DaniWeb Forum Index > Web Development > PHP

send email on mysql db update

Please support our PHP advertiser: PostgreSQL or MySQL? Compare and contrast the two most popular open source databases

Thread Solved

•

Join Date: Feb 2008

Posts: 347

Reputation: kevin wood is an unknown quantity at this point

Solved Threads: 1

kevin wood kevin wood is offline

Offline

Posting Whiz

send email on mysql db update

Mar 9th, 2009

i am trying to get this code to work but there is something wrong with the array (not to good at these). the main part of the code works it is sending out the email but only ever to one registered user.

here is the code i have so far.

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
	$query = "SELECT email FROM emails";
	$result = mysql_query($query) or die(mysql_error());
 
	while($row = mysql_fetch_array($result)) {
 
	$contactemail = $row['email'];
 
 
 
 
	// Contacts
	//$replyName = $merc_replyId;
	//$replyEmail = $merc_replyAddress;
 
	$replyName = "PiPonliine";
	$replyEmail = "info@piponline.info";
 
	$contactname = "";
 
 
	// Subject
	$subject = "Website Update";
 
	// Headers
	$headers = "MIME-Version: 1.0" . PHP_EOL;
	$headers .= "Content-type: text/html; charset=iso-8859-1" . PHP_EOL;
	$headers .= "From: ".$replyName." <".$replyEmail.">" . PHP_EOL;
	$headers .= "BCC: ".$contactname." <".$contactemail.">\r\n" . PHP_EOL;
 
 
	mail($contactemail, $subject, $message, $headers);
	}
  echo "$contactemail";
  echo "<h2>Email notification sent</h2>";
  echo "<h2>1 record added</h2>";
 
  mysql_close($con);
	$query = "SELECT email FROM emails";
	$result = mysql_query($query) or die(mysql_error());

	while($row = mysql_fetch_array($result)) {
	
	$contactemail = $row['email'];
	



	// Contacts
	//$replyName = $merc_replyId;
	//$replyEmail = $merc_replyAddress;
	
	$replyName = "PiPonliine";
	$replyEmail = "info@piponline.info";

	$contactname = "";
	

	// Subject
	$subject = "Website Update";

	// Headers
	$headers = "MIME-Version: 1.0" . PHP_EOL;
	$headers .= "Content-type: text/html; charset=iso-8859-1" . PHP_EOL;
	$headers .= "From: ".$replyName." <".$replyEmail.">" . PHP_EOL;
	$headers .= "BCC: ".$contactname." <".$contactemail.">\r\n" . PHP_EOL;
	

	mail($contactemail, $subject, $message, $headers);
	}
  echo "$contactemail";
  echo "<h2>Email notification sent</h2>";
  echo "<h2>1 record added</h2>";

  mysql_close($con);

•

Join Date: Feb 2009

Posts: 83

Reputation: ahmksssv is an unknown quantity at this point

Solved Threads: 7

ahmksssv

Offline

Junior Poster in Training

Re: send email on mysql db update

Mar 9th, 2009

[QUOTE=kevin wood;821441]i am trying to get this code to work but there is something wrong with the array (not to good at these). the main part of the code works it is sending out the email but only ever to one registered user.

Hi..
i dont know the exact solution....but, try to do this...

1) if there is any id in database, try to using id by incrementing.......
2) try to use FOREACH instead of while......

this is just try, i dont know the exact way.....

•

Join Date: Feb 2008

Posts: 347

Reputation: kevin wood is an unknown quantity at this point

Solved Threads: 1

kevin wood kevin wood is offline

Offline

Posting Whiz

Re: send email on mysql db update

Mar 9th, 2009

a foreach loop will need to start with a while loop and i do not see the need to use the id of the table as i only need to loop through the email address and user these to send the email.

•

Join Date: Nov 2007

Posts: 3,748

Reputation: nav33n is a jewel in the rough

Solved Threads: 331

nav33n

Offline

Senior Poster

Re: send email on mysql db update

Mar 10th, 2009

@Kevin wood, Your script seems fine.
Try this.

 Help with Code Tags 
 php Syntax (Toggle Plain Text) 
	$query = "SELECT email FROM emails";
	$result = mysql_query($query) or die(mysql_error());
 
	while($row = mysql_fetch_array($result)) {
 
	$emailaddress[] = $row['email'];
	}
 
 
	// Contacts
	//$replyName = $merc_replyId;
	//$replyEmail = $merc_replyAddress;
	$i=0;
	foreach($emailaddress as $contactemail) {
	$replyName = "PiPonliine";
	$replyEmail = "info@piponline.info";
 
	$contactname = "";
 
 
	// Subject
	$subject = "Website Update";
 
	// Headers
	$headers = "MIME-Version: 1.0" . PHP_EOL;
	$headers .= "Content-type: text/html; charset=iso-8859-1" . PHP_EOL;
	$headers .= "From: ".$replyName." <".$replyEmail.">" . PHP_EOL;
	$headers .= "BCC: ".$contactname." <".$contactemail.">\r\n" . PHP_EOL;
 
 
	mail($contactemail, $subject, $message, $headers);
	$i++;
	}
  echo "$contactemail"; //this will print only 1 email address, which is the last one
  echo "<h2>Email notification sent</h2>";
  echo "<h2>".$i." mails sent</h2>";
	$query = "SELECT email FROM emails";
	$result = mysql_query($query) or die(mysql_error());

	while($row = mysql_fetch_array($result)) {
	
	$emailaddress[] = $row['email'];
	}


	// Contacts
	//$replyName = $merc_replyId;
	//$replyEmail = $merc_replyAddress;
	$i=0;
	foreach($emailaddress as $contactemail) {
	$replyName = "PiPonliine";
	$replyEmail = "info@piponline.info";

	$contactname = "";
	

	// Subject
	$subject = "Website Update";

	// Headers
	$headers = "MIME-Version: 1.0" . PHP_EOL;
	$headers .= "Content-type: text/html; charset=iso-8859-1" . PHP_EOL;
	$headers .= "From: ".$replyName." <".$replyEmail.">" . PHP_EOL;
	$headers .= "BCC: ".$contactname." <".$contactemail.">\r\n" . PHP_EOL;
	

	mail($contactemail, $subject, $message, $headers);
	$i++;
	}
  echo "$contactemail"; //this will print only 1 email address, which is the last one
  echo "<h2>Email notification sent</h2>";
  echo "<h2>".$i." mails sent</h2>";

This definitely works. (I tried with 3 email addresses)