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Problem with string search of an array

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Join Date: Jan 2005

Posts: 2

Reputation: cricket is an unknown quantity at this point

Solved Threads: 0

cricket

Offline

Newbie Poster

Problem with string search of an array

Jan 30th, 2005

I am just learning C/C++. My problem is to determine if a character is or isn't within an array then returning an appropriate message to the user. I've only gotten this far using 'strchr' without much success. Any suggestions or help would be appreciated. Should I be using pointers instead within the function?

Thank you

Program Char Search */

#include<stdio.h>
#include<stdlib.h>
#include<string.h>
char check(char c, char str);

main()

{ char response;
char strg[] = "Array test";
printf("%s\n", strg);

{ Printf("Enter the character you would like to search for.");

Scanf(" %c\n", &response);
}

/*function 'check'*/
{
char check(char str[],char c);
str = strg;
c = response;
scanf("strchr: %s\n",&strg);

if strchr=c
printf("The character is %s\n",c);
}

return 0;
}

•

Join Date: Jan 2005

Posts: 45

Reputation: Siersan is an unknown quantity at this point

Solved Threads: 2

Siersan

Offline

Speaker of Truth

Re: Problem with string search of an array

Jan 30th, 2005

Using strchr it would look something like this.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
int check(char str[], int search);
 
int main(void)
{
  char buf[BUFSIZ];
  int ch;
 
  printf("Enter a string: ");
  fflush(stdout);
  if (fgets(buf, sizeof buf, stdin) == NULL)
    return EXIT_FAILURE;
 
  printf("Enter a character to search for: ");
  fflush(stdout);
  if ((ch = getchar()) == EOF)
    return EXIT_FAILURE;
 
  if (check(buf, ch))
    printf("%c was found\n", ch);
  else
    printf("%c was not found\n", ch);
 
  return EXIT_SUCCESS;
}
 
int check(char str[], int search)
{
  return strchr(str, search) != NULL;
}
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int check(char str[], int search);

int main(void)
{
  char buf[BUFSIZ];
  int ch;

  printf("Enter a string: ");
  fflush(stdout);
  if (fgets(buf, sizeof buf, stdin) == NULL)
    return EXIT_FAILURE;

  printf("Enter a character to search for: ");
  fflush(stdout);
  if ((ch = getchar()) == EOF)
    return EXIT_FAILURE;

  if (check(buf, ch))
    printf("%c was found\n", ch);
  else
    printf("%c was not found\n", ch);

  return EXIT_SUCCESS;
}

int check(char str[], int search)
{
  return strchr(str, search) != NULL;
}

You can also do it manually if you want.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
int check(char str[], int search)
{
  int i;
 
  for (i = 0; str[i] != '\0'; i++) {
    if (search == str[i])
      return 1;
  }
 
  return 0;
}
int check(char str[], int search)
{
  int i;

  for (i = 0; str[i] != '\0'; i++) {
    if (search == str[i])
      return 1;
  }

  return 0;
}

•

Join Date: Jan 2005

Posts: 2

Reputation: cricket is an unknown quantity at this point

Solved Threads: 0

cricket

Offline

Newbie Poster

Re: Problem with string search of an array

Jan 30th, 2005

Thank you very much. I will try this.

•

Join Date: Oct 2004

Posts: 3,955

Reputation: vegaseat is just really nice

Solved Threads: 917

vegaseat

Online

DaniWeb's Hypocrite

Re: Problem with string search of an array

Jan 31st, 2005

[QUOTE=Siersan]Using strchr it would look something like this.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
 
int check(char str[], int search);
 
int main(void)
{
  char buf[BUFSIZ];
  int ch;
 
  printf("Enter a string: ");
  fflush(stdout);
  if (fgets(buf, sizeof buf, stdin) == NULL)
    return EXIT_FAILURE;
 
  printf("Enter a character to search for: ");
  fflush(stdout);
  if ((ch = getchar()) == EOF)
    return EXIT_FAILURE;
 
  if (check(buf, ch))
    printf("%c was found\n", ch);
  else
    printf("%c was not found\n", ch);
 
  return EXIT_SUCCESS;
}
 
int check(char str[], int search)
{
  return strchr(str, search) != NULL;
}
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int check(char str[], int search);

int main(void)
{
  char buf[BUFSIZ];
  int ch;

  printf("Enter a string: ");
  fflush(stdout);
  if (fgets(buf, sizeof buf, stdin) == NULL)
    return EXIT_FAILURE;

  printf("Enter a character to search for: ");
  fflush(stdout);
  if ((ch = getchar()) == EOF)
    return EXIT_FAILURE;

  if (check(buf, ch))
    printf("%c was found\n", ch);
  else
    printf("%c was not found\n", ch);

  return EXIT_SUCCESS;
}

int check(char str[], int search)
{
  return strchr(str, search) != NULL;
}

Just a friendly note:
fgets() will append a \n to the string, if you then just press enter at the character search prompt you will find the \n. The answer will be: was found

May 'the Google' be with you!

•

Join Date: Sep 2004

Posts: 7,580

Reputation: Narue has a reputation beyond repute

Solved Threads: 709

Narue

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Code Goddess

Re: Problem with string search of an array

Jan 31st, 2005

>if you then just press enter at the character search prompt you will find the \n.
That's reasonable (and expected) behavior. Let's say you want to test for exceptionally long lines:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
while (fgets(buffer, sizeof buffer, stdin) != NULL && !check(buffer, '\n')) {
  /* Append buffer to a dynamic string */
}
while (fgets(buffer, sizeof buffer, stdin) != NULL && !check(buffer, '\n')) {
  /* Append buffer to a dynamic string */
}

If you don't want to find the newline, then remove it before the test, or verify the value of the search character as being neither EOF nor '\n'.