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Converting a char array into numbers

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dj_saxy

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Converting a char array into numbers

Jan 16th, 2005

Is is possible to take an array full of characters and then make the characters into numbers?

i.e. a =1, b=2 etc.

I'm trying to write a program that deciphers ceasar shift ciphers.

Any ideas would be really helpful,

Thanks

dj_saxy

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Narue

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Re: Converting a char array into numbers

Jan 16th, 2005

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
int get_code(char c)
{
  string alpha = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  return static_cast<int>(alpha.find(c));
}
int get_code(char c)
{
  string alpha = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  return static_cast<int>(alpha.find(c));
}

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Join Date: Nov 2004

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dj_saxy

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Re: Converting a char array into numbers

Jan 16th, 2005

OK, i guess that it's a function so it should go at the start, but do i need to change anything, because my compiler doesn't like it...

Thanks for the help though

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Narue

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Re: Converting a char array into numbers

Jan 16th, 2005

>because my compiler doesn't like it...
Well, I was assuming some measure of intelligence on your part. I won't make that mistake in the future:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <cctype>
#include <iomanip>
#include <iostream>
#include <string>
 
using namespace std;
 
int get_code(char c)
{
  string alpha = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  return static_cast<int>(alpha.find(c));
}
 
int main()
{
  string s = "This is a test";
 
  cout<<"Code values of \""<< s <<"\" are:\n";
  for (string::const_iterator it = s.begin(); it != s.end(); ++it) {
    if (isalpha(*it))
      cout<< left << setw(3) << get_code(*it);
  }
  cout<<endl;
}
#include <cctype>
#include <iomanip>
#include <iostream>
#include <string>

using namespace std;

int get_code(char c)
{
  string alpha = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
  return static_cast<int>(alpha.find(c));
}

int main()
{
  string s = "This is a test";

  cout<<"Code values of \""<< s <<"\" are:\n";
  for (string::const_iterator it = s.begin(); it != s.end(); ++it) {
    if (isalpha(*it))
      cout<< left << setw(3) << get_code(*it);
  }
  cout<<endl;
}

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harshchandra harshchandra is offline

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Re: Converting a char array into numbers

Jan 17th, 2005

U can define a function called as " convert "
th prototype will look like this : int convert( char)
for(i=0;i<MAX;i++)
number = convert(a[i]);

int convert(char c)
{ return c - '0' ;
}

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Join Date: Sep 2004

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Narue

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Re: Converting a char array into numbers

Jan 17th, 2005

•

U can define a function called as " convert "
th prototype will look like this : int convert( char)
for(i=0;i<MAX;i++)
number = convert(a[i]);

int convert(char c)
{ return c - '0' ;
}

So, do you just post random replies without reading the original question? Come to think of it, is this trick the only one you know? It seems like the only thing you post.

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