errors but all it does is ask for a number, and when you hit enter it says Thanks...What am I doing wrong? I've been on this for 2 hours! HELP.
*Lori*
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Join Date: Apr 2004
Posts: 3,462
Reputation: 
Rep Power: 16
Solved Threads: 138
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Join Date: Nov 2004
Location: Netherlands
Posts: 5,661
Reputation:
Rep Power: 18
Solved Threads: 192
what does " if (i=0) " do?
think about that, there's an error on that line
think about that, there's an error on that line
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Join Date: Dec 2004
Posts: 15
Reputation:
Rep Power: 4
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Newbie Poster
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Originally Posted by jwenting
what does " if (i=0) " do?
think about that, there's an error on that line
Well, I think it should go to cout << The number you entered is zero. Right??
*Lori*
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Join Date: Apr 2004
Posts: 3,462
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Originally Posted by LAMJAM
Well, I think it should go to cout << The number you entered is zero. Right??
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Join Date: Dec 2004
Posts: 15
Reputation:
Rep Power: 4
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Newbie Poster
Thanks! I knew it was something stupid!
*Lori*
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Join Date: Dec 2004
Posts: 15
Reputation:
Rep Power: 4
Solved Threads: 0
Newbie Poster
I have another one that's making me crazy. My code so far is...I just need some prodding-please.
#include <iostream.h>
void print_value
int global = x;
x = 0;
int main ()
{
int local = y;
y = num?
cin please enter num.
// function incx loop 15 times
incx = x++ //increment x by 1 each time
cout the value of x is x.
#include <iostream.h>
void print_value
int global = x;
x = 0;
int main ()
{
int local = y;
y = num?
cin please enter num.
// function incx loop 15 times
incx = x++ //increment x by 1 each time
cout the value of x is x.
*Lori*
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Join Date: Nov 2004
Location: Netherlands
Posts: 5,661
Reputation:
Rep Power: 18
Solved Threads: 192
you're not thinking!
What does i=0 do?
So what happens when you do if (i=0) ?
And indeed what is the result if if (i=0) ?
some hints:
assignment, false
What does i=0 do?
So what happens when you do if (i=0) ?
And indeed what is the result if if (i=0) ?
some hints:
assignment, false
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Join Date: Dec 2004
Posts: 15
Reputation:
Rep Power: 4
Solved Threads: 0
Newbie Poster
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Originally Posted by jwenting
you're not thinking!
What does i=0 do?
So what happens when you do if (i=0) ?
And indeed what is the result if if (i=0) ?
some hints:
assignment, false
Thanks,
I figured that one out. I just had to change it to (i ==0) and it worked.
Now my problem is with the other code...
#include <iostream.h>
void print_value
int global = x;
x = 0;
int main ()
{
int local = y;
y = num
cin please enter num.
//function incx loop 15 times
incx = x++ //increment x by 1 each time
cout the value of x is x.
*Lori*
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