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numtolet

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Join Date: Sep 2009

Posts: 72

Reputation: Kruptein is an unknown quantity at this point

Solved Threads: 5

Kruptein

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Junior Poster in Training

numtolet

Oct 19th, 2009

okay I tried to make a reverse of finding the num value of a letter bu it returns in an error :f

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Traceback (most recent call last):
File "/home/darragh/Bureaublad/t.py", line 15, in <module>
numtolet('A')
File "/home/darragh/Bureaublad/t.py", line 6, in numtolet
letters['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
TypeError: list indices must be integers, not tuple

 Help with Code Tags 
 python Syntax (Toggle Plain Text) 
def numtolet(num):
	letters['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
	nummers = []
	for i in range(1,25):
		nummers.append(i)
	pos = nummers.find(num)
	poss = letters.find(pos - 1)
	return poss
def numtolet(num):
	letters['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
	nummers = []
	for i in range(1,25):
		nummers.append(i)
	pos = nummers.find(num)
	poss = letters.find(pos - 1)
	return poss

Last edited by Kruptein; Oct 19th, 2009 at 3:28 pm.

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Join Date: Sep 2009

Posts: 50

Reputation: lukerobi is an unknown quantity at this point

Solved Threads: 16

lukerobi

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Junior Poster in Training

Oct 19th, 2009

You mean something like this?

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
def numtolet(num):
    letters = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
    return letters[num]
def numtolet(num):
    letters = ['A','B','C','D','E','F','G','H','I','J','K','L','M','N','O','P','Q','R','S','T','U','V','W','X','Y','Z']
    return letters[num]

>>> numtolet(1)
'B'
>>> numtolet(14)
'O'

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Join Date: Jul 2008

Posts: 1,046

Reputation: jlm699 is a jewel in the rough

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jlm699

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Knows where his Towel is

Oct 19th, 2009

Or what about using chr() and then just adding 65?:

 Help with Code Tags 
 python Syntax (Toggle Plain Text) 
>>> def numtolet(num):
...     return chr(num + 65)
...     
>>> numtolet(1)
'B'
>>> numtolet(12)
'M'
>>> numtolet(14)
'O'
>>>
>>> def numtolet(num):
...     return chr(num + 65)
...     
>>> numtolet(1)
'B'
>>> numtolet(12)
'M'
>>> numtolet(14)
'O'
>>>

Or the reverse:

 Help with Code Tags 
 python Syntax (Toggle Plain Text) 
>>> def lettonum(let):
...     return ord(let) - 65
...     
>>> lettonum('O')
14
>>> lettonum('A')
0
>>> lettonum('N')
13
>>>
>>> def lettonum(let):
...     return ord(let) - 65
...     
>>> lettonum('O')
14
>>> lettonum('A')
0
>>> lettonum('N')
13
>>>

Last edited by jlm699; Oct 19th, 2009 at 4:31 pm.

1. Use Code Tags.
2. Homework? Show Effort.
3. Keep discussions on the forum: no PMs

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Join Date: Jul 2005

Posts: 1,221

Reputation: bumsfeld will become famous soon enough

Solved Threads: 137

bumsfeld

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Nearly a Posting Virtuoso

Oct 19th, 2009

This will also trap number exceeding the index:

 Help with Code Tags 
 python Syntax (Toggle Plain Text) 
import string
 
def numtolet(num):
    if num > 25: return
    return string.ascii_uppercase[num]
 
print( numtolet(0) )   # A
print( numtolet(5) )   # F
print( numtolet(25) )  # Z
print( numtolet(26) )  # None
import string

def numtolet(num):
    if num > 25: return
    return string.ascii_uppercase[num]

print( numtolet(0) )   # A
print( numtolet(5) )   # F
print( numtolet(25) )  # Z
print( numtolet(26) )  # None