Hi,
Here's my code:
#include <iostream.h>

int main ()
{
int i;

cout << "Please enter a number" << endl;
cin >> i;

if (i < 0)
{ cout << "The number you entered is negative.\n";}

if (i = 0)
{ cout << "The number you entered is zero.\n";}

if (i > 0)
{ cout << "The number you entered is positive.\n";}

else
{ cout << "Thank you for using this program.\n";}

return 0;
}


I just want to have the program print if the number is 0, negative or positive. The code works with no errors but all it does is ask for a number, and when you hit enter it says Thanks...What am I doing wrong? I've been on this for 2 hours! HELP.

This is assignment: This is comparison: [edit]And these are code tags: [code][/code]

what does " if (i=0) " do?

think about that, there's an error on that line

Well, I think it should go to cout << The number you entered is zero. Right??

Is zero true or false?

Thanks! I knew it was something stupid!

I have another one that's making me crazy. My code so far is...I just need some prodding-please.

#include <iostream.h>


void print_value
int global = x;
x = 0;


int main ()

{

int local = y;
y = num?
cin please enter num.


// function incx loop 15 times

incx = x++ //increment x by 1 each time

cout the value of x is x.

you're not thinking!
What does i=0 do?
So what happens when you do if (i=0) ?
And indeed what is the result if if (i=0) ?

some hints:
assignment, false

Thanks,
I figured that one out. I just had to change it to (i ==0) and it worked.
Now my problem is with the other code...

#include <iostream.h>


void print_value
int global = x;
x = 0;


int main ()

{

int local = y;
y = num
cin please enter num.


//function incx loop 15 times

incx = x++ //increment x by 1 each time

cout the value of x is x.

Okay, that's not really your code is it? Your compiler must be screaming at you. Are you having trouble with the error messages?