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Join Date: Mar 2005
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What do you use to parse the url?

  #1  
Mar 31st, 2005
I wouldn't even consider myself a rookie with javascript but know it can be done, so thanks for any help.

What function would I use to have javascript read the page it is on, grab the url which is like:
http://site.com/boards/index.php?sho...37&mode=linear

and say if the url includes "mode=linear" then apply this style sheet?

Thanks!
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Join Date: Dec 2004
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Re: What do you use to parse the url?

  #2  
Mar 31st, 2005
I suppose you could do a
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     somevariable = window.location;

and then do a substr or substring on the url, and see if it's in there. There might be an easier way, but that's probably how I'd do it.
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Re: What do you use to parse the url?

  #3  
May 17th, 2007
Well, try this function, it should be working.
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javascript Syntax (Toggle Plain Text) 
  1. function parseURL(buffer) {
  2.   var result = { };
  3.   result.protocol = "";
  4.   result.user = "";
  5.   result.password = "";
  6.   result.host = "";
  7.   result.port = "";
  8.   result.path = "";
  9.   result.query = "";
  10.  
  11.   var section = "PROTOCOL";
  12.   var start = 0;
  13.   var wasSlash = false;
  14.  
  15.   while(start < buffer.length) {
  16.     if(section == "PROTOCOL") {
  17.       if(buffer.charAt(start) == ':') {
  18.         section = "AFTER_PROTOCOL";
  19.         start++;
  20.       } else if(buffer.charAt(start) == '/' && result.protocol.length() == 0) { 
  21.         section = PATH;
  22.       } else {
  23.         result.protocol += buffer.charAt(start++);
  24.       }
  25.     } else if(section == "AFTER_PROTOCOL") {
  26.       if(buffer.charAt(start) == '/') {
  27.     if(!wasSlash) {
  28.           wasSlash = true;
  29.     } else {
  30.           wasSlash = false;
  31.           section = "USER";
  32.     }
  33.         start ++;
  34.       } else {
  35.         throw new ParseException("Protocol shell be separated with 2 slashes");
  36.       }       
  37.     } else if(section == "USER") {
  38.       if(buffer.charAt(start) == '/') {
  39.         result.host = result.user;
  40.         result.user = "";
  41.         section = "PATH";
  42.       } else if(buffer.charAt(start) == '?') {
  43.         result.host = result.user;
  44.         result.user = "";
  45.         section = "QUERY";
  46.         start++;
  47.       } else if(buffer.charAt(start) == ':') {
  48.         section = "PASSWORD";
  49.         start++;
  50.       } else if(buffer.charAt(start) == '@') {
  51.         section = "HOST";
  52.         start++;
  53.       } else {
  54.         result.user += buffer.charAt(start++);
  55.       }
  56.     } else if(section == "PASSWORD") {
  57.       if(buffer.charAt(start) == '/') {
  58.         result.host = result.user;
  59.         result.port = result.password;
  60.         result.user = "";
  61.         result.password = "";
  62.         section = "PATH";
  63.       } else if(buffer.charAt(start) == '?') {
  64.         result.host = result.user;
  65.         result.port = result.password;
  66.         result.user = "";
  67.         result.password = "";
  68.         section = "QUERY";
  69.         start ++;
  70.       } else if(buffer.charAt(start) == '@') {
  71.         section = "HOST";
  72.         start++;
  73.       } else {
  74.         result.password += buffer.charAt(start++);
  75.       }
  76.     } else if(section == "HOST") {
  77.       if(buffer.charAt(start) == '/') {
  78.         section = "PATH";
  79.       } else if(buffer.charAt(start) == ':') {
  80.         section = "PORT";
  81.         start++;
  82.       } else if(buffer.charAt(start) == '?') {
  83.         section = "QUERY";
  84.         start++;
  85.       } else {
  86.         result.host += buffer.charAt(start++);
  87.       }
  88.     } else if(section == "PORT") {
  89.       if(buffer.charAt(start) = '/') {
  90.         section = "PATH";
  91.       } else if(buffer.charAt(start) == '?') {
  92.         section = "QUERY";
  93.         start++;
  94.       } else {
  95.         result.port += buffer.charAt(start++);
  96.       }
  97.     } else if(section == "PATH") {
  98.       if(buffer.charAt(start) == '?') {
  99.     section = "QUERY";
  100.     start ++;
  101.       } else {
  102.     result.path += buffer.charAt(start++);
  103.       }
  104.     } else if(section == "QUERY") {
  105.       result.query += buffer.charAt(start++);
  106.     }
  107.   }
  108.  
  109.   if(section == "PROTOCOL") {
  110.     result.host = result.protocol;
  111.     result.protocol = "http";
  112.   } else if(section == "AFTER_PROTOCOL") {
  113.     throw new ParseException("Invalid url");
  114.   } else if(section == "USER") {
  115.     result.host = result.user;
  116.     result.user = "";
  117.   } else if(section == "PASSWORD") {
  118.     result.host = result.user;
  119.     result.port = result.password;
  120.     result.user = "";
  121.     result.password = "";
  122.   }
  123.  
  124.   return result;
  125. }
  126.  
  127. function ParseException(description) {
  128.     this.description = description;
  129. }
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Re: What do you use to parse the url?

  #4  
May 19th, 2007
I don't unserstand why the Javascript needs to know the url of the calling page. Doesn't the person who wrote both of them already know that?
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