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only difference in return type

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Join Date: Nov 2006

Posts: 42

Reputation: bluebird is an unknown quantity at this point

Solved Threads: 0

bluebird

Offline

Light Poster

only difference in return type

Mar 22nd, 2009

hello everybody!

As far as I understand, the functions that are only different in return type are not allowed.
But how can I write the program for the following question?
*****************************************
Create two classes DM and DB which store the value of distances. DM stores distances in meters and centimeters and DB in feet and inches. Write a program that can read values for the class objects and add one object of DM with another object of DB. Use a friend function to carry out the addition operation. The object that stores the result may be a DM object or DB object, depending on the units in which the results are required. The display should be in the format of feet and inches or meters and centimeters depending on the object on display.
****************************************
Here is my program. It does not work.
please help me. Thanks in advance.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include<iostream.h>
 
class DB;
class DM
{
float   me,cm;
public:
DM()
{}
 
 
DM(float m,float c)
{
 me=m;
 cm=c;
}
friend DB operator+(DM,DB);
 
};
 
class DB
{
float ft;
float inches;
 
public:
DB()
{}
 
DB(float f,float in)
{
ft=f;
inches=in;
}
void display()
{
 cout<<"\nfeet:"<<ft;
 cout<<"\ninches:"<<inches;
 }
 
 
 
 
friend  DB operator+(DM,DB);
 
 
};
 
 
DB operator+(DM m, DB b)
{
 DB b2;
 m.cm+=m.me*10;
 b.inches+=b.ft*12;
 b2.inches=m.cm*0.3937+b.inches;
 while(b2.inches>=12)
 {
  b2.ft++;
  b2.inches-=12;
 }
 return b2;
}
 
int main()
{
DM dm1 (1,9);
DB db1(1,1);
DB db2;
db2=dm1+db1;
db2.display();
 
return 0;
}
#include<iostream.h>

class DB;
class DM
{
float   me,cm;
public:
DM()
{}


DM(float m,float c)
{
 me=m;
 cm=c;
}
friend DB operator+(DM,DB);

};

class DB
{
float ft;
float inches;

public:
DB()
{}

DB(float f,float in)
{
ft=f;
inches=in;
}
void display()
{
 cout<<"\nfeet:"<<ft;
 cout<<"\ninches:"<<inches;
 }




friend  DB operator+(DM,DB);


};


DB operator+(DM m, DB b)
{
 DB b2;
 m.cm+=m.me*10;
 b.inches+=b.ft*12;
 b2.inches=m.cm*0.3937+b.inches;
 while(b2.inches>=12)
 {
  b2.ft++;
  b2.inches-=12;
 }
 return b2;
}

int main()
{
DM dm1 (1,9);
DB db1(1,1);
DB db2;
db2=dm1+db1;
db2.display();

return 0;
}

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Join Date: May 2008

Posts: 128

Reputation: kenji is an unknown quantity at this point

Solved Threads: 10

kenji

Offline

Junior Poster

Re: only difference in return type

Mar 22nd, 2009

You need to return a reference to the overloaded operator.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
ie. friend operator+(const DM &, const DB &);
{
     /*Declare a new class*/
    /*your code*/
    return newClass;
}
ie. friend operator+(const DM &, const DB &);
{
     /*Declare a new class*/
    /*your code*/
    return newClass;
}

Also you need to code an overloaded assignment operator.

Last edited by kenji; Mar 22nd, 2009 at 4:44 pm.

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