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Simple Recursion (Multiplying by using Addition)
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Join Date: Mar 2008
Posts: 352
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Hello all,
My objective is simple. I have to take in 2 positive integers and multiply them by using addition. This is a recursive problem.
Example of Output:
Please enter 2 positive integers to multiply:
4 2
4 * 2 = 8
The problem is whenever the user types in both numbers, the program window just disappears.
To receive my result, I am suppose to use something like:
x + multiply(x,--y);
Please help me with this...Thank you
My objective is simple. I have to take in 2 positive integers and multiply them by using addition. This is a recursive problem.
Example of Output:
Please enter 2 positive integers to multiply:
4 2
4 * 2 = 8
The problem is whenever the user types in both numbers, the program window just disappears.
To receive my result, I am suppose to use something like:
x + multiply(x,--y);
Please help me with this...Thank you
C++ Syntax (Toggle Plain Text)
#include <iostream> using namespace std; int multiply(int x, int y); int main() { int x; int y; cout<<"Please enter 2 positive integers to multiply"<<endl; cin>>x; cin>>y; cout<<x<<" * "<<y<<" = "<<multiply(x,--y)<<endl; system ("PAUSE"); return 0; } int multiply(int x, int y) { if (x == 0) { return 0; } if (x == 1) { return x; } if (x > 1) { return (x + multiply(x,--y)); } }
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