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Karatsuba Wrong Answer After 6 Decimal digits
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Join Date: Feb 2008
Posts: 40
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Hello to all, i have code karatsuba but it is not compute correctly after 6 decimal digits.
For example, 123456 * 654321 * 80779853 but my program display wrong answer.
Thanks.
C++ Syntax (Toggle Plain Text)
#include <iostream> #include <vector> #include <algorithm> #include <limits> #include <cmath> #include <cctype> // ================================================ using namespace std; typedef unsigned long ulong; void userInput(ulong&, ulong&); int numberLength(ulong); ulong leftSplit(ulong, int); ulong rightSplit(ulong, int); int numberPower(const ulong&, const ulong&, const ulong&); ulong Karatsuba(const ulong&, const ulong&); const int MINLENGTH = 5; // ============================================= int main(int argc, char *argv[]) { ulong first(0), second(0); while (1) { userInput(first, second); cout << "The result of " << first << " * " << second << " : " << Karatsuba(first, second); } return 0; } // ============================================= void userInput(ulong& first, ulong& second) { cout << "\nEnter First Number : "; cin >> first; while (cin.fail()) { cin.clear(); cin.ignore(std::numeric_limits<int>::max(), '\n'); cout << "\nEnter First Number : "; cin >> first; } cout << "\nEnter Second Number : "; cin >> second; while (cin.fail()) { cin.clear(); cin.ignore(std::numeric_limits<int>::max(), '\n'); cout << "\nEnter Second Number : "; cin >> second; } } // ============================================= int numberLength(ulong number) { int len(0); // Check length of integer algorithm // * 10 = To shift left 1 digit in number // % 10 = To get last digit of number while (number >= 1) { number /= 10; ++len; } return len; } // ============================================= ulong leftSplit(ulong number, int length) { int middle = length / 2; vector<int> remainder(0); // To get most significant digit while (number >= 10) { remainder.push_back(number % 10); number /= 10; } std::reverse(remainder.begin(), remainder.end()); ulong result(number);int remLoop(0); for (int loop = 0;loop < middle - 1;++loop) { if (remLoop < static_cast<int>(remainder.size())) { result = result * 10 + remainder[remLoop]; } ++remLoop; } return result; } // ============================================= ulong rightSplit(ulong number, int length) { int remainder(0), multiply(1); ulong result(0); for (int loop = 0; loop < length;++loop) { remainder = number % 10; number /= 10; result += remainder * multiply ; multiply *= 10; } return result; } // ============================================= int numberPower(const ulong& first, const ulong& x1, const ulong& y1) { int lengthPower(1); const int base(10); while (first - y1 != (x1 * (pow(static_cast<double>(base), static_cast<int>(lengthPower)))) ) { ++lengthPower; } return lengthPower; } // ============================================= ulong Karatsuba(const ulong& first, const ulong& second) { if (first != 0 && second != 0) { if (numberLength(first) > MINLENGTH && numberLength(second) > MINLENGTH) { ulong x1 = leftSplit(first, numberLength(first)); ulong y1 = leftSplit(second, numberLength(second)); ulong x0 = rightSplit(first, numberLength(first) - numberLength(x1)); ulong y0 = rightSplit(second, numberLength(second) - numberLength(y1)); int lengthPower = numberPower(first, x1, x0); unsigned long X = Karatsuba(x1, y1); int length = numberLength(X); ulong Y = Karatsuba(x0, y0); ulong Z = Karatsuba(x1 + x0, y1 + y0); Z = Z - X - Y; return (X * static_cast<unsigned long>(pow(10.0, 2.0 * lengthPower))) + (Z * static_cast<unsigned long>(pow(10.0, lengthPower))) + Y; } else { return first * second; } } else { return 0; } } // =============================================
For example, 123456 * 654321 * 80779853 but my program display wrong answer.
Thanks.
Take into account that
but
Try
Otherwise try one of big int class libraries...
C++ Syntax (Toggle Plain Text)
123456 * 654321 * 80779853 == 6525384681074833728
std::numeric_limits<long>::max() is equal to 2147483647 on 32-bit processors (integer overflow is not detected).Try
long long type (it's supported by modern compilers now), its max value is 9223372036854775807.Otherwise try one of big int class libraries...
No, I have not bigint libraries. I have no need in these libraries.
Have you ever seen the phrase "Search Google"?
Try this (for bigint library) and you will get lots of links, for example (from the 1st page):
http://mattmccutchen.net/bigint/
http://en.wikipedia.org/wiki/Arbitra...ion_arithmetic
http://math.libtomcrypt.com/
and many many others...
Have you ever seen the phrase "Search Google"?
Try this (for bigint library) and you will get lots of links, for example (from the 1st page):
http://mattmccutchen.net/bigint/
http://en.wikipedia.org/wiki/Arbitra...ion_arithmetic
http://math.libtomcrypt.com/
and many many others...
It seems you don't understand that no need in Karatsuba algorithm while you are trying to get unsigned long results: use built-in arithmetic - that's all. But if the result is greater than unsigned long max value you can't return unsigned long value from Karatsuba function! No need in Karatsuba algorithm if you have bigint library: there is bigint multiplication in every such library.
Therefore all your codes are senseless from the beginning. Start your design from the big int representation. See, for example, http://en.wikipedia.org/wiki/Karatsuba_algorithm.
Apropos: the simplest (but ineffective) arbitrary precision integer representation is a simple text string. Try to implement Karatsuba algorithm for this representation.
Therefore all your codes are senseless from the beginning. Start your design from the big int representation. See, for example, http://en.wikipedia.org/wiki/Karatsuba_algorithm.
Apropos: the simplest (but ineffective) arbitrary precision integer representation is a simple text string. Try to implement Karatsuba algorithm for this representation.
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