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Solve My Question Pls....
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Hi,
Can u add numbers without using arithmetic operators in java.We can add using bitwise operators.But i m not able to get the ans.
Solve:
a+b=c;
Prove 2+2=4 without using arithmetic opreations.
Looking for u r answers
Can u add numbers without using arithmetic operators in java.We can add using bitwise operators.But i m not able to get the ans.
Solve:
a+b=c;
Prove 2+2=4 without using arithmetic opreations.
Looking for u r answers
What have you done on this problem? Show us some effort and maybe you will receive help. Also, try google.
Last edited by jasimp; Nov 29th, 2008 at 10:20 am.
"Argyou not with the hand you are dealt in cards or life." ---- Wizard and Glass
And I want a billion dollars 
"Argyou not with the hand you are dealt in cards or life." ---- Wizard and Glass
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One way that came to mind is use 2 for-loops
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What about binary calculations 
010
AND
010
is
100
010
AND
010
is
100
Last edited by peter_budo; Nov 29th, 2008 at 7:54 pm.
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(~100 BC)
LJC - London Java Community, Graduate & Undergraduate Software Development Community, JAVAWUG (Java Web User Group), The London Android Group
Publilius Syrus
(~100 BC)
LJC - London Java Community, Graduate & Undergraduate Software Development Community, JAVAWUG (Java Web User Group), The London Android Group
We can multiply/divide by 2 succesive using bitwise operators .
May be You are looking to The Vedas (Sanskrit वेद, véda, "knowledge") arithmetic .The product of the sum - Gunitasamuchyah.
(or Trachtenbergs system to speed multiply in memory).
quuba
byte a = 4;
byte b = (byte) (a >> 1);
byte c = (byte) (a >> 2);
byte d = (byte) (a << 1);
System.out.println(a);
System.out.println(b);
System.out.println(c);
System.out.println(d);(or Trachtenbergs system to speed multiply in memory).
quuba
I m still can't get the answer from u guys.....
Let me explain more in detail:
class add{
public static void main(String args[])
{
int a=2,b=2,c;
c=a+b;
System.out.println("C="+c);
}
}
This what we normally done using arith operator '+'.
I want the answer c=4 without using '+' or any arith operator.
Pls suggest ur ideas through the example.. i m a beginner in java so i can clearly understand... Hoping for u r answers......
Let me explain more in detail:
class add{
public static void main(String args[])
{
int a=2,b=2,c;
c=a+b;
System.out.println("C="+c);
}
}
This what we normally done using arith operator '+'.
I want the answer c=4 without using '+' or any arith operator.
Pls suggest ur ideas through the example.. i m a beginner in java so i can clearly understand... Hoping for u r answers......
c=a+b; - here is arithmetic operator .System.out.println("C="+c); - here is overloaded operator + . Here this mean CONCATENATION of two String-s.
You can asked: c is not a String type. Yes it is true, but c is casting to String automatically before join.
In Your case You can write:
System.out.print("C=");
System.out.println(""+c);// "" (an empty String) can cast integer to StringSystem.out.print("C=");
System.out.println(c);// "" automatic cast int to StringRemark: Sign + in arithmetic has two menings:
1. before a single number indicate, positive number
2. between two numbers , sum operation
Try write:
System.out.println(c++); orSystem.out.println(++c); try explain differencequuba
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Use XOR .
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