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How To Get this ??

 
0
  #1
Dec 16th, 2008
I have problem in getting outputs
plz give me suggetion or correct error if any and make it working.......
plz help.........

there is no error........in this program.........when i compiled.

c++ Syntax (Toggle Plain Text) 
  1.  #include<iostream>
  2. #include<cstdio>
  3. #include<cstring>
  4. #include<cstdio>
  5. #define IS_STRING 1
  6. #define IS_CHARACTER 2
  7. #define IS_INTEGER 3
  8. #define IS_FLOAT 4
  9. //using std::cout;
  10. //using std::cin;
  11. //using std::endl;
  12. using namespace std;
  13. int main(void)
  14. {
  15. string s;
  16. cout<<"Input a string/character/number:\n";
  17. cin>>s;
  18. short int input_type=0;
  19. int x;
  20. bool DotReached=false;
  21. if(s.length()==1 && (s[0]>'9' || s[0]<'0'))
  22. {
  23. input_type=IS_CHARACTER;
  24. cout<< "its a char";
  25. }
  26. else
  27. for(x=0;x<s.length();x++)
  28. {
  29. if((s[x]>'9' || s[x]<'0') && s[x]!='.')
  30. {
  31. input_type=IS_STRING; break;
  32. cout<<" Its an integer ";
  33. }
  34. else if(s[x]=='.')
  35. {if(!DotReached) DotReached= true; else
  36.  {
  37.  input_type=IS_STRING; 
  38.  cout<<"ITs a Float";
  39.  break;
  40.  }
  41. }
  42. }
  43. cin.get();
  44. cin.get();
  45. return 0;
  46. }
Last edited by ninja_gs; Dec 16th, 2008 at 9:43 am.
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Re: How To Get this ??

 
0
  #2
Dec 16th, 2008
c++ Syntax (Toggle Plain Text) 
  1. for(x=0;x<s.length();x++)
  2. {
  3.     if((s[x]>'9' || s[x]<'0') && s[x]!='.')
  4.    {
  5.    input_type=IS_STRING; break;
  6.    cout<<" Its an integer ";
  7.    }
  8.  
  9.    else if(s[x]=='.')
  10.   {
  11.    if(!DotReached) DotReached= true; else
  12.    {
  13.    input_type=IS_STRING; 
  14.    cout<<"ITs a Float";
  15.    break;
  16.    }
  17.  }
  18. }

Line 6:
How do you want the program to output "It's an integer" when there's a "break;" before it?
You should output "It's a string" and not "It's an integer" if the input_type is IS_STRING.

Line 14:
Again, it's a string, not a floating-point number.

If you want to determine the input type after you know it's not a char/string (if input_type==0, which is its initial value), you should just check if DotReached returns true or false, because you already know it's a number:
c++ Syntax (Toggle Plain Text) 
  1.   if(input_type==0) // the initial value - meaning no type is determined yet
  2.    {
  3.    if(DotReached) input_type=IS_FLOAT;
  4.    else input_type=IS_INTEGER;
  5.    }
Last edited by unbeatable0; Dec 16th, 2008 at 10:30 am.
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Re: How To Get this ??

 
0
  #3
Dec 16th, 2008
Cool i corrected it ......
thanks Mr Unbeatable()
It works but Also Say Its integer
when i enter Floating
C++ Syntax (Toggle Plain Text) 
  1. #include<iostream>
  2. #include<cstdio>
  3. #include<cstring>
  4. #include<cstdio>
  5. #define IS_STRING 1
  6. #define IS_CHARACTER 2
  7. #define IS_INTEGER 3
  8. #define IS_FLOAT 4
  9. //using std::cout;
  10. //using std::cin;
  11. //using std::endl;
  12. using namespace std;
  13. int main(void)
  14. {
  15. string s;
  16. cout<<"Input a string/character/number:\n";
  17. cin>>s;
  18. short int input_type=0;
  19. int x;
  20. bool DotReached=false;
  21. if(s.length()==1 && (s[0]>'9' || s[0]<'0'))
  22. {
  23. input_type=IS_CHARACTER;
  24. cout<< "its a char";
  25. }
  26. else
  27. for(x=0;x<s.length();x++)
  28. {
  29. if((s[x]>'9' || s[x]<'0') && s[x]!='.')
  30. {
  31. input_type=IS_STRING;
  32. cout<<" ITs an String ";
  33. break;
  34. }
  35. else if(input_type==0) 
  36.   {
  37.     if(DotReached) 
  38.     {
  39.      input_type=IS_FLOAT;
  40.      cout<<"Its a Floating Point Value";
  41.      break; 
  42.       }
  43.    else
  44.    {
  45.     input_type=IS_INTEGER;
  46.     cout<<"Its an Integer";
  47.     break;
  48.    }
  49.    }
  50. }
  51. cin.get();
  52. cin.get();
  53. cin.get();
  54. return 0;
  55. }

