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Parameters order

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Join Date: Apr 2005

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oberle1515 oberle1515 is offline

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Parameters order

Apr 18th, 2005

Could someone explain parameters a little bit to me. I have to write a program that returns the difference of of two integers.(larger-smaller)

I understand the basis

class FindDifference {
//Main method
public static int difference(int num1, int num2) {

int num1 = 10;
int num2 = 4;

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Join Date: Apr 2005

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nicentral

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Re: Parameters order

Apr 18th, 2005

What do you want to know about parameters? They're basically variables set up in the method declaration that allow you to pass values to the method. If your method is to return something, you would need a return statement. I.e. your method should look like this

public static int difference(int num1, int num2){

return num1 - num2;

}

Andy

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-- Please do not PM me with questions about a thread. If you respond to a thread, then everyone can benefit.

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Re: Parameters order

Apr 18th, 2005

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Originally Posted by nicentral

What do you want to know about parameters? They're basically variables set up in the method declaration that allow you to pass values to the method. If your method is to return something, you would need a return statement. I.e. your method should look like this

public static int difference(int num1, int num2){

return num1 - num2;

}

Andy

to call that method you would do this:
int firstNum = 35;
int secondNum = 5;
ClassName.difference(firstNum,secondNum);

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Join Date: Oct 2004

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Re: Parameters order

Apr 20th, 2005

you always want the largest minus the smallest, here is two ways of doing just that so you don't have to worry or know the order...

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
public class Test
{
	public static void main(String[] args)
	{
		int n1 = 10;
		int n2 = 4;
		System.out.println(difference(n1,n2));
		System.out.println(difference(n2,n1));
		System.out.println(difference(n1,n2));
		System.out.println(difference(n2,n1));
	}
 
	public static int difference(int num1, int num2)
	{
		return num1 > num2 ? num1-num2 : num2-num1;
	}
 
	public static int subtract(int num1, int num2)
	{
		int returnVal;
 
		if (num1 > num2)
		{
			returnVal = num1 - num2;
		}
		else
		{
			returnVal = num2 - num1;
		}
 
		return returnVal;
	}
}
public class Test
{
	public static void main(String[] args)
	{
		int n1 = 10;
		int n2 = 4;
		System.out.println(difference(n1,n2));
		System.out.println(difference(n2,n1));
		System.out.println(difference(n1,n2));
		System.out.println(difference(n2,n1));
	}

	public static int difference(int num1, int num2)
	{
		return num1 > num2 ? num1-num2 : num2-num1;
	}

	public static int subtract(int num1, int num2)
	{
		int returnVal;

		if (num1 > num2)
		{
			returnVal = num1 - num2;
		}
		else
		{
			returnVal = num2 - num1;
		}

		return returnVal;
	}
}

I think that was what you were asking. the difference method is too intuitive so I created a second called subtract with an if statment in there which is hopefully easier to understand

http://www.brangle.com/

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Re: Parameters order

Apr 20th, 2005

What if that's the order it's suppose to be in?

I mean, take for instance this:

-5 - -4 = -1

By your method it would actually turn out to be this:

-4 + 5 = 1