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how to print the address stored by char *

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Join Date: Dec 2007

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Rhohitman

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how to print the address stored by char *

Aug 26th, 2009

cout<< worked out for every other pointer data type but... when char is fed it show the pointed address.....(which every one knows)

but i want to see the address stored in the char pointer how to see it..

i was thinking using [icode] printf() [icode] but ruined out by not knowing what kind of data type is the used to store address...

I am curious in which data type is used to store mem address....
long, int ....

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Join Date: Jun 2009

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Tom Gunn

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Practically a Master Poster

Re: how to print the address stored by char *

Aug 26th, 2009

Most of the time when a programmer prints a char*, he wants a string to be printed, not the address. cout assumes that is what you want and to get around it, you need to cast to a different pointer type. void* is a good choice because an object pointer can be cast to void* safely:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
 
int main()
{
    char const* p = "string";
 
    std::cout << p << '\n'
              << (void*)p << '\n';
}
#include <iostream>

int main()
{
    char const* p = "string";

    std::cout << p << '\n'
              << (void*)p << '\n';
}

On a side note, this is the same as how printf works with the %p modifier. To be 100% safe, the pointer should be cast to void* because that is the type %p expects:

 Help with Code Tags 
 c Syntax (Toggle Plain Text) 
#include <cstdio>
 
int main()
{
    char const* p = "string";
 
    std::printf("%s\n%p\n", p, (void*)p);
}
#include <cstdio>

int main()
{
    char const* p = "string";

    std::printf("%s\n%p\n", p, (void*)p);
}