Need help for this Part

Wats wrong ??

it shows Int For float.............
Last edited by ninja_gs; Dec 16th, 2008 at 12:04 pm.
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Re: How To Get this ??

 
0
  #4
Dec 16th, 2008
You have a few errors:
Firstly, the if(input_value==0) ..... should be OUTSIDE the 'for' loop, because you want to check what kind of number the input is after you know it isn't a string nor a char.
Therefore you need to end the loop before this 'if' and remove the 'else' before it.
Secondly, in lines 38-39, the type is IS_STRING, because a number can't have more than a single dot.
Now just return the code you've put in the comments. It's necessary!
Lastly, you don't need the break; in lines 49 and 55, as they're not supposed to be in a loop
Last edited by unbeatable0; Dec 16th, 2008 at 11:50 am.
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Re: How To Get this ??

 
0
  #5
Dec 16th, 2008
I think i corrected mistakes you have mentioned earlier........

Plz Now Say wats the Problem.........

c++ Syntax (Toggle Plain Text) 
  1. #include<iostream>
  2. #include<cstdio>
  3. #include<cstring>
  4. #include<cstdio>
  5. #define IS_STRING 1
  6. #define IS_CHARACTER 2
  7. #define IS_INTEGER 3
  8. #define IS_FLOAT 4
  9. //using std::cout;
  10. //using std::cin;
  11. //using std::endl;
  12. using namespace std;
  13. int main(void)
  14. {
  15. string s;
  16. cout<<"Input a string/character/number:\n";
  17. cin>>s;
  18. short int input_type=0;
  19. int x;
  20. bool DotReached=false;
  21. if(s.length()==1 && (s[0]>'9' || s[0]<'0'))
  22. {
  23. input_type=IS_CHARACTER;
  24. cout<< "its a char";
  25. }
  26. else
  27. for(x=0;x<s.length();x++)
  28. {
  29.   if((s[x]>'9' || s[x]<'0') && s[x]!='.')
  30.     {
  31.      input_type=IS_STRING;
  32.      cout<<" ITs an String ";
  33.      break;
  34.      }
  35. }
  36. //else 
  37. if(input_type==0)
  38.    {
  39.     if(DotReached) 
  40.      {
  41.      input_type=IS_FLOAT;
  42.      cout<<"Its a Floating Point Value";
  43.      //break; 
  44.      }
  45.    else
  46.      {
  47.     input_type=IS_INTEGER;
  48.     cout<<"Its an Integer";
  49.      //break;
  50.      }
  51.    }
  52. cin.get();
  53. cin.get();
  54. cin.get();
  55. return 0;
  56. }
Last edited by ninja_gs; Dec 16th, 2008 at 12:10 pm.
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Re: How To Get this ??

 
0
  #6
Dec 16th, 2008
That's because you removed this piece of code from your code:
c++ Syntax (Toggle Plain Text) 
  1. else if(s[x]=='.')
  2. {
  3.    if(!DotReached) DotReached= true;
  4.  
  5.    else
  6.    {
  7.    input_type=IS_FLOAT; 
  8.    cout<<"ITs a Float";
  9.    break;
  10.    }
  11. }
Last edited by unbeatable0; Dec 16th, 2008 at 12:14 pm.
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Re: How To Get this ??

