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convert cstring to char*
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simply
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Join Date: Dec 2005
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> char *my_char = new char[];
What does this do again?
What does this do again?
To allocate n bytes of storage suitably aligned to represent any array object of that size or smaller. The program can define a function with this function signature that replaces the default version defined by the Standard C++ Library. The required behavior is the same as for operator new(unsigned int). The default behavior is to return operator new(n).
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And if you don't specify an n, then what?
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Originally Posted by Salem 
And if you don't specify an n, then what?
??? What the difference between :
C++ Syntax (Toggle Plain Text)
C++ Syntax (Toggle Plain Text)
Last edited by cikara21; Dec 18th, 2008 at 5:10 am.
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> char *my_char = new char(5);
1 char, initialised to (char)5
> char *my_char = new char[5];
5 chars, initialised with the default ctor
> char *my_char = new char();
1 char, initialised with the default ctor
> char *my_char = new char[];
Does it even compile?
I've no idea what you get if it does.
I'm pretty sure that what it ISN'T is an infinitely large array you can appy write as much data as you want to without incident.
1 char, initialised to (char)5
> char *my_char = new char[5];
5 chars, initialised with the default ctor
> char *my_char = new char();
1 char, initialised with the default ctor
> char *my_char = new char[];
Does it even compile?
I've no idea what you get if it does.
I'm pretty sure that what it ISN'T is an infinitely large array you can appy write as much data as you want to without incident.
about 
I just confuse with the statement below..
To allocate
but thanks..
char *my_char = new char[]; yes. it does compile... I just confuse with the statement below..
To allocate
n bytes of storage suitably aligned to represent any array object of that size or smaller. The program can define a function with this function signature that replaces the default version defined by the Standard C++ Library. The required behavior is the same as for operator new(unsigned int) . The default behavior is to return operator new(n).but thanks..
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