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Idea

 
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  #1
Jun 26th, 2009
I m trying to find idea to change like from 1 to one and 2 to two and 3 three from 1 to 999 i m had an idea to do like a string with information etc ? but i want better idea so i dunno how to do it lolz.
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Re: Idea

 
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  #2
Jun 26th, 2009
Think Check Writing Program
C Syntax (Toggle Plain Text) 
  1. ary [] = { Zero, One, ...., Nineteen Twenty, Thirty, Fourty, ... Ninety, Hundred,  Thousand };
  2.  
  3. if (n <= 19)
  4.      ary[n]
  5. else if (n < 100)      // 20...99
  6.      j = ary[  (n / 10) + 18 ]          // Get 10's
  7.      k = ary[ n % 10 ]                   // get 1's  if zero ignore
  8.      if ( k == 0) then ignore
  9.  
  10. etc.
Last edited by wildgoose; Jun 26th, 2009 at 7:23 pm. Reason: corrections
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Re: Idea

 
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  #3
Jun 26th, 2009
What the poster above posted might look confusing, but what he is saying is a good way of doing this: Each String in the array will be the "name" of the index it is at. So index 0 of the array is named zero, and so on. This means in order to find the name of "20", you would use array[20] and it would return "twenty" since that is what you stored there.

The implementation is a little different - for example in C, I think an array of Strings is actually a 2D array of chars, but you get the point, I hope.
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Re: Idea

 
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  #4
Jun 26th, 2009
Ah, 20 was on the edge, but 21 would involve hitting the list twice.
Once for "twenty" and again for "one" then glue the two halves together for "twenty-one"
30 would be "thirty" since no ones remainder on the modulus then no second noun.
134 would be "One" + "Hundred" "Thirty" - "Four"

So twenty-seven ASCII nouns would cover one thousand numbers.
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Re: Idea

 
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  #5
Jun 26th, 2009
but i still i would have to do tests from 1 to nineteen
whish would be alot of tests i thought of this idea but is there another way i could do it by
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Re: Idea

 
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  #6
Jun 26th, 2009
No, For a number up to 999 you have 4 tests?

If number is 0 to 20 then use it as a string table index.
if greater then that then turn it into 10's and 1's
And use them as separate indexes!
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Re: Idea

 
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  #7
Jun 26th, 2009
C Syntax (Toggle Plain Text) 
  1. char *szNoun[]= {
  2.    "zero", "one", "two", "three", "four", "five", "six", "seven",
  3.    "eight", "nine", "ten",
  4.    "eleven", "twelve", "thirteen", "fourteen", "fifteen",
  5.    "sixteen", "seventeen", "eighteen", "nineteen",
  6.     "twenty", "thirty", "fourty", "fifty", "sixty", "seventy",
  7.     "eighty", "ninety", "hundred", "thousand" };
  8.  
  9. // n is number
  10. if ( n <= 20)
  11.         print szNoun[ n ];
  12. else if (n < 100)
  13.         j = n / 10;       // { 2...9 }
  14.         k = n % 10;    // { 0...9 }
  15.         print szNoun[ j + 18 ];
  16.         if ( k != 0 )
  17.             print "-"    szNoun[k];
  18.  
  19. // and the rest for you to figure out!
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Re: Idea

 
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  #8
Jun 26th, 2009
till now i made but i tried with 21 it didnt work out
C Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <string.h>
  3. #define DEBUG
  4. char *string[]= {
  5.      "zero","one","two","three","four","five","six","seven","eight","nine","ten","eleven","tweleve","thirteen","fourteen","fifteen",
  6.      "sixten","sevten","eighteen","nineteen"
  7.      };
  8. char *string2[]= {
  9.      "twenty","thirty","fourty","fifty","sexty","seventy","eighty","nighty","hundreed"
  10.      };
  11. //from int to array and return char string
  12. char *IntToarray(int num)
  13. {
  14.      char *pch;
  15.      int j=0;
  16.      if(num>0 || num<=19)
  17.               pch=string[num];
  18.      else if(num>=20 || num<=100) {
  19.               j=num %10;
  20. #ifdef DEBUG
  21.               printf("number of j is %d",j);//it should out here 1 and it didnt 
  22.               printf("number of j is %d",j);
  23.               if(j==1)
  24.                   puts("dude so cool");
  25. #endif
  26.               getchar();
  27.               num=num %10;
  28.               strcat(string2[num]," ");
  29.               strcat(string2[num],string[j]);
  30.               }    
  31. }
  32. int main(void)
  33. {
  34.     char *pch;
  35.     pch=IntToarray(21);
  36.     //puts(pch);
  37.     getchar();
  38.     return 0;
  39. }
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Re: Idea

 
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  #9
Jun 26th, 2009
i dunno how its possible to do it with 1 string only like if i get 20 or thirty fourty fifty etc etc i think that should be in a array itself so i get the reminder by j then after that cancnate it to the string2
then as for 100 and up i have to do extra work but i will figure that out i just wanna fix from 20 to 99 first then do from 100 to 999
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Re: Idea

 
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  #10
Jun 26th, 2009
You really need the dwarf array for optimization.
you have a math bug.
C Syntax (Toggle Plain Text) 
  1. char szBuf[ 80 ];
  2. strcpy( szBuf, string1[ num ];
  3.  
  4.      else if(num>=20 || num<100) {
  5.               j=num %10;
  6. #ifdef DEBUG
  7.               printf("number of j is %d",j);//it should out here 1 and it didnt 
  8.               printf("number of j is %d",j);
  9.               if(j==1)
  10.                   puts("dude so cool");
  11. #endif
  12.               getchar();
  13.               num=num / 10;
  14.               strcpy( szBuf, string2[ num ] );
  15.               if (j)
  16.              {
  17.                  strcat( szBuf, "-" );
  18.                  strcat( szBuf, string1[ j ] );
  19.               }
  20.            }
  21.  
  22. printf szBuf
Last edited by wildgoose; Jun 26th, 2009 at 9:47 pm. Reason: correction
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