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Drop 0 in floating point variable 0.233

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Join Date: Jan 2005

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dallin

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Drop 0 in floating point variable 0.233

Feb 18th, 2005

I'm using visual studio .net c++ and I'm looking for the easiest code to drop the 0 on 0.233 to .233 when displaying floating point variable on screen. Thanks.

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Join Date: Sep 2004

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Narue

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Re: Drop 0 in floating point variable 0.233

Feb 18th, 2005

My first question is: why bother? Unless there's a trick that's slipped my mind, you need to copy the value into a string and then remove the first character:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
#include <sstream>
 
using namespace std;
 
int main()
{
  double f = 0.123;
  ostringstream sout;
 
  sout<< f;
  string s = sout.str();
  cout<< s.substr(1, s.length()) <<endl;
}
#include <iostream>
#include <sstream>

using namespace std;

int main()
{
  double f = 0.123;
  ostringstream sout;

  sout<< f;
  string s = sout.str();
  cout<< s.substr(1, s.length()) <<endl;
}

That's hardly worth the effort for something so small as removing a 0 for no apparent benefit.

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Join Date: Jan 2005

Posts: 14

Reputation: dallin is an unknown quantity at this point

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dallin

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Re: Drop 0 in floating point variable 0.233

Feb 19th, 2005

I agree, however, I believe its for my educational benefit only and my grade. I've tried it and like it, however, what additional code do I need to limit the digits displayed to 3? Found it, I think I'm taking care of. Thanks!

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Join Date: Mar 2004

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BountyX

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Code Guru

Re: Drop 0 in floating point variable 0.233

Feb 19th, 2005

For the benifits of others:

You must include <iomanip> to use this manipulator.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
 
// setprecision example
#include <iostream>
#include <iomanip>
using namespace std;
int main () { 
double f =3.14159; cout << setprecision (5) << f << endl; 
cout << setprecision (9) << f << endl; 
return 0;
}
 
// setprecision example
#include <iostream>
#include <iomanip>
using namespace std;
int main () { 
double f =3.14159; cout << setprecision (5) << f << endl; 
cout << setprecision (9) << f << endl; 
return 0;
}