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Getting Future Date

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Join Date: Nov 2008

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xarz

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Getting Future Date

Nov 29th, 2008

I don't know how to explain this correctly but just some sample for you guys so that you can really get what Im trying to say.

Today is November 28, 2008

3 days from now is December 1,2008

Im looking for a php code, which can give me the exact date giving the number of days interval prior to the current date.

I've been looking for a thread which can solve or even give a hint on how to solve this one but I found none.

:: xarz ::

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peter_budo peter_budo is offline

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Re: Getting Future Date

Nov 29th, 2008

Is it so difficult to use google with keywords search php+get+date+future.
From what I got from this search even me with no interest in PHP could make that part of the code work...

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Join Date: Sep 2007

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cwarn23

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Re: Getting Future Date

Nov 29th, 2008

I have created a script for you to fiddle with and is below. The below script is a function where you can enter the number of days, months and years untill the future date and the function will return what that date is.

 Help with Code Tags 
 php Syntax (Toggle Plain Text) 
<?
function count_to_date($day,$month,$year)
    {
    $d=date(j)+$day;
    $m=date(n)+$month;
    $y=date(Y)+$year;
    if ($d>31)
        {
        while ($d>31)
            {
            $d-=31;
            $m+=1;
            }
        }
    if ($m>12)
        {
        while ($m>12)
            {
            $m-=12;
            $y+=1;
            }
        }
    //below sets sequence: day/month/year
    $r=$d.'/'.$m.'/'.$y;
    return $r;
    }
 
 
//below returns a future date (day/month/year)  
echo count_to_date(3,0,0);
 
//a bit of theory
//count_to_date(number_of_days,number_of_months,number_of_years);
?>
<?
function count_to_date($day,$month,$year)
    {
    $d=date(j)+$day;
    $m=date(n)+$month;
    $y=date(Y)+$year;
    if ($d>31)
        {
        while ($d>31)
            {
            $d-=31;
            $m+=1;
            }
        }
    if ($m>12)
        {
        while ($m>12)
            {
            $m-=12;
            $y+=1;
            }
        }
    //below sets sequence: day/month/year
    $r=$d.'/'.$m.'/'.$y;
    return $r;
    }


//below returns a future date (day/month/year)  
echo count_to_date(3,0,0);

//a bit of theory
//count_to_date(number_of_days,number_of_months,number_of_years);
?>

Try not to bump 10 year old threads as it can be really annoying.
Like php then read my website at http://syntax.cwarn23.net/
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Join Date: Nov 2008

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xarz

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Re: Getting Future Date

Dec 1st, 2008

@cwarn23

great! thanks alot for the code..
i haven't tried it yet.. but will let you know if there are any problems with it..

:: xarz ::

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Join Date: Dec 2008

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sikka_varun sikka_varun is offline

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Re: Getting Future Date

Dec 2nd, 2008

Hi I really doubt whether this piece of code will work for every date.. It might not work with february date, leap years, and for months with months with 30 days like april..

Im providing you with some other code sample, that can work for most of the cases...

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
<?php
function count_to_date($curr_day,$curr_month,$curr_yr,$day,$month,$year)
    {
    $d=$curr_day+$day;
    $m=$curr_month+$month;
    $y=$curr_yr+$year;
    if ($m>12)
        {
            $m-=12;
            $y+=1;
        }
 
	$no_of_days=get_days_in_month($m,$y);
	if ($d>$no_of_days)
        {
            $d-=$no_of_days;
            $m+=1;
        }
 
    //below sets sequence: day/month/year
    $r=$d.'/'.$m.'/'.$y;
    return $r;
    }
 
function leap_year($yr)
{
	if($yr%4==0 || $yr%400==0)
		return true;
	else
		return false;
}
function get_days_in_month($mnth_no,$yr)
{
	switch($mnth_no)
	{
		case 1:
		case 3:
		case 5:
		case 8:
		case 10:
		case 12:return 31;
		break;
 
		case 4:
		case 6:
		case 9:
		case 11:return 30;
		break;
 
		case 2:if(leap_year($yr))
					return 29;
				else
					return 28;
		break;
	}
}
 
//below returns a future date (day/month/year)  
echo count_to_date(30,3,2007,1,0,1);
 