 
0
  #7
Dec 16th, 2008
c++ Syntax (Toggle Plain Text) 
  1. #include<iostream>
  2. #include<cstdio>
  3. #include<cstring>
  4. #include<cstdio>
  5. #define IS_STRING 1
  6. #define IS_CHARACTER 2
  7. #define IS_INTEGER 3
  8. #define IS_FLOAT 4
  9. //using std::cout;
  10. //using std::cin;
  11. //using std::endl;
  12. using namespace std;
  13. int main(void)
  14. {
  15. string s;
  16. cout<<"Input a string/character/number:\n";
  17. cin>>s;
  18. short int input_type=0;
  19. int x;
  20. bool DotReached=false;
  21. if(s.length()==1 && (s[0]>'9' || s[0]<'0'))
  22. {
  23. input_type=IS_CHARACTER;
  24. cout<< "its a char";
  25. }
  26. else
  27. for(x=0;x<s.length();x++)
  28. {
  29.   if((s[x]>'9' || s[x]<'0') && s[x]!='.')
  30.    {
  31.      input_type=IS_STRING;
  32.      cout<<" ITs an String ";
  33.      break;
  34.     }
  35.      else if(s[x]=='.')
  36.      {
  37.      if(!DotReached) DotReached= true; 
  38.      else
  39.      {
  40.      input_type=IS_FLOAT; 
  41.      cout<<"Its a flt";
  42.      break;
  43.      }
  44.     //else 
  45. if(input_type==0) // the initial value - meaning no type is determined yet
  46.    {
  47.     if(DotReached) 
  48.      {
  49.      input_type=IS_FLOAT;
  50.      cout<<"Its a Floating Point Value";
  51.      //break; 
  52.      }
  53.    else
  54.      {
  55.     input_type=IS_INTEGER;
  56.     cout<<"Its an Integer";
  57.      //break;
  58.      }
  59.    }
  60. cin.get();
  61. cin.get();
  62. cin.get();
  63. return 0;
  64. }
  65. }
  66. }

IS THIS SO ?????/
MENTION THE LINE IN HERE SIR
I CANT GET IT ....SIR

CAN YOU PLZ FILL WAT TO BE ADDED ........
PLZ.........
Last edited by ninja_gs; Dec 16th, 2008 at 12:46 pm.
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Re: How To Get this ??

 
0
  #8
Dec 16th, 2008
Lines 40-41 - it's a STRING, not a float. I've never heard of a number with two decimal dots.
Also, you didn't end the 'for' loop before the input_type check.
You can see it yourself.
Last edited by unbeatable0; Dec 16th, 2008 at 12:51 pm.
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Re: How To Get this ??

 
0
  #9
Dec 16th, 2008
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COOL IT WORKS
I GOTTCHA

THNKS MAN

UR A KIND FULL PERSON MAN
NOW I AM HAPPY
Great job..........Mr.Unbeatable()..........
THAnks Mr.

heres the working Code
c++ Syntax (Toggle Plain Text) 
  1.  #include<iostream>
  2. #include<cstdio>
  3. #include<cstring>
  4. #include<cstdio>
  5. #define IS_STRING 1
  6. #define IS_CHARACTER 2
  7. #define IS_INTEGER 3
  8. #define IS_FLOAT 4
  9. //using std::cout;
  10. //using std::cin;
  11. //using std::endl;
  12. using namespace std;
  13. int main(void)
  14. {
  15.  string s;
  16.  cout<<"Input a string/character/number:\n";
  17.  cin>>s;
  18.  short int input_type=0;
  19.  int x;
  20.  bool DotReached=false;
  21.  if(s.length()==1 && (s[0]>'9' || s[0]<'0'))
  22.  {
  23.  input_type=IS_CHARACTER;
  24.  cout<< "its a char";
  25.  }
  26.  else
  27.  for(x=0;x<s.length();x++)
  28.   {
  29.    if((s[x]>'9' || s[x]<'0') && s[x]!='.')
  30.     {
  31.       input_type=IS_STRING;
  32.       cout<<" ITs an String ";
  33.       break;
  34.     }
  35.    else if(s[x]=='.')
  36.     {
  37.      if(!DotReached)
  38.       { 
  39.        DotReached= true; 
  40.       }
  41.    else
  42.      {
  43.       input_type=IS_STRING; 
  44.       cout<<"Its a flt";
  45.       break;
  46.      }
  47.    }
  48. }
  49.     //else 
  50. if(input_type==0) // the initial value - meaning no type is determined yet
  51.    {
  52.     if(DotReached) 
  53.      {
  54.      input_type=IS_FLOAT;
  55.      cout<<"Its a Floating Point Value";
  56.      //break; 
  57.      }
  58.    else
  59.      {
  60.     input_type=IS_INTEGER;
  61.     cout<<"Its an Integer";
  62.      //break;
  63.      }
  64.    }
  65. cin.get();
  66. cin.get();
  67. cin.get();
  68. return 0;
  69. }
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