Python

Displaying Deck of Cards

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Join Date: Sep 2009

Posts: 6

Reputation: etypaldo is an unknown quantity at this point

Solved Threads: 0

etypaldo

Offline

Newbie Poster

Displaying Deck of Cards

Sep 20th, 2009

I am currently learning Python and how to work with start and stop indexing. I am doing a project from the book I am learning from and I'm stumped...I need to display a full deck of cards, with

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
numbers = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suits = ("c", "h", "s", "d")
numbers = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suits = ("c", "h", "s", "d")

so that it displays the entire deck, paired and ordered to look like:

Ac Ah As Ad
2c 2h 2s 2d
3c 3h 3s 3d
.
.
.
.
Qc Qh Qs Qd
Kc Kh Ks Kd

so far all I have are the numbers and suits set up but I keep trying to do things way too complicated with for loops, so i completely deleted my code and came here for fresh ideas.

Thanks

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Join Date: Aug 2008

Posts: 175

Reputation: snippsat is an unknown quantity at this point

Solved Threads: 51

snippsat

Online

Junior Poster

Re: Displaying Deck of Cards

Sep 20th, 2009

One way is like this
Take numbers and add like this "A" count as 1.

 Help with Code Tags 
 python Syntax (Toggle Plain Text) 
>>> numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] + 'Jack Queen King'.split()
>>> numbers
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 'Jack', 'Queen', 'King']
>>> 
>>> suits = ['diamonds', 'clubs', 'hearts', 'spades']
>>> suits
['diamonds', 'clubs', 'hearts', 'spades']
 
>>> deck = ['%s of %s' % (n, s) for n in numbers for s in suits]
>>> deck
# the hole deck
 
And we can make it look better.
>>> from pprint import pprint
>>> pprint(deck[:10])  #52 gives the hole deck
['1 of diamonds',
 '1 of clubs',
 '1 of hearts',
 '1 of spades',
 '2 of diamonds',
 '2 of clubs',
 '2 of hearts',
 '2 of spades',
 '3 of diamonds',
 '3 of clubs']
>>>
>>> numbers = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10] + 'Jack Queen King'.split()
>>> numbers
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 'Jack', 'Queen', 'King']
>>> 
>>> suits = ['diamonds', 'clubs', 'hearts', 'spades']
>>> suits
['diamonds', 'clubs', 'hearts', 'spades']

>>> deck = ['%s of %s' % (n, s) for n in numbers for s in suits]
>>> deck
# the hole deck

And we can make it look better.
>>> from pprint import pprint
>>> pprint(deck[:10])  #52 gives the hole deck
['1 of diamonds',
 '1 of clubs',
 '1 of hearts',
 '1 of spades',
 '2 of diamonds',
 '2 of clubs',
 '2 of hearts',
 '2 of spades',
 '3 of diamonds',
 '3 of clubs']
>>>

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Join Date: Oct 2004

Posts: 4,113

Reputation: vegaseat is just really nice

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vegaseat

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DaniWeb's Hypocrite

Re: Displaying Deck of Cards

Sep 20th, 2009

I am not sure which version of Python you are using, but if you explore this code ...

 Help with Code Tags 
 python Syntax (Toggle Plain Text) 
rank = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suit = ("c", "h", "s", "d")
 
deck = []
for r in rank:
    for s in suit:
        card = r + s
        deck.append(card)
 
print( deck )
rank = ("A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K")
suit = ("c", "h", "s", "d")

deck = []
for r in rank:
    for s in suit:
        card = r + s
        deck.append(card)

print( deck )

... you can see the the list called deck is almost ordered the way you want it. All you need to do now is to print four of the list's elements in a row and then slip in a newline character. Put your thinking hat on!

May 'the Google' be with you!

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Join Date: Aug 2008

Posts: 175

Reputation: snippsat is an unknown quantity at this point

Solved Threads: 51

snippsat

Online

Junior Poster

Re: Displaying Deck of Cards

Sep 21st, 2009

Just to explain one thing look at vegaseat code.
Does it look like this line?

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
deck = ['%s of %s' % (n, s) for n in numbers for s in suits]
deck = ['%s of %s' % (n, s) for n in numbers for s in suits]

This is called list List Comprehensions
I can wite it like this.

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
deck = []
for n in numbers:
    for s in suits:
        card = '%s of %s' % (s, n)
        deck.append(card)
deck = []
for n in numbers:
    for s in suits:
        card = '%s of %s' % (s, n)
        deck.append(card)

Then you see it not so differnt.