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Floating point numbers

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Join Date: Sep 2004

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Narue

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Senior Bitch

Re: Floating point numbers

#21

Jan 1st, 2005

>if ( string[n] < 0 )
This test is wrong because a printable character will not be less than 0. What are you trying to do to make the code "more powerful"?

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Join Date: Dec 2004

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happyHour

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Re: Floating point numbers

#22

Jan 1st, 2005

basically if a user enteres a - followed by the numbers then the statment will look for the sign and says that the sign is a -.

if its not a minus then the number enetered must be a plus

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Join Date: Sep 2004

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Narue

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Re: Floating point numbers

#23

Jan 1st, 2005

Well, in that case you need to test for '-':

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
if (string[0] == '-')
  cout<<"Negative value"<<endl;
else
  cout<<"Positive value"<<endl;
if (string[0] == '-')
  cout<<"Negative value"<<endl;
else
  cout<<"Positive value"<<endl;

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1o0oBhP

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Re: Floating point numbers

#24

Jan 1st, 2005

•

basically if a user enteres a - followed by the numbers then the statment will look for the sign and says that the sign is a -.

if its not a minus then the number enetered must be a plus

so let the user enter a number!!!!

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
float x;
 
cin >> x;
 
if(x < 0)
    cout << "You entered a negative number\n";
else
    cout << "You entered a positive number\n";
 
cout << "The real part: " << int(x) <<"\n";
cout << "The fractional part: " << float(x - int(x)) << "\n";
float x;

cin >> x;

if(x < 0)
    cout << "You entered a negative number\n";
else
    cout << "You entered a positive number\n";

cout << "The real part: " << int(x) <<"\n";
cout << "The fractional part: " << float(x - int(x)) << "\n";