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Form load based on condition

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Join Date: Dec 2008

Posts: 11

Reputation: krm08 is an unknown quantity at this point

Solved Threads: 0

krm08

Offline

Newbie Poster

Form load based on condition

Jun 17th, 2009

Hi experts,
I'm extreme beginner in PHP.My problem is that,i've an html page and there's combobox on it,I want to load the form according to the selection of items.
The html page is

 Help with Code Tags 
 html Syntax (Toggle Plain Text) 
<form action="search.php" method="post">
<select name="option" size="1">
<option value="1">value1</option>
<option value="2">value2</option>
<option value="3">value3</option>
<option value="4">value4</option>
</select>
<input type="submit" />
</form>
<form action="search.php" method="post">
<select name="option" size="1">
<option value="1">value1</option>
<option value="2">value2</option>
<option value="3">value3</option>
<option value="4">value4</option>
</select>
<input type="submit" />
</form>

and the search.php:

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 php Syntax (Toggle Plain Text) 
<?php
 
$v = $_POST['option'];
 
if($v==1)
{
	?>
	<form method="get" action="page1.php"></form>
 
	<?php
}
if($v==2)
{
	?>
	<form method="get" action="page2.php"></form>
 
	<?php
}
if($v==3)
{
	?>
	<form method="get" action="page3.php"></form>
 
	<?php
}
if($v==4)
{
	?>
	<form method="get" action="page4.php"></form>
 
	<?php
}
?>
<?php

$v = $_POST['option'];

if($v==1)
{
	?>
	<form method="get" action="page1.php"></form>
	
	<?php
}
if($v==2)
{
	?>
	<form method="get" action="page2.php"></form>
	
	<?php
}
if($v==3)
{
	?>
	<form method="get" action="page3.php"></form>
	
	<?php
}
if($v==4)
{
	?>
	<form method="get" action="page4.php"></form>
	
	<?php
}
?>

I want to navigate through the page according to the value in the variable v.
Thanks in advance.

•

Join Date: Jun 2009

Posts: 68

Reputation: djjjozsi is an unknown quantity at this point

Solved Threads: 10

djjjozsi

Offline

Junior Poster in Training

Re: Form load based on condition

Jun 17th, 2009

 Help with Code Tags 
 php Syntax (Toggle Plain Text) 
<?php
$forms=array(
"1"=>"page1.php",
"2"=>"page2.php",
"3"=>"page3.php");
?>
<?php
$forms=array(
"1"=>"page1.php",
"2"=>"page2.php",
"3"=>"page3.php");
?>

build the form:
<form action="" method="post" name="Form">
...
select box <--
...</form>

On submit, check if the posted value is in the array:

 Help with Code Tags 
 php Syntax (Toggle Plain Text) 
<?php
if ( !empty( $_POST["option"] ) ) {
    $option = $_POST["option"];
    if ( !empty( $forms[$option] ) ) {
 
        ?>	<form method="get" action="<?php echo htmlspecialchars( $form[$option] );
        ?>"></form><?php
    } else {
        print "You have selected a non existing option...";
    } 
} 
 
?>
<?php
if ( !empty( $_POST["option"] ) ) {
    $option = $_POST["option"];
    if ( !empty( $forms[$option] ) ) {

        ?>	<form method="get" action="<?php echo htmlspecialchars( $form[$option] );
        ?>"></form><?php
    } else {
        print "You have selected a non existing option...";
    } 
} 

?>

Last edited by djjjozsi; Jun 17th, 2009 at 3:17 am.

•

Join Date: Dec 2008

Posts: 11

Reputation: krm08 is an unknown quantity at this point

Solved Threads: 0

krm08

Offline

Newbie Poster

Re: Form load based on condition

Jun 17th, 2009

Thanks djjjozsi,
but my problem is not solved,
The form doesn't works

 Help with Code Tags 
 php Syntax (Toggle Plain Text) 
<form method="get" action="<?php echo $forms[$option] ;
        ?>"></form><?php
<form method="get" action="<?php echo $forms[$option] ;
        ?>"></form><?php

but the arrays works.
It doesn't navigate to the page specified in the array

•

Join Date: Jun 2009

Posts: 68

Reputation: djjjozsi is an unknown quantity at this point

Solved Threads: 10

djjjozsi

Offline

Junior Poster in Training

Re: Form load based on condition

Jun 17th, 2009

if the user posted the form you want to redirect to the specified page?

header("Location: ". $forms[$option] );

notice that, you should not print or have outputted html codes to the display before this header location.