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Count characters in a code

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Join Date: Oct 2009

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chengeto

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Count characters in a code

Oct 21st, 2009

I am trying to get this program to count the number of characters in a string. By number of characters l mean not punctuation or a space.What is wrong with my code because l don't understand why the program won't work?

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import javax.swing.*;
 
publiemc class ExamPractise
{
	public static void main (String [] geek)
 
	{
		String sentence = JOptionPane.showInputDialog("Enter a any sentence");
 
 
		int countCharacters=0;
 
 
 
       for (int i = 0; i < sentence.length(); i++)
       {
		   char c = sentence.charAt(i);		  
 
 
			    	if (c !=' '||c!='?'||c!='.'||c!=' ')
			    	{
						countCharacters++;
					}
	   }
 
 
		  System.out.println("There are" + " " + countCharacters + " " + "word");
 
 
	}
}
import javax.swing.*;

publiemc class ExamPractise
{
	public static void main (String [] geek)

	{
		String sentence = JOptionPane.showInputDialog("Enter a any sentence");

		
		int countCharacters=0;



       for (int i = 0; i < sentence.length(); i++)
       {
		   char c = sentence.charAt(i);		  
			
			    
			    	if (c !=' '||c!='?'||c!='.'||c!=' ')
			    	{
						countCharacters++;
					}
	   }


		  System.out.println("There are" + " " + countCharacters + " " + "word");


	}
}

Last edited by chengeto; Oct 21st, 2009 at 1:25 am. Reason: Typo

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Join Date: Feb 2009

Posts: 36

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.11

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Oct 21st, 2009

Help with Code Tags

(Toggle Plain Text)

publiemc class ExamPractise

Make it public

And:

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(Toggle Plain Text)

if (c !=' '||c!='?'||c!='.'||c!=')
{
       countCharacters++;
}

^What do you wanna c not to be there?

Should be find after that.
-----

And I checked out the program, it still counts for spaces and punctuation.

EDIT AGAIN

Since your counting the characters you should make you if statement to check the ASCII value for an example:

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if ((c >= 65 && c > 91))
{
	countCharacters++;
}
if ((c >= 65 && c > 91))
{
	countCharacters++;
}

That will check for uppercase letters only. Heres an ascii table.
http://web.cs.mun.ca/~michael/c/ascii-table.html

Just OR it with the other conditionals you make i.e.

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if ((c >= 65 && c > 91) || (lower case condition) || (numbers condition))
{
	countCharacters++;
}
if ((c >= 65 && c > 91) || (lower case condition) || (numbers condition))
{
	countCharacters++;
}

Last edited by .11; Oct 21st, 2009 at 1:45 am.

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Join Date: Oct 2009

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chengeto

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Oct 21st, 2009

•

Originally Posted by .11

Help with Code Tags

(Toggle Plain Text)
publiemc class ExamPractise
publiemc class ExamPractise
Make it public

And:
Help with Code Tags

(Toggle Plain Text)
if (c !=' '||c!='?'||c!='.'||c!=')
{
       countCharacters++;
}
if (c !=' '||c!='?'||c!='.'||c!=') { countCharacters++; }
^What do you wanna c not to be there?

Should be find after that.
-----

And I checked out the program, it still counts for spaces and punctuation.

Right now if l enter the word Obama Obama ? it counts the question mark and space between the two words as a character and l don't want it to do that.I don't know how do l get around that ?

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Join Date: Feb 2009

Posts: 36

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.11

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Oct 21st, 2009

•

Originally Posted by chengeto

Right now if l enter the word Obama Obama ? it counts the question mark and space between the two words as a character and l don't want it to do that.I don't know how do l get around that ?

Check out the ASCII table above I edit my post, the upper case condition is checked for, just check for the other two. And it will eliminate the characters that aren't a letter and number.

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nola_Coder nola_Coder is offline

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Oct 21st, 2009

try using this method to check each character:

if (Character.isLetter(c)) {
countCharacters++;
}

don't forget, you'll need to import java.lang.Character;

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~s.o.s~

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Failure as a human

Oct 21st, 2009

> By number of characters l mean not punctuation or a space

Look into the isLetter method of the Character class; modify your logic to increment the count only if the above method returns true .

Last edited by ~s.o.s~; Oct 21st, 2009 at 1:56 am.

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