Current Working directory

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Current Working directory

 
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  #1
Feb 21st, 2009
Hi All,
I'm using XAMMP server in USB stick and have Web project in this structure:
F:\xampplite\htdocs\projects\Elijah

So my current working DIR is elijah. However, I don't want to write the long path "../projects/elijah/elijah.css" when linking css file or using images. I would like to use something like a function that will retrieve current working directory so that path will be
"The_function_to_get_DIR/elijah.css" I want the root to be seen virtually as elijah

Thanks for your help, and I'm ready to clarify wherever there's ambiguity
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Re: Current Working directory

 
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  #2
Feb 21st, 2009
php Syntax (Toggle Plain Text) 
  1. include("./thisfile");
html Syntax (Toggle Plain Text) 
  1. <link rel="stylesheet" type="text/css" media="screen" href="./style.css">
php Syntax (Toggle Plain Text) 
  1. $basedir=substr("$_SERVER['SCRIPT_FILENAME']",0,strripos("$_SERVER['SCRIPT_FILENAME'],"/",0));
  2.  
just some of the diff ways to find the same thing
Last edited by almostbob; Feb 21st, 2009 at 3:50 pm.
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Re: Current Working directory

 
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  #3
Feb 21st, 2009
Can you comment on code so as I ca understand better
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Re: Current Working directory

 
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  #4
Feb 21st, 2009
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Originally Posted by evstevemd View Post
Can you comment on code so as I ca understand better
First two, . is the default for current folder, as .. is parent
third one

take the current script name as known to the server and break it at the last / character
substring of the server array, from position 0 to the position of the last /
this gives the documentroot path to the current folder
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Re: Current Working directory

 
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  #5
Feb 22nd, 2009
Ok I have this code:
How do I link the CSS file using PHP in that, Instead of full CSS path I will have href="$paths/elijah.css" ?

Thanks for your valuable reply

php Syntax (Toggle Plain Text) 
  1. html>
  2. 	<head>
  3. 		<title>Test Page - Elijah Ministries</title>
  4. 		<?php
  5. 				$paths = getcwd();
  6. 				print $paths;
  7. 				?> 
  8. 		<link rel = "sheet" style = "text/css" href = "/project/elijah/elijah.css"  />
  9. 	</head>
  10.  
  11. 	<body>
  12. 		<table width="100%" height="450px" bgcolor="silver">
  13. 			<tr>
  14. 				<td class="top_header">
  15.  
  16. 				</td>
  17. 			</tr>
  18. 		</table>
  19.  
  20.  
  21. 	</body>
  22.  
  23. <html>
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Re: Current Working directory

 
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  #6
Feb 23rd, 2009
May be question was too vague, here is another way,
I get path of current DIR via php script
php Syntax (Toggle Plain Text) 
  1. <?php
  2. $paths = getcwd();
  3. ?>

Then I want to use this path when linking all my image and css file
Here is my code linking the CSS file
php Syntax (Toggle Plain Text) 
  1. <link rel = "sheet" style = "text/css" href = "/project/elijah/elijah.css"  />

How do I link the CSS file using $paths that is <link rel = "sheet" style = "text/css" href = "$paths/elijah.css" />

Thanks for your invaluable help
Last edited by peter_budo; Feb 25th, 2009 at 8:04 pm. Reason: Closing tag is [/code] not [/php]
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Re: Current Working directory

 
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  #7
Feb 23rd, 2009
Your code
html Syntax (Toggle Plain Text) 
  1. <link rel = "sheet" style = "text/css" href = "/project/elijah/elijah.css" />
shouild be
html Syntax (Toggle Plain Text) 
  1. <link rel="stylesheet" type="text/css" href="/project/elijah/elijah.css" />
even before you make it
html Syntax (Toggle Plain Text) 
  1. <link rel="stylesheet" type="text/css" href="./elijah.css" />
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Re: Current Working directory

 
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  #8
Feb 23rd, 2009
Yeah, that error is obvious, but I failed to see it. Thanks.
It is that I'm refactoring my old HTML code to incorporate PHP. However, My working folder in XAMPP ("/project/elijah/elijah.css") will not be valid when kept on server where path will be something like "/elijah.css". So I want to use path to avoid changing things in file, which is tedious work
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