//a bit of theory
//count_to_date(number_of_days,number_of_months,number_of_years);
?>
<?php
function count_to_date($curr_day,$curr_month,$curr_yr,$day,$month,$year)
    {
    $d=$curr_day+$day;
    $m=$curr_month+$month;
    $y=$curr_yr+$year;
    if ($m>12)
        {
            $m-=12;
            $y+=1;
        }
	
	$no_of_days=get_days_in_month($m,$y);
	if ($d>$no_of_days)
        {
            $d-=$no_of_days;
            $m+=1;
        }
    
    //below sets sequence: day/month/year
    $r=$d.'/'.$m.'/'.$y;
    return $r;
    }

function leap_year($yr)
{
	if($yr%4==0 || $yr%400==0)
		return true;
	else
		return false;
}
function get_days_in_month($mnth_no,$yr)
{
	switch($mnth_no)
	{
		case 1:
		case 3:
		case 5:
		case 8:
		case 10:
		case 12:return 31;
		break;
		
		case 4:
		case 6:
		case 9:
		case 11:return 30;
		break;
		
		case 2:if(leap_year($yr))
					return 29;
				else
					return 28;
		break;
	}
}
		
//below returns a future date (day/month/year)  
echo count_to_date(30,3,2007,1,0,1);

//a bit of theory
//count_to_date(number_of_days,number_of_months,number_of_years);
?>

VâRûN
---Happy to Help---
sikka_varun@yahoo.com

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Join Date: Nov 2008

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xarz

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Newbie Poster

Re: Getting Future Date

Dec 2nd, 2008

sikka_varun and cwarn23

thanks alot for the codes..

I make some modifications to fit my need from your work guys.
basically the changes are adding a parameter so that I can choose what date I want to start counting off.
Here is the outcome:

 Help with Code Tags 
 php Syntax (Toggle Plain Text) 
function count_to_date($sqldate,$day,$month,$year)
{
	$d=substr($sqldate,8,2);
	$m=substr($sqldate,5,2);
	$y=substr($sqldate,0,4);
	$h=substr($sqldate,11,2);
	$min=substr($sqldate,14,2);
 
    $d=intval($d)+$day;
    $m=intval($m)+$month;
    $y=intval($y)+$year;
    if ($d>31)
        {
        while ($d>31)
            {
            $d-=31;
            $m+=1;
            }
        }
    if ($m>12)
        {
        while ($m>12)
            {
            $m-=12;
            $y+=1;
            }
        }
    //below sets sequence: day/month/year
	if($d<10) $d='0'.$d;
	if($m<10) $m='0'.$m;
    $r=$y.'-'.$m.'-'.$d.' '.$h.':'.$min.':00';
    return $r;
}
function count_to_date($sqldate,$day,$month,$year)
{
	$d=substr($sqldate,8,2);
	$m=substr($sqldate,5,2);
	$y=substr($sqldate,0,4);
	$h=substr($sqldate,11,2);
	$min=substr($sqldate,14,2);
	
    $d=intval($d)+$day;
    $m=intval($m)+$month;
    $y=intval($y)+$year;
    if ($d>31)
        {
        while ($d>31)
            {
            $d-=31;
            $m+=1;
            }
        }
    if ($m>12)
        {
        while ($m>12)
            {
            $m-=12;
            $y+=1;
            }
        }
    //below sets sequence: day/month/year
	if($d<10) $d='0'.$d;
	if($m<10) $m='0'.$m;
    $r=$y.'-'.$m.'-'.$d.' '.$h.':'.$min.':00';
    return $r;
}

can be called by

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
echo count_to_date("2007-07-01 06:00:00",5,0,0);
echo count_to_date("2007-07-01 06:00:00",5,0,